/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q5.3-29E Question: A factorization \(A = ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Question: A factorization \(A = PD{P^{ - {\bf{1}}}}\) is not unique. Demonstrate this for the matrix A in Example 2. With \({D_{\bf{1}}} = \left[ {\begin{array}{*{20}{c}}{\bf{3}}&{\bf{0}}\\{\bf{0}}&{\bf{5}}\end{array}} \right]\), use the information in Example 2 to find the matrix \({P_{\bf{1}}}\) such that \(A = {P_{\bf{1}}}{D_{\bf{1}}}P_{\bf{1}}^{ - {\bf{1}}}\).

Short Answer

Expert verified

The matrix \({P_1}\) is \(\left[ {\begin{array}{*{20}{c}}1&1\\{ - 2}&{ - 1}\end{array}} \right]\).

Step by step solution

01

Write the information given

The matrices from example 2 are,

\[A = \left[ {\begin{array}{*{20}{c}}7&2\\{ - 4}&1\end{array}} \right], P = \left[ {\begin{array}{*{20}{c}}1&1\\{ - 1}&{ - 2}\end{array}} \right], D = \left[ {\begin{array}{*{20}{c}}5&0\\0&3\end{array}} \right]\]

02

Find the matrix \({P_{\bf{1}}}\)

For eigenvalue 5, the eigenvector is \(\left[ {\begin{array}{*{20}{c}}1\\{ - 1}\end{array}} \right]\) and for eigenvalue 3, the eigenvector is \(\left[ {\begin{array}{*{20}{c}}1\\{ - 2}\end{array}} \right]\).

The matrix \({P_1}\) is such that \(A = {P_1}{D_1}P_1^{ - 1}\), so the matrix \({D_1}\) is:

\[{D_1} = \left[ {\begin{array}{*{20}{c}}3&0\\0&5\end{array}} \right]\]

Interchange the columns of P to find the matrix \({P_1}\).

\[{P_1} = \left[ {\begin{array}{*{20}{c}}1&1\\{ - 2}&{ - 1}\end{array}} \right]\]

03

Find the product \({P_{\bf{1}}}{D_{\bf{1}}}P_{\bf{1}}^{ - {\bf{1}}}\)

The product \({P_1}{D_1}P_1^{ - 1}\) can be calculated as follows:

\[\begin{array}{c}{P_1}{D_1}P_1^{ - 1} = \left[ {\begin{array}{*{20}{c}}1&1\\{ - 2}&{ - 1}\end{array}} \right]\left[ {\begin{array}{*{20}{c}}3&0\\0&5\end{array}} \right]\left[ {\begin{array}{*{20}{c}}{ - 1}&{ - 1}\\2&1\end{array}} \right]\\ = \left[ {\begin{array}{*{20}{c}}7&2\\{ - 4}&1\end{array}} \right]\\ = A\end{array}\]

So, the matrix \({P_1}\) is \(\left[ {\begin{array}{*{20}{c}}1&1\\{ - 2}&{ - 1}\end{array}} \right]\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let\(\varepsilon = \left\{ {{{\bf{e}}_1},{{\bf{e}}_2},{{\bf{e}}_3}} \right\}\) be the standard basis for \({\mathbb{R}^3}\),\(B = \left\{ {{{\bf{b}}_1},{{\bf{b}}_2},{{\bf{b}}_3}} \right\}\) be a basis for a vector space \(V\) and\(T:{\mathbb{R}^3} \to V\) be a linear transformation with the property that

\(T\left( {{x_1},{x_2},{x_3}} \right) = \left( {{x_3} - {x_2}} \right){{\bf{b}}_1} - \left( {{x_1} - {x_3}} \right){{\bf{b}}_2} + \left( {{x_1} - {x_2}} \right){{\bf{b}}_3}\)

  1. Compute\(T\left( {{{\bf{e}}_1}} \right)\), \(T\left( {{{\bf{e}}_2}} \right)\) and \(T\left( {{{\bf{e}}_3}} \right)\).
  2. Compute \({\left( {T\left( {{{\bf{e}}_1}} \right)} \right)_B}\), \({\left( {T\left( {{{\bf{e}}_2}} \right)} \right)_B}\) and \({\left( {T\left( {{{\bf{e}}_3}} \right)} \right)_B}\).
  3. Find the matrix for \(T\) relative to \(\varepsilon \), and\(B\).

Let\(D = \left\{ {{{\bf{d}}_1},{{\bf{d}}_2}} \right\}\) and \(B = \left\{ {{{\bf{b}}_1},{{\bf{b}}_2}} \right\}\) be bases for vector space \(V\) and \(W\), respectively. Let \(T:V \to W\) be a linear transformation with the property that

\(T\left( {{{\bf{d}}_1}} \right) = 2{{\bf{b}}_1} - 3{{\bf{b}}_2}\), \(T\left( {{{\bf{d}}_2}} \right) = - 4{{\bf{b}}_1} + 5{{\bf{b}}_2}\)

Find the matrix for \(T\) relative to \(D\), and\(B\).

[M] In Exercises 19 and 20, find (a) the largest eigenvalue and (b) the eigenvalue closest to zero. In each case, set \[{{\bf{x}}_{\bf{0}}}{\bf{ = }}\left( {{\bf{1,0,0,0}}} \right)\] and carry out approximations until the approximating sequence seems accurate to four decimal places. Include the approximate eigenvector.

20. \[A{\bf{ = }}\left[ {\begin{array}{*{20}{c}}{\bf{1}}&{\bf{2}}&{\bf{3}}&{\bf{2}}\\{\bf{2}}&{{\bf{12}}}&{{\bf{13}}}&{{\bf{11}}}\\{{\bf{ - 2}}}&{\bf{3}}&{\bf{0}}&{\bf{2}}\\{\bf{4}}&{\bf{5}}&{\bf{7}}&{\bf{2}}\end{array}} \right]\]

Apply the results of Exercise \({\bf{15}}\) to find the eigenvalues of the matrices \(\left( {\begin{aligned}{*{20}{c}}{\bf{1}}&{\bf{2}}&{\bf{2}}\\{\bf{2}}&{\bf{1}}&{\bf{2}}\\{\bf{2}}&{\bf{2}}&{\bf{1}}\end{aligned}} \right)\) and \(\left( {\begin{aligned}{*{20}{c}}{\bf{7}}&{\bf{3}}&{\bf{3}}&{\bf{3}}&{\bf{3}}\\{\bf{3}}&{\bf{7}}&{\bf{3}}&{\bf{3}}&{\bf{3}}\\{\bf{3}}&{\bf{3}}&{\bf{7}}&{\bf{3}}&{\bf{3}}\\{\bf{3}}&{\bf{3}}&{\bf{3}}&{\bf{7}}&{\bf{3}}\\{\bf{3}}&{\bf{3}}&{\bf{3}}&{\bf{3}}&{\bf{7}}\end{aligned}} \right)\).

Show that if \(A\) is diagonalizable, with all eigenvalues less than 1 in magnitude, then \({A^k}\) tends to the zero matrix as \(k \to \infty \). (Hint: Consider \({A^k}x\) where \(x\) represents any one of the columns of \(I\).)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.