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In Exercise 33-36, verify that \(\det EA = \left( {\det E} \right)\left( {\det A} \right)\)where E is the elementary matrix shown and \(A = \left[ {\begin{array}{*{20}{c}}a&b\\c&d\end{array}} \right]\).

34. \(\left[ {\begin{array}{*{20}{c}}1&0\\k&1\end{array}} \right]\)

Short Answer

Expert verified

It is verified that \(\det EA = \left( {\det E} \right)\left( {\det A} \right)\).

Step by step solution

01

Determine matrix \(EA\)

It is given that \(A = \left[ {\begin{array}{*{20}{c}}a&b\\c&d\end{array}} \right],{\rm{ }}E = \left[ {\begin{array}{*{20}{c}}1&0\\k&1\end{array}} \right]\).

Compute matrix \(EA\) as shown below:

\(\begin{array}{c}EA = \left[ {\begin{array}{*{20}{c}}1&0\\k&1\end{array}} \right]\left[ {\begin{array}{*{20}{c}}a&b\\c&d\end{array}} \right]\\ = \left[ {\begin{array}{*{20}{c}}{a + 0}&{b + 0}\\{ka + c}&{kb + d}\end{array}} \right]\\ = \left[ {\begin{array}{*{20}{c}}a&b\\{ka + c}&{kb + d}\end{array}} \right]\end{array}\)

02

Verify that \(\det EA = \left( {\det E} \right)\left( {\det A} \right)\)

The determinants of matrices Eand A are shown below:

\[\begin{array}{c}\det E = \left| {\begin{array}{*{20}{c}}1&0\\k&1\end{array}} \right|\\ = 1\\\det A = \left| {\begin{array}{*{20}{c}}a&b\\c&d\end{array}} \right|\\ = ad - bc\end{array}\]

The determinant of matrix \(EA\) is shown below:

\(\begin{array}{c}\det EA = \left| {\begin{array}{*{20}{c}}a&b\\{ka + c}&{kb + d}\end{array}} \right|\\ = a\left( {kb + d} \right) - \left( {ka + c} \right)b\\ = kab + ad - kab - bc\\ = 1\left( {ad - bc} \right)\\ = \left( {\det E} \right)\left( {\det A} \right)\end{array}\)

Thus, it is verified that \(\det EA = \left( {\det E} \right)\left( {\det A} \right)\).

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Most popular questions from this chapter

In Exercises 21–23, use determinants to find out if the matrix is invertible.

22. \(\left( {\begin{aligned}{*{20}{c}}5&1&{ - 1}\\1&{ - 3}&{ - 2}\\0&5&3\end{aligned}} \right)\)

Find the determinant in Exercise 19, where \[\left| {\begin{aligned}{*{20}{c}}{\bf{a}}&{\bf{b}}&{\bf{c}}\\{\bf{d}}&{\bf{e}}&{\bf{f}}\\{\bf{g}}&{\bf{h}}&{\bf{i}}\end{aligned}} \right| = {\bf{7}}\].

19. \[\left| {\begin{aligned}{*{20}{c}}{\bf{a}}&{\bf{b}}&{\bf{c}}\\{{\bf{2d}} + {\bf{a}}}&{{\bf{2e}} + {\bf{b}}}&{{\bf{2f}} + {\bf{c}}}\\{\bf{g}}&{\bf{h}}&{\bf{i}}\end{aligned}} \right|\]

The expansion of a \({\bf{3}} \times {\bf{3}}\) determinant can be remembered by the following device. Write a second type of the first two columns to the right of the matrix, and compute the determinant by multiplying entries on six diagonals.

Add the downward diagonal products and subtract the upward products. Use this method to compute the determinants in Exercises 15-18. Warning: This trick does not generalize in any reasonable way to \({\bf{4}} \times {\bf{4}}\) or larger matrices.

\(\left| {\begin{aligned}{*{20}{c}}{\bf{2}}&{ - {\bf{3}}}&{\bf{3}}\\{\bf{3}}&{\bf{2}}&{\bf{2}}\\{\bf{1}}&{\bf{3}}&{ - {\bf{1}}}\end{aligned}} \right|\)

In Exercises 39 and 40, \(A\) is an \(n \times n\) matrix. Mark each statement True or False. Justify each answer.

39.

a. An \(n \times n\) determinant is defined by determinants of \(\left( {n - 1} \right) \times \left( {n - 1} \right)\) submatrices.

b. The \(\left( {i,j} \right)\)-cofactor of a matrix \(A\) is the matrix \({A_{ij}}\) obtained by deleting from A its \(i{\mathop{\rm th}\nolimits} \) row and \[j{\mathop{\rm th}\nolimits} \]column.

Question: In Exercise 9, determine the values of the parameter s for which the system has a unique solution, and describe the solution.

9.

\(\begin{array}{c}s{x_{\bf{1}}} + {\bf{2}}s{x_{\bf{2}}} = - {\bf{1}}\\{\bf{3}}{x_{\bf{1}}} + {\bf{6}}s{x_{\bf{2}}} = {\bf{4}}\end{array}\)

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