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In Exercises 7 and \(8,\) find the barycentric coordinates of \(\mathbf{p}\) with respect to the affinely independent set of points that precedes it. $$ \left[\begin{array}{r}{0} \\ {1} \\ {-2} \\\ {1}\end{array}\right],\left[\begin{array}{l}{1} \\ {1} \\ {0} \\\ {2}\end{array}\right],\left[\begin{array}{r}{1} \\ {4} \\ {-6} \\\ {5}\end{array}\right], \mathbf{p}=\left[\begin{array}{r}{-1} \\ {1} \\ {-4} \\\ {0}\end{array}\right] $$

Short Answer

Expert verified
Barycentric coordinates of \(\mathbf{p}\) are \((2, -1, 0)\).

Step by step solution

01

Write the points

The given points are \( \mathbf{a} = \begin{bmatrix} 0 \ 1 \ -2 \ 1 \end{bmatrix}, \mathbf{b} = \begin{bmatrix} 1 \ 1 \ 0 \ 2 \end{bmatrix}, \mathbf{c} = \begin{bmatrix} 1 \ 4 \ -6 \ 5 \end{bmatrix} \) and point \( \mathbf{p} = \begin{bmatrix} -1 \ 1 \ -4 \ 0 \end{bmatrix} \) for which we need to find the barycentric coordinates.
02

Set up the barycentric coordinate equation

Barycentric coordinates \((\lambda_1, \lambda_2, \lambda_3)\) for point \(\mathbf{p}\) can be solved with the equation \( \lambda_1 \mathbf{a} + \lambda_2 \mathbf{b} + \lambda_3 \mathbf{c} = \mathbf{p} \), with the condition \( \lambda_1 + \lambda_2 + \lambda_3 = 1 \).
03

Translate to matrix form

This forms a system of linear equations:\[\begin{align*}0\lambda_1 + 1\lambda_2 + 1\lambda_3 &= -1 \1\lambda_1 + 1\lambda_2 + 4\lambda_3 &= 1 \-2\lambda_1 + 0\lambda_2 - 6\lambda_3 &= -4 \1\lambda_1 + 2\lambda_2 + 5\lambda_3 &= 0 \\lambda_1 + \lambda_2 + \lambda_3 &= 1\end{align*}\]
04

Perform row reduction

Solve the linear system using row reduction or matrices to find the values of \(\lambda_1\), \(\lambda_2\), \(\lambda_3\). The augmented matrix is:\[\begin{bmatrix}0 & 1 & 1 & | & -1 \1 & 1 & 4 & | & 1 \-2 & 0 & -6 & | & -4 \1 & 2 & 5 & | & 0 \1 & 1 & 1 & | & 1\end{bmatrix}\]
05

Solve the linear system

Through matrix row operations or substitution methods, solve for \(\lambda_1, \lambda_2, \lambda_3\). You'll find that:\[\lambda_1 = 2, \quad \lambda_2 = -1, \quad \lambda_3 = 0\]These are the barycentric coordinates of \(\mathbf{p}\).
06

Verify the sum of coordinates

Verify that \( \lambda_1 + \lambda_2 + \lambda_3 = 2 - 1 + 0 = 1 \) satisfies the condition for barycentric coordinates.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Affinely Independent Set
An affinely independent set refers to a collection of points in a vector space where no single point can be expressed as an affine combination of the others. This concept ensures that these points define the simplest form of a geometric figure, such as lines, planes, and higher-dimensional analogs.

Consider the points in question:
  • \(\mathbf{a} = \begin{bmatrix} 0 \ 1 \ -2 \ 1 \end{bmatrix}\)
  • \(\mathbf{b} = \begin{bmatrix} 1 \ 1 \ 0 \ 2 \end{bmatrix}\)
  • \(\mathbf{c} = \begin{bmatrix} 1 \ 4 \ -6 \ 5 \end{bmatrix}\)
These points are affinely independent if there are no non-trivial solutions to the equation:\[ \lambda_1 \mathbf{a} + \lambda_2 \mathbf{b} + \lambda_3 \mathbf{c} = \mathbf{0} \]Where \(\lambda_1 + \lambda_2 + \lambda_3 = 0\) and not all \(\lambda_i\) are zero. This property is crucial for calculating barycentric coordinates since it ensures that the coordinates have a unique solution.
Linear Systems
A linear system comprises multiple linear equations that simultaneously relate several variables. In this exercise, the system represented by our barycentric coordinate equation is crucial for defining the location of point \(\mathbf{p}\) based on points \(\mathbf{a}, \mathbf{b},\) and \(\mathbf{c}\).

Here is the system of equations used:
  • \(0\lambda_1 + 1\lambda_2 + 1\lambda_3 = -1\)
  • \(1\lambda_1 + 1\lambda_2 + 4\lambda_3 = 1\)
  • \(-2\lambda_1 + 0\lambda_2 - 6\lambda_3 = -4\)
  • \(1\lambda_1 + 2\lambda_2 + 5\lambda_3 = 0\)
  • \(\lambda_1 + \lambda_2 + \lambda_3 = 1\)
This set of equations ensures that the proportions of the points in the system add up correctly to form point \(\mathbf{p}\). Solving these equations simultaneously is an essential process to find the values of the barycentric coordinates.
Matrix Row Operations
Matrix row operations are transformations used to simplify matrix equations and solve systems of linear equations. They include row swapping, scaling rows, and adding or subtracting the rows from each other.

Consider the augmented matrix that reflects our system of linear equations:\[\begin{bmatrix}0 & 1 & 1 & | & -1 \1 & 1 & 4 & | & 1 \-2 & 0 & -6 & | & -4 \1 & 2 & 5 & | & 0 \1 & 1 & 1 & | & 1\end{bmatrix}\]Through row operations, we can transform this matrix into a simpler form to find the values of \(\lambda_1\), \(\lambda_2\), and \(\lambda_3\).

  • Row Swapping: Changing the positions of two rows.
  • Row Multiplication: Multiplying a row by a non-zero scalar.
  • Row Addition: Adding or subtracting the multiple of one row from another.
The aim is to reach a form where the solution is clearly seen, often using a method known as Gaussian or Gauss-Jordan elimination.
Coordinate Geometry
Coordinate geometry, or analytic geometry, is the study of geometric figures through a coordinate system. This allows for the application of algebraic techniques to solve geometric problems.

Barycentric coordinates fall into this category, providing a means to express a point's position with respect to a given triangle or set of points. This is very much in line with coordinate geometry as it uses coordinate-based methods to determine spatial relationships.

With our points \(\mathbf{a}\), \(\mathbf{b}\), \(\mathbf{c}\), and point \(\mathbf{p}\), barycentric coordinates allow us to find weights or coefficients \(\lambda_1, \lambda_2\), and \(\lambda_3\) such that their linear combination equals point \(\mathbf{p}\). This connection reveals the significance of coordinate geometry as it translates visual geometric properties into solvable algebraic equations, thus bridging the gap between geometry and algebra.

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Most popular questions from this chapter

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