/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 If \(A\) and \(B\) are convex se... [FREE SOLUTION] | 91Ó°ÊÓ

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If \(A\) and \(B\) are convex sets, prove that \(A+B\) is convex.

Short Answer

Expert verified
The set \(A+B\) is convex because a convex combination of sums from \(A\) and \(B\) results in an element of \(A+B\).

Step by step solution

01

Understanding Convex Sets

A set is convex if for every pair of points within the set, the line segment joining them lies entirely within the set. Mathematically, a set \( S \) is convex if for any two points \( x, y \in S \), and for every \( \lambda \in [0, 1] \), it holds that \( \lambda x + (1-\lambda) y \in S \).
02

Defining the Sum of Sets

The sum of two sets \( A \) and \( B \), denoted as \( A + B \), is defined as \( \{ a + b : a \in A, b \in B \} \). This is the set of all points obtained by adding each element of \( A \) to each element of \( B \).
03

Prove Convexity of \( A + B \)

To prove that \( A + B \) is convex, consider any two points \( p_1, p_2 \in A + B \). By definition, we have \( p_1 = a_1 + b_1 \) and \( p_2 = a_2 + b_2 \) where \( a_1, a_2 \in A \) and \( b_1, b_2 \in B \).
04

Use Convex Property on Elements

Since \( A \) and \( B \) are convex, for any \( \lambda \in [0, 1] \), the points \( \lambda a_1 + (1-\lambda) a_2 \in A \) and \( \lambda b_1 + (1-\lambda) b_2 \in B \).
05

Combine Elements to Show Convexity

Now consider the combination \( \lambda p_1 + (1-\lambda) p_2 = \lambda (a_1 + b_1) + (1-\lambda) (a_2 + b_2) = (\lambda a_1 + (1-\lambda) a_2) + (\lambda b_1 + (1-\lambda) b_2) \). Since \( \lambda a_1 + (1-\lambda) a_2 \in A \) and \( \lambda b_1 + (1-\lambda) b_2 \in B \), it follows that \( \lambda p_1 + (1-\lambda) p_2 \in A + B \). Therefore, \( A + B \) is convex.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Set Addition
Set addition, also known as the Minkowski sum, is a fundamental operation in mathematics when dealing with sets. It involves creating a new set from two original sets by adding each element of the first set to each element of the second set. If you have two sets, say set \( A \) and set \( B \), the set addition, denoted as \( A + B \), is defined as all possible sums of elements from these sets. This results in the set \( \{ a + b : a \in A, b \in B \} \).
This concept is essential in various fields like geometry, optimization, and economics, where combining sets in such a manner is used to explore new areas or solutions. It is especially interesting because set addition retains certain properties of the original sets, such as convexity, which is a crucial aspect when proving that certain structures like \( A+B \) will also be convex. By understanding how we combine points from each set, we can visualize and reason about how their resulting Minkowski sum behaves and retains characteristics from the original sets.
Proving Convexity of Set Additions
To prove that the Minkowski sum of two convex sets remains convex, we start by understanding what convexity means. A set is convex if, for any two points in that set, the whole line segment between these points also lies within the set. This is mathematically expressed as: for any points \( x, y \) in the set and any \( \lambda \) in the range \( [0, 1] \), the point \( \lambda x + (1-\lambda) y \) is also in the set. This idea shows how the set doesn’t "break," as all portions of the line segment remain inside the set.
Convexity in set addition can be proved by leveraging the convexity property of each original set. When proving that the set \( A + B \) is convex, we begin by taking any two points \( p_1, p_2 \in A + B \). By definition, these points can be represented as \( p_1 = a_1 + b_1 \) and \( p_2 = a_2 + b_2 \), where \( a_1, a_2 \in A \) and \( b_1, b_2 \in B \). We apply the convexity condition on these components, creating the expression \( \lambda a_1 + (1-\lambda)a_2 \in A \) and \( \lambda b_1 + (1-\lambda)b_2 \in B \).
Now, by forming \( \lambda p_1 + (1-\lambda)p_2 \) using these expressions, it remains within \( A + B \), fulfilling the condition for convexity. Thus, we understand that the operation of set addition preserves the integral property of convexity.
Properties of Line Segments within Convex Sets
The concept of convexity in sets is closely tied to the behavior of line segments. A line segment, simply put, is the straight path connecting two points. In a convex set, drawing a line between any two points results in a segment that lies entirely within the set. This characteristic is what defines a shape or space as convex, dictating that you can "connect the dots" and always remain within the boundaries of the shape.
Line segments play a crucial role in performing logical proofs related to convexity. For instance, when analyzing or establishing the convexity of set additions, the ability to show that every point on a line segment remains inside the resulting set \( A + B \) is pivotal. It reassures us that, regardless of where you pick your starting and ending points within \( A \) and \( B \), the connecting line falls within \( A + B \), confirming its convex structure.
To understand this better, imagine stretching a rubber band around points from the set. If the band doesn’t leave the set's boundary at any point along its stretch, then the set is convex. Thus, properties of line segments are fundamental in explaining and proving the concept of convexity for both basic sets and for combinations like set addition.

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Most popular questions from this chapter

In Exercises 16 and \(17,\) mark each statement True or False. Justify each answer. a. A cube in \(\mathbb{R}^{3}\) has exactly five facets. b. A point \(\mathbf{p}\) is an extreme point of a polytope \(P\) if and only if \(\mathbf{p}\) is a vertex of \(P .\) c. If \(S\) is a nonempty compact convex set and a linear functional attains its maximum at a point \(\mathbf{p}\) , then \(\mathbf{p}\) is an extreme point of \(S\) . d. \(\mathrm{A} 2\) -dimensional polytope always has the same number of vertices and edges.

In Exercises 11 and \(12,\) mark each statement True or False. Justify each answer. a. The cubic Bézier curve is based on four control points. b. Given a quadratic Bézier curve \(\mathbf{x}(t)\) with control points \(\mathbf{p}_{0}, \mathbf{p}_{1},\) and \(\mathbf{p}_{2},\) the directed line segment \(\mathbf{p}_{1}-\mathbf{p}_{0}\) (from \(\mathbf{p}_{0}\) to \(\mathbf{p}_{1} )\) is the tangent vector to the curve at \(\mathbf{p}_{0}\) . c. When two quadratic Bézier curves with control points \(\left\\{\mathbf{p}_{0}, \mathbf{p}_{1}, \mathbf{p}_{2}\right\\}\) and \(\left\\{\mathbf{p}_{2}, \mathbf{p}_{3}, \mathbf{p}_{4}\right\\}\) are joined at \(\mathbf{p}_{2},\) the combined Bézier curve will have \(C^{1}\) continuity at \(\mathbf{p}_{2}\) if \(\mathbf{p}_{2}\) is the midpoint of the line segment between \(\mathbf{p}_{1}\) and \(\mathbf{p}_{3} .\)

Prove that the convex hull of a bounded set is bounded.

The conditions for affine dependence are stronger than those for linear dependence, so an affinely dependent set is automatically linearly dependent. Also, a linearly independent set cannot be affinely dependent and therefore must be affinely independent. Construct two linearly dependent indexed sets \(S_{1}\) and \(S_{2}\) in \(\mathbb{R}^{2}\) such that \(S_{1}\) is affinely dependent and \(S_{2}\) is affinely independent. In each case, the set should contain either one, two, or three nonzero points.

Take \(\mathbf{q}\) on the line segment from \(\mathbf{b}\) to \(\mathbf{c}\) and consider the line through \(\mathbf{q}\) and \(\mathbf{a},\) which may be written as \(\mathbf{p}=(1-x) \mathbf{q}+x \mathbf{a}\) \(x \cdot \operatorname{det}[\tilde{\mathbf{a}} \quad \tilde{\mathbf{b}} \quad \tilde{\mathbf{c}}] .\) From this and earlier work, conclude that the parameter \(x\) is the first barycentric coordinate of \(\mathbf{p} .\) However, by construction, the parameter \(x\) also determines the relative distance between \(\mathbf{p}\) and \(\mathbf{q}\) along the segment from q to a. (When \(x=1, \mathbf{p}=\mathbf{a} . )\) When this fact is applied to Example \(5,\) it shows that the colors at vertex \(\mathbf{a}\) and the point \(\mathbf{q}\) are smoothly interpolated as \(\mathbf{p}\) moves along the line between \(\mathbf{a}\) and \(\mathbf{q}\)

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