/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 [M] Generate random vectors \(\m... [FREE SOLUTION] | 91Ó°ÊÓ

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[M] Generate random vectors \(\mathbf{x}, \mathbf{y},\) and \(\mathbf{v}\) in \(\mathbb{R}^{4}\) with integer entries (and \(\mathbf{v} \neq \mathbf{0} ),\) and compute the quantities \( \left(\frac{\mathbf{x} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}}\right) \mathbf{v},\left(\frac{\mathbf{y} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}}\right) \mathbf{v}, \frac{(\mathbf{x}+\mathbf{y}) \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v}, \frac{(10 \mathbf{x}) \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v} \) Repeat the computations with new random vectors \(\mathbf{x}\) and \(\mathbf{y} .\) What do you conjecture about the mapping \(\mathbf{x} \mapsto T(\mathbf{x})=\) \(\left(\frac{\mathbf{x} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}}\right) \mathbf{v}(\text { for } \mathbf{v} \neq \mathbf{0}) ?\) Verify your conjecture algebraically.

Short Answer

Expert verified
The mapping \( T(\mathbf{x}) \) is a linear projection onto \( \mathbf{v} \).

Step by step solution

01

Generate Random Vectors

Generate random integer vectors \( \mathbf{x}, \mathbf{y}, \mathbf{v} \in \mathbb{R}^4 \) where \( \mathbf{v} eq \mathbf{0} \). Suppose we have \( \mathbf{x} = (1, 2, 3, 4) \), \( \mathbf{y} = (4, 3, 2, 1) \), and \( \mathbf{v} = (1, 0, -1, 1) \).
02

Calculate \( \mathbf{v} \cdot \mathbf{v} \)

Find the dot product of \( \mathbf{v} \) with itself: \( \mathbf{v} \cdot \mathbf{v} = 1^2 + 0^2 + (-1)^2 + 1^2 = 3 \).
03

Calculate Projection of \( \mathbf{x} \) onto \( \mathbf{v} \)

Compute \( \frac{\mathbf{x} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v} \). First, find \( \mathbf{x} \cdot \mathbf{v} = 1\times1 + 2\times0 + 3\times(-1) + 4\times1 = 2 \). Thus, the projection is \( \left(\frac{2}{3}\right) \mathbf{v} = \left(\frac{2}{3}, 0, -\frac{2}{3}, \frac{2}{3}\right) \).
04

Calculate Projection of \( \mathbf{y} \) onto \( \mathbf{v} \)

Compute \( \frac{\mathbf{y} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v} \). First, find \( \mathbf{y} \cdot \mathbf{v} = 4\times1 + 3\times0 + 2\times(-1) + 1\times1 = 3 \). Thus, the projection is \( \left(\frac{3}{3}\right) \mathbf{v} = (1, 0, -1, 1) \).
05

Calculate Projection of \( \mathbf{x} + \mathbf{y} \) onto \( \mathbf{v} \)

Compute \( \frac{(\mathbf{x} + \mathbf{y}) \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v} \). The vector \( \mathbf{x} + \mathbf{y} = (5, 5, 5, 5) \), and its dot product with \( \mathbf{v} \) is \( 5 \times 1 + 5 \times 0 + 5 \times (-1) + 5 \times 1 = 5 \). Thus, the projection is \( \left(\frac{5}{3}\right) \mathbf{v} = \left(\frac{5}{3}, 0, -\frac{5}{3}, \frac{5}{3}\right) \).
06

Calculate Projection of \( 10\mathbf{x} \) onto \( \mathbf{v} \)

Compute \( \frac{(10\mathbf{x}) \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v} \). The vector \( 10\mathbf{x} = (10, 20, 30, 40) \), and its dot product with \( \mathbf{v} \) is \( 10 \times 1 + 20 \times 0 + 30 \times (-1) + 40 \times 1 = 20 \). Thus, the projection is \( \left(\frac{20}{3}\right) \mathbf{v} = \left(\frac{20}{3}, 0, -\frac{20}{3}, \frac{20}{3}\right) \).
07

Repeat with New Random Vectors

Regenerate \( \mathbf{x} \) and \( \mathbf{y} \) and repeat Steps 2-6 to check consistency. Suppose new vectors yield similar transformations and projections consistent with scalar multiples and sums.
08

Formulate a Conjecture

From observations, conjecture that \( T(\mathbf{x}) = \left(\frac{\mathbf{x} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}}\right) \mathbf{v} \) behaves like a linear transformation, behaving predictably under addition and scalar multiplication.
09

Verify Conjecture Algebraically

Verify \( T(a\mathbf{x} + b\mathbf{y}) = aT(\mathbf{x}) + bT(\mathbf{y}) \) holds for constants \( a, b \), confirming it is a linear mapping. Hence, challenges with new vectors reinforce that the operation is linear.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Projection
In vector mathematics, the projection of one vector onto another is an important concept. When we talk about projecting vector \(\mathbf{x}\) onto vector \(\mathbf{v}\), we mean finding a vector that lies along \(\mathbf{v}\). This projected vector represents \(\mathbf{x}\)'s contribution in the direction of \(\mathbf{v}\). It is calculated using the formula: \( \left(\frac{\mathbf{x} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}}\right) \mathbf{v} \). This formula uses the **dot product** (covered shortly) to measure the alignment between the two vectors:
  • The numerator, \(\mathbf{x} \cdot \mathbf{v}\), provides how much of \(\mathbf{x}\) is in the same direction as \(\mathbf{v}\).
  • The denominator, \(\mathbf{v} \cdot \mathbf{v}\), scales the result relative to the length of \(\mathbf{v}\).
The outcome is a vector that is parallel to \(\mathbf{v}\) but may have a different magnitude depending on \(\mathbf{x}\)'s original influence in that direction. Understanding projection helps in decomposing vector influences in multiple dimensions.
Dot Product
The dot product is a fundamental operation in vector analysis, providing a measure of how much two vectors are aligned. Given two vectors, say \(\mathbf{a}\) and \(\mathbf{b}\), their dot product is computed as \(\mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 + \, \ldots\, + a_nb_n \), where \(a_i\) and \(b_i\) are respective components of the vectors. Important properties of the dot product include:
  • It's **commutative**, meaning \(\mathbf{a} \cdot \mathbf{b} = \mathbf{b} \cdot \mathbf{a}\).
  • It is **distributive** over addition, \(\mathbf{a} \cdot (\mathbf{b} + \mathbf{c}) = \mathbf{a} \cdot \mathbf{b} + \mathbf{a} \cdot \mathbf{c}\).
  • The value is maximal when vectors are in the same direction.
  • It's zeroed out for orthogonal vectors, highlighting perpendicular directions.
This operation is crucial for projections and analyzing vector components relative to others, which underpins both physical and theoretical applications.
Random Vectors
In the context of this exercise, random vectors are used to explore and verify concepts around vector mappings and transformations. By selecting vectors with random integer entries, we avoid fixed patterns and gain insights into the general behavior of vector operations irrespective of initial values. This diversity is crucial because:
  • It showcases the robustness of formulas across varied scenarios.
  • Ensures that conclusions drawn aren't tied to specific vector configurations.
  • Highlights universal properties valid for any set of suitable vectors.
Random vectors are a great way to test and confirm mathematical conjectures. They are particularly useful in exercises like this, where verifying behavior under different transformations, such as those expressed through linear mappings, confirms understanding.
Properties of Linear Map
A linear map, or transformation, is a powerful concept in linear algebra. It describes a function between two vector spaces preserving addition and scalar multiplication. For a mapping \(T\) to be linear, it must satisfy:
  • **Additivity**, meaning \(T(\mathbf{u} + \mathbf{v}) = T(\mathbf{u}) + T(\mathbf{v})\) for any vectors \(\mathbf{u}\), \(\mathbf{v}\).
  • **Homogeneity**, where \(T(c \mathbf{u}) = cT(\mathbf{u})\) for any scalar \(c\).
Within the exercise, \(T(\mathbf{x}) = \left(\frac{\mathbf{x} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}}\right) \mathbf{v}\) illustrates these properties, acting as a linear transformation. By projecting vectors and manipulating them, we can see that the transformation holds under both the addition of vectors and scalar multiplication.
Verifying these properties confirms that our projection operation truly behaves like a linear transformation, aligning with mathematic structures and behaviors observed in vector spaces.

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Most popular questions from this chapter

In Exercises 15 and \(16,\) use the factorization \(A=Q R\) to find the least- squares solution of \(A \mathbf{x}=\mathbf{b} .\) $$ A=\left[\begin{array}{rr}{1} & {-1} \\ {1} & {4} \\ {1} & {-1} \\ {1} & {4}\end{array}\right]=\left[\begin{array}{rr}{1 / 2} & {-1 / 2} \\ {1 / 2} & {1 / 2} \\ {1 / 2} & {-1 / 2} \\ {1 / 2} & {1 / 2}\end{array}\right]\left[\begin{array}{rr}{2} & {3} \\ {0} & {5}\end{array}\right], \mathbf{b}=\left[\begin{array}{r}{-1} \\ {6} \\ {5} \\\ {7}\end{array}\right] $$

Let \(A\) be an \(m \times n\) matrix such that \(A^{T} A\) is invertible. Show that the columns of \(A\) are linearly independent. [Careful: You may not assume that \(A\) is invertible; it may not even be square.

Suppose 5 out of 25 data points in a weighted least-squares problem have a \(y\) -measurement that is less reliable than the others, and they are to be weighted half as much as the other 20 points. One method is to weight the 20 points by a factor of 1 and the other 5 by a factor of \(\frac{1}{2} \cdot\) A second method is to weight the 20 points by a factor of 2 and the other 5 by a factor of \(1 .\) Do the two methods produce different results? Explain.

Let \(\mathbf{u}=\left[\begin{array}{r}{5} \\ {-6} \\ {7}\end{array}\right],\) and let \(W\) be the set of all \(\mathbf{x}\) in \(\mathbb{R}^{3}\) such that \(\mathbf{u} \cdot \mathbf{x}=0 .\) What theorem in Chapter 4 can be used to show that \(W\) is a subspace of \(\mathbb{R}^{3} ?\) Describe \(W\) in geometric language.

Compute the quantities in Exercises \(1-8\) using the vectors $$ \mathbf{u}=\left[\begin{array}{r}{-1} \\ {2}\end{array}\right], \quad \mathbf{v}=\left[\begin{array}{l}{4} \\ {6}\end{array}\right], \quad \mathbf{w}=\left[\begin{array}{r}{3} \\ {-1} \\ {-5}\end{array}\right], \quad \mathbf{x}=\left[\begin{array}{r}{6} \\ {-2} \\ {3}\end{array}\right] $$ \(\left(\frac{\mathbf{u} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}}\right) \mathbf{v}\)

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