Chapter 6: Problem 28
Let \(U\) be an \(n \times n\) orthogonal matrix. Show that the rows of \(U\) form an orthonormal basis of \(\mathbb{R}^{n}\) .
Short Answer
Expert verified
The rows of an orthogonal matrix form an orthonormal basis for \( \mathbb{R}^n \).
Step by step solution
01
Understanding Orthogonal Matrices
An orthogonal matrix, by definition, is a square matrix whose columns (and rows) are orthonormal vectors. If \( U \) is an \( n \times n \) orthogonal matrix, then it satisfies \( U^T U = I \), where \( I \) is the identity matrix. This means the columns of \( U \) are orthonormal, implying each column vector of \( U \) has unit length and is mutually perpendicular to each other.
02
Properties of Transpose of Orthogonal Matrices
Since \( U \) is an orthogonal matrix, \( U^T \) is also orthogonal. The operation \( U^T U = I \) implies that the rows of \( U \), which are the columns of \( U^T \), are orthonormal. An orthonormal set is simply orthogonal vectors that also have a magnitude of 1.
03
Checking Orthonormality of Rows
Each row in an orthogonal matrix can be seen as a column when considering \( U^T \). Thus, if the rows of \( U \) are orthonormal, then they must satisfy two conditions: (1) each row vector must have a length of 1, and (2) any two distinct rows are orthogonal (dot product is zero). From \( U^T U = I \), it is clear these conditions are satisfied.
04
Verification of Orthonormal Basis
Given the rows of \( U \) satisfy the orthonormal conditions mentioned, they form an orthonormal basis for \( \mathbb{R}^n \). Orthonormal bases have vectors that span the entire space and are mutually orthogonal, fulfilling the criteria for them being a basis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Orthonormal Basis
An orthonormal basis is a special kind of basis in a vector space where all basis vectors are orthogonal and each vector has unit length. But what does this really mean? Cozily imagine a set of vectors spread out in such a way that each one meets another at a right angle, just like the axes in a 2D graph.
This ensures that they don't lean towards each other in any direction. Additionally, every vector has a length, or a 'magnitude', of one to simplify calculations.
In mathematical terms, if you have a set of vectors \([u_1, u_2, ..., u_n]\) that form a basis of the vector space \( extbf{R}^n\), these vectors meet two important criteria:
This ensures that they don't lean towards each other in any direction. Additionally, every vector has a length, or a 'magnitude', of one to simplify calculations.
In mathematical terms, if you have a set of vectors \([u_1, u_2, ..., u_n]\) that form a basis of the vector space \( extbf{R}^n\), these vectors meet two important criteria:
- Orthogonality: For any two different vectors, say \(u_i\) and \(u_j\), the dot product \(u_i \, \cdot \, u_j = 0\). This means they are perpendicular.
- Normalization: Each vector must have a length of 1. Expressed mathematically, \(|u_i| = 1\). This is what makes them 'unit vectors'.
Orthogonal Vectors
Orthogonal vectors are like friends who keep their distance. They hold no preference towards each other in any direction; they are completely independent. In \( extbf{R}^n\) space, vectors that hold this trait will have a dot product of zero.
Consider the formula for a dot product:
\[\text{dot}(\mathbf{a}, \mathbf{b}) = a_1b_1 + a_2b_2 + \ldots + a_nb_n,\]
where \(\mathbf{a}\) and \(\mathbf{b}\) are vectors. If \(\text{dot}(\mathbf{a}, \mathbf{b}) = 0\), these vectors are orthogonal.
Consider the formula for a dot product:
\[\text{dot}(\mathbf{a}, \mathbf{b}) = a_1b_1 + a_2b_2 + \ldots + a_nb_n,\]
where \(\mathbf{a}\) and \(\mathbf{b}\) are vectors. If \(\text{dot}(\mathbf{a}, \mathbf{b}) = 0\), these vectors are orthogonal.
- Perpendicularity: Think of orthogonal vectors as arrows pointing north and east. They meet at a right angle.
- Independence: Because orthogonal vectors are independent, information carried by one vector is not duplicative of the other.
Matrix Transpose
A matrix transpose is a neat trick that involves flipping a matrix over its diagonal. Imagine taking a table of numbers and exchanging its rows for columns - that's essentially what transposing does.
Notation-wise, if your matrix is \(A\), then \(A^T\) is the transpose of \(A\).
When applied to an orthogonal matrix, the transpose has a special property: it results in the inverse of that matrix. In simpler terms, if \(U\) is an orthogonal matrix, then \(U^T = U^{-1}\).
Notation-wise, if your matrix is \(A\), then \(A^T\) is the transpose of \(A\).
When applied to an orthogonal matrix, the transpose has a special property: it results in the inverse of that matrix. In simpler terms, if \(U\) is an orthogonal matrix, then \(U^T = U^{-1}\).
- Diagonal Flip: The main diagonal (from top left to bottom right) remains the same. It's all about swapping positions symmetrically across this line.
- Symmetric Matrices: If a matrix is equal to its own transpose, it is called symmetric. Some matrices, like identity matrices, are inherently symmetric.