Chapter 6: Problem 22
Let \(\mathbf{u}_{1}, \ldots, \mathbf{u}_{p}\) be an orthogonal basis for a subspace \(W\) of \(\mathbb{R}^{n},\) and let \(T : \mathbb{R}^{n} \rightarrow \mathbb{R}^{n}\) be defined by \(T(\mathbf{x})=\operatorname{proj}_{W} \mathbf{x}\) Show that \(T\) is a linear transformation.
Short Answer
Expert verified
The function \( T \) is a linear transformation because it satisfies both additivity and homogeneity properties.
Step by step solution
01
Recall Definition of Projection
The projection of a vector \( \mathbf{x} \) onto a subspace \( W \), which is spanned by an orthogonal basis \( \{ \mathbf{u}_1, \ldots, \mathbf{u}_p \} \), is given by the formula: \( \operatorname{proj}_{W} \mathbf{x} = \sum_{i=1}^{p} \frac{\mathbf{u}_i \cdot \mathbf{x}}{\mathbf{u}_i \cdot \mathbf{u}_i} \mathbf{u}_i \).
02
Verify Additivity
To show additivity, consider two vectors \( \mathbf{x} \) and \( \mathbf{y} \) in \( \mathbb{R}^n \). We find \( T(\mathbf{x} + \mathbf{y}) = \operatorname{proj}_W (\mathbf{x} + \mathbf{y}) = \sum_{i=1}^{p} \frac{\mathbf{u}_i \cdot (\mathbf{x} + \mathbf{y})}{\mathbf{u}_i \cdot \mathbf{u}_i} \mathbf{u}_i = \sum_{i=1}^{p} \frac{\mathbf{u}_i \cdot \mathbf{x}}{\mathbf{u}_i \cdot \mathbf{u}_i} \mathbf{u}_i + \sum_{i=1}^{p} \frac{\mathbf{u}_i \cdot \mathbf{y}}{\mathbf{u}_i \cdot \mathbf{u}_i} \mathbf{u}_i = \operatorname{proj}_W (\mathbf{x}) + \operatorname{proj}_W (\mathbf{y}) = T(\mathbf{x}) + T(\mathbf{y}) \).
03
Verify Homogeneity
To show homogeneity, take a scalar \( c \) and vector \( \mathbf{x} \), and calculate \( T(c\mathbf{x}) = \operatorname{proj}_{W} (c\mathbf{x}) = \sum_{i=1}^{p} \frac{\mathbf{u}_i \cdot (c\mathbf{x})}{\mathbf{u}_i \cdot \mathbf{u}_i} \mathbf{u}_i = \sum_{i=1}^{p} c \cdot \frac{\mathbf{u}_i \cdot \mathbf{x}}{\mathbf{u}_i \cdot \mathbf{u}_i} \mathbf{u}_i = c \cdot \operatorname{proj}_W (\mathbf{x}) = cT(\mathbf{x}) \).
04
Conclude Linearity
Since both additivity \( T(\mathbf{x} + \mathbf{y}) = T(\mathbf{x}) + T(\mathbf{y}) \) and homogeneity \( T(c\mathbf{x}) = cT(\mathbf{x}) \) have been verified, the function \( T \) is a linear transformation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Projection
The concept of a projection in linear algebra involves mapping a vector onto a subspace. Projection is particularly useful in many areas of mathematics, physics, and engineering because it simplifies the analysis of vectors by reducing their dimensionality. In our context, projecting a vector \( \mathbf{x} \) onto a subspace \( W \) spanned by an orthogonal basis \( \{ \mathbf{u}_1, \ldots, \mathbf{u}_p \} \) uses the formula:
\( \operatorname{proj}_{W} \mathbf{x} = \sum_{i=1}^{p} \frac{\mathbf{u}_i \cdot \mathbf{x}}{\mathbf{u}_i \cdot \mathbf{u}_i} \mathbf{u}_i \).
This formula essentially breaks down vector \( \mathbf{x} \) into components that are parallel to each of the basis vectors \( \mathbf{u}_i \).
\( \operatorname{proj}_{W} \mathbf{x} = \sum_{i=1}^{p} \frac{\mathbf{u}_i \cdot \mathbf{x}}{\mathbf{u}_i \cdot \mathbf{u}_i} \mathbf{u}_i \).
This formula essentially breaks down vector \( \mathbf{x} \) into components that are parallel to each of the basis vectors \( \mathbf{u}_i \).
- Firstly, each term \( \mathbf{u}_i \cdot \mathbf{x} \) represents the dot product between \( \mathbf{x} \) and \( \mathbf{u}_i \), indicating how much of \( \mathbf{x} \) lies in the direction of \( \mathbf{u}_i \).
- This term is then scaled by the length squared of \( \mathbf{u}_i \) (denoted \( \mathbf{u}_i \cdot \mathbf{u}_i \)) to factor out magnitude differences.
Orthogonal Basis
An orthogonal basis in a subspace is essential for simplifying calculations such as projections.
Orthogonality means that all basis vectors are perpendicular to each other.
For a set of vectors \( \{ \mathbf{u}_1, \ldots, \mathbf{u}_p \} \) to form an orthogonal basis for a subspace \( W \), each pair of different vectors must satisfy \( \mathbf{u}_i \cdot \mathbf{u}_j = 0 \) when \( i eq j \).
Orthogonality means that all basis vectors are perpendicular to each other.
For a set of vectors \( \{ \mathbf{u}_1, \ldots, \mathbf{u}_p \} \) to form an orthogonal basis for a subspace \( W \), each pair of different vectors must satisfy \( \mathbf{u}_i \cdot \mathbf{u}_j = 0 \) when \( i eq j \).
- Orthogonal vectors reduce complex problems into simpler, solvable parts, often leading to more efficient computational processes.
- An orthogonal set can be easily transformed into an orthonormal set, where each vector also has a unit length by dividing each vector by its own length.
Subspace
A subspace in linear algebra is a set of vectors that satisfies two main conditions:
For instance, all operations defined by vectors in \( W \) stay entirely within \( W \), ensuring that the calculations remain relevant to the subspace's span properties.
These properties keep transformations like projections within the logical and mathematical framework of subspaces.
- Any linear combination of vectors within the subspace is also a vector within the same subspace.
- It must include the zero vector.
For instance, all operations defined by vectors in \( W \) stay entirely within \( W \), ensuring that the calculations remain relevant to the subspace's span properties.
These properties keep transformations like projections within the logical and mathematical framework of subspaces.
Additivity
Additivity is a key property that defines linear transformations. A transformation \( T \) is additive if for any vectors \( \mathbf{x} \) and \( \mathbf{y} \) in \( \mathbb{R}^n \), the transformation satisfies:
\[ T(\mathbf{x} + \mathbf{y}) = T(\mathbf{x}) + T(\mathbf{y}) \]This property means that the transformation of a sum of vectors is equal to the sum of their individual transformations.
To demonstrate additivity, consider two vectors being projected onto \( W \). The projection of their sum should equal the sum of their projections:
\[ T(\mathbf{x} + \mathbf{y}) = T(\mathbf{x}) + T(\mathbf{y}) \]This property means that the transformation of a sum of vectors is equal to the sum of their individual transformations.
To demonstrate additivity, consider two vectors being projected onto \( W \). The projection of their sum should equal the sum of their projections:
- When \( T(\mathbf{x} + \mathbf{y}) \) is calculated, it splits into individual projections of \( \mathbf{x} \) and \( \mathbf{y} \), respecting individual component contributions.
- This behavior is critical for maintaining consistency across vector spaces undergoing the transformation process.
Homogeneity
Homogeneity, alongside additivity, qualifies a transformation as linear. For a transformation \( T \) to be homogeneous, it must hold true that for any scalar \( c \) and vector \( \mathbf{x} \), the relationship
\[ T(c\mathbf{x}) = cT(\mathbf{x}) \]is satisfied.
This means that scaling a vector before applying the transformation yields the same result as transforming the vector first and then scaling it.
Verifying homogeneity involves simply multiplying the vector \( \mathbf{x} \) by a scalar \( c \) and observing if the projection operation behaves as expected:
\[ T(c\mathbf{x}) = cT(\mathbf{x}) \]is satisfied.
This means that scaling a vector before applying the transformation yields the same result as transforming the vector first and then scaling it.
Verifying homogeneity involves simply multiplying the vector \( \mathbf{x} \) by a scalar \( c \) and observing if the projection operation behaves as expected:
- Every component of \( c\mathbf{x} \) in the direction of each basis \( \mathbf{u}_i \) is scaled by \( c \).
- This assures that the final transformation is scaled uniformly, preserving proportions across dimensions.