Chapter 6: Problem 18
Let \(\mathbf{y}=\left[\begin{array}{l}{7} \\ {9}\end{array}\right], \mathbf{u}_{1}=\left[\begin{array}{r}{1 / \sqrt{10}} \\ {-3 / \sqrt{10}}\end{array}\right],\) and \(W=\operatorname{Span}\left\\{\mathbf{u}_{1}\right\\}\) a. Let \(U\) be the \(2 \times 1\) matrix whose only column is \(\mathbf{u}_{1}\) . Compute \(U^{T} U\) and \(U U^{T}\) . b. Compute proj \(_{W} \mathbf{y}\) and \(\left(U U^{T}\right) \mathbf{y}\)
Short Answer
Step by step solution
Define Matrices
Compute \(U^T U\)
Compute \(U U^T\)
Calculate the Projection \(\text{proj}_W \mathbf{y}\)
Calculate \((UU^T)\mathbf{y}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Projection Matrix
A projection matrix is usually represented as \( P \) and is defined such that when it multiplies a vector, it returns that vector's projection onto the subspace. If you have a vector space represented by \( U \), and a vector \( \mathbf{y} \) you want to project, the projection matrix \( P \) is given by:
- \( P = U(U^T U)^{-1} U^T \)
In this exercise, we used the projection matrix to project \( \mathbf{y} \) onto the subspace spanned by \( \mathbf{u}_1 \). By applying this matrix, you can accurately find the shadow of \( \mathbf{y} \) in the direction defined by \( \mathbf{u}_1 \). This illustrates how projection matrices make complex spaces easier to navigate.
Subspace Projection
In mathematical terms, when you project a vector \( \mathbf{y} \) onto a subspace \( W \), you're looking for a vector in \( W \) that is as close as possible to \( \mathbf{y} \). This operation is highly useful for simplifying complex problems by using reduced dimensions or simpler approximations.
- A subspace is defined by its basis vectors, like \( \mathbf{u}_1 \) in our example.
- To project \( \mathbf{y} \) onto \( W \), we use the formula \( \text{proj}_W \mathbf{y} = U(U^T U)^{-1} U^T \mathbf{y} \). This method leverages the pre-computed values of \( U^T U \) and \( U U^T \).
Matrix Multiplication
In our exercise, matrix multiplication plays a critical role in creating the projection. Here, we used this operation to compute \( U^T U \), \( U U^T \), and the final projection onto subspace \( W \). Understanding how these matrices interact can greatly simplify many calculations in both theoretical and applied mathematics.
- To calculate \( U^T U \), multiply the transpose of \( U \) by itself. This results in a scalar value when \( U \) is a single column vector.
- \( U U^T \) multiplication provides us a projection matrix when \( U \) is an orthonormal matrix.
- Finally, multiply the obtained projection matrix with the vector \( \mathbf{y} \) to get the projected vector.