Chapter 6: Problem 14
In Exercises 13 and \(14,\) the columns of \(Q\) were obtained by applying the Gram-Schmidt process to the columns of \(A .\) Find an upper triangular matrix \(R\) such that \(A=Q R .\) Check your work. $$ A=\left[\begin{array}{rr}{-2} & {3} \\ {5} & {7} \\ {2} & {-2} \\ {4} & {6}\end{array}\right], Q=\left[\begin{array}{rr}{-2 / 7} & {5 / 7} \\ {5 / 7} & {2 / 7} \\ {2 / 7} & {-4 / 7} \\ {4 / 7} & {2 / 7}\end{array}\right] $$
Short Answer
Step by step solution
Understand the relationship
Find R using Q
Calculate Q Transpose
Multiply Q^T by A
Solve the multiplication
Simplify to find R
Verify A = QR
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