Chapter 5: Problem 21
Verify the statements in Exercises \(19-24 .\) The matrices are square. If \(B\) is similar to \(A\) and \(C\) is similar to \(A,\) then \(B\) is similar to \(C .\)
Short Answer
Expert verified
Yes, if B is similar to A and C is similar to A, then B is similar to C.
Step by step solution
01
Understand Similarity of Matrices
Two matrices \( B \) and \( A \) are said to be similar if there exists an invertible matrix \( P \) such that \( B = P^{-1}AP \). This transformation indicates that both matrices represent the same linear transformation under different bases.
02
Write the Given Similarity Conditions
From the problem, we have that \( B \) is similar to \( A \) which means \( B = P^{-1}AP \) for some invertible matrix \( P \), and \( C \) is similar to \( A \) which means \( C = Q^{-1}AQ \) for some invertible matrix \( Q \).
03
Derive the Relationship Between B and C
To show that \( B \) is similar to \( C \), we need to express \( B \) in the form \( B = R^{-1}CR \) for some invertible matrix \( R \). Given \( B = P^{-1}AP \) and \( C = Q^{-1}AQ \), we substitute \( A = QC^{-1}Q^{-1} \) into the expression for \( B \).
04
Calculate B Using Given Equations
Substitute \( A \) from the similarity of \( C = Q^{-1}AQ \) into \( B \)'s equation: \( B = P^{-1}(Q^{-1} C Q)P \). Simplifying, we get \( B = (PQ^{-1})C(QP^{-1}) \). Let \( R = QP^{-1} \), making \( B = R^{-1}CR \), proving \( B \) is similar to \( C \).
05
Verify R is Invertible
The product of invertible matrices is also invertible, hence \( R = QP^{-1} \) is invertible because both \( Q \) and \( P \) are invertible matrices.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Invertible Matrix
An invertible matrix, also known as a non-singular or non-degenerate matrix, is a square matrix that possesses an inverse. In simple terms, if you can "undo" the operation of a matrix using another matrix, then the original matrix is invertible.
Here's a more mathematical take: a matrix is invertible if there exists another matrix such that when they are multiplied, the result is the identity matrix, which is a matrix consisting of 1s on the diagonal and 0s elsewhere. For a matrix \( A \), this can be expressed as \( A \, A^{-1} = A^{-1} \, A = I \), where \( I \) is the identity matrix.
Remember, the identity matrix acts as the neutral element in matrix multiplication, akin to how 1 is in scalar multiplication. This ability of being neutral helps in "undoing" or reversing the transformations applied by the matrix.
Here's a more mathematical take: a matrix is invertible if there exists another matrix such that when they are multiplied, the result is the identity matrix, which is a matrix consisting of 1s on the diagonal and 0s elsewhere. For a matrix \( A \), this can be expressed as \( A \, A^{-1} = A^{-1} \, A = I \), where \( I \) is the identity matrix.
Remember, the identity matrix acts as the neutral element in matrix multiplication, akin to how 1 is in scalar multiplication. This ability of being neutral helps in "undoing" or reversing the transformations applied by the matrix.
- A matrix must be square (same number of rows and columns) to be invertible.
- Not all square matrices are invertible; a matrix with a determinant of zero is not invertible.
- An invertible matrix is related to transformations that are reversible, meaning information is fully retained.
Linear Transformation
A linear transformation is a function between two vector spaces that preserves vector addition and scalar multiplication. Essentially, it transforms vectors in a "straight" or "un-curved" fashion, maintaining the structure of the space. In terms of matrices, a linear transformation from one space to another can be represented by multiplying a vector by a matrix.
Here's the key: linear transformations are neatly captured by matrices, and any matrix that represents a linear transformation does so by defining how each vector in a space is modified. Consider a matrix \( A \), which transforms a vector \( \textbf{v} \) into a new vector \( A \textbf{v} \). The properties of linearity are:
Here's the key: linear transformations are neatly captured by matrices, and any matrix that represents a linear transformation does so by defining how each vector in a space is modified. Consider a matrix \( A \), which transforms a vector \( \textbf{v} \) into a new vector \( A \textbf{v} \). The properties of linearity are:
- Additivity: \( T(\textbf{u} + \textbf{v}) = T(\textbf{u}) + T(\textbf{v}) \) for any vectors \( \textbf{u} \) and \( \textbf{v} \).
- Homogeneity: \( T(c\textbf{v}) = cT(\textbf{v}) \) for any scalar \( c \) and vector \( \textbf{v} \).
Similar Matrices
Matrices \( A \) and \( B \) are said to be similar if one can be related to the other through an invertible matrix. More concretely, matrices \( B \) and \( A \) are similar if there exists an invertible matrix \( P \) such that \( B = P^{-1}AP \).
This similarity isn't just abstract; it tells us that \( A \) and \( B \) represent the same linear transformation, albeit under different coordinate systems or bases. This is akin to seeing a geometric shape from different angles—it's the same object, but appears different due to your viewing position.
Here are some important points about similar matrices:
This similarity isn't just abstract; it tells us that \( A \) and \( B \) represent the same linear transformation, albeit under different coordinate systems or bases. This is akin to seeing a geometric shape from different angles—it's the same object, but appears different due to your viewing position.
Here are some important points about similar matrices:
- They share the same eigenvalues, which are the scalars indicating the factors by which a transformation stretches or shrinks vectors.
- The determinant and trace (sum of diagonal elements) are also identical for similar matrices.
- Similar matrices are not identical but reflect the same underlying transformation properties.