/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 Exercises 31 and 32 concern fini... [FREE SOLUTION] | 91Ó°ÊÓ

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Exercises 31 and 32 concern finite-dimensional vector spaces \(V\) and \(W\) and a linear transformation \(T : V \rightarrow W\). Let \(H\) be a nonzero subspace of \(V,\) and suppose \(T\) is a one-to-one (linear) mapping of \(V\) into \(W .\) Prove that \(\operatorname{dim} T(H)=\operatorname{dim} H .\) If \(T\) happens to be a one-to-one mapping of \(V\) onto \(W,\) then \(\operatorname{dim} V=\operatorname{dim} W .\) Isomorphic finite- dimensional vector spaces have the same dimension.

Short Answer

Expert verified
If \( T \) is one-to-one, then \( \operatorname{dim} T(H) = \operatorname{dim} H \). If \( T \) is onto, then \( \operatorname{dim} V = \operatorname{dim} W \).

Step by step solution

01

Understanding Linear Maps

A linear map (or transformation) is a function between vector spaces that preserves vector addition and scalar multiplication. In this exercise, we have a linear map \( T: V \rightarrow W \) that is one-to-one, meaning each element of \( V \) maps to a unique element in \( W \).
02

Identifying Subspaces and Dimensions

Subspace \( H \) is given as a nonzero subspace of \( V \). The dimension of a subspace is the number of vectors in any basis of that subspace. Thus, to show that \( \operatorname{dim} T(H) = \operatorname{dim} H \), we need to relate the basis and dimensionality concepts.
03

Understanding One-to-One Linear Transformations

Since \( T \) is one-to-one, this implies that if \( T(v_1) = T(v_2) \), then \( v_1 = v_2 \) for any \( v_1, v_2 \in V \). This one-to-one property helps maintain the dimensionality between \( H \) and \( T(H) \).
04

Relating the Dimension of Subspaces Under Linear Transformation

A one-to-one linear transformation between vector spaces ensures that the dimension of the image of \( H \) under \( T \), noted as \( \operatorname{dim} T(H) \), equals \( \operatorname{dim} H \). This is because the one-to-one property ensures that each basis vector of \( H \) maps uniquely to a basis vector of \( T(H) \).
05

Considering Mapping Onto W

If \( T: V \rightarrow W \) is not only one-to-one but also onto, every element of \( W \) is an image under \( T \). The mapping from a finite-dimensional space \( V \) onto \( W \) implies that \( \operatorname{dim} V = \operatorname{dim} W \).
06

Conclusion on Isomorphic Vector Spaces

Two vector spaces are isomorphic if there exists a linear transformation that is both one-to-one and onto. It means isomorphic finite-dimensional vector spaces have the same dimension, supporting the final statement in the exercise.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Finite-Dimensional Vector Spaces
Vector spaces are mathematical structures that allow us to perform algebraic operations easily. They can have infinite or finite dimensions. In the context of this exercise, we deal with finite-dimensional vector spaces, which means they are spanned by a finite number of vectors. When discussing a finite-dimensional vector space, the number of vectors in the basis equates to the dimension of that space. This idea is crucial because dimensions help us understand size and capacity within vector spaces.
A finite-dimensional vector space provides a more structured and comprehensive framework when analyzing concepts like linear transformations and subspaces. For our exercise, knowing the finite dimensions of space allows us to apply properties of linear transformations effectively.
One-to-One Mapping
A one-to-one mapping, or injective mapping, plays a critical role in linear algebra. It means that each element of one set maps to exactly one unique element in another set with no overlaps. In our exercise, the linear transformation \( T: V \rightarrow W \) is described as one-to-one. This property indicates that if \( T(v_1) = T(v_2) \), then necessarily \( v_1 = v_2 \).
For students, understanding this mapping is essential because it ensures that the dimension of the subspace \( H \) will remain constant when mapped onto \( T(H) \). Each basis vector from \( H \) transforms into a unique vector in \( T(H) \), preserving the structure and complexity of the original subspace.
  • Ensures uniqueness in mapping.
  • Preserves the original dimension when mapping subspaces.
Subspace Dimension
When we deal with subspaces like \( H \) in vector spaces, recognizing their dimensions is vital. A subspace itself is a vector space, which means it could have its own basis and dimension. The key part of this exercise is understanding that the size or dimension of a subspace is equivalent to the number of vectors in its basis.
Given the one-to-one nature of \( T \), the dimension of \( T(H) \) is secured as \( \operatorname{dim} H \). Each vector in the basis of \( H \) maps to a distinct vector in \( T(H) \), preserving the dimension of the subspace under such a linear transformation. Understanding subspace dimensions aids in grasping larger vector space structures and transformations.
Isomorphic Vector Spaces
Isomorphic vector spaces are central to understanding equivalency in linear algebra. Two vector spaces are considered isomorphic if there's a bijective linear map between them: a function that's both one-to-one and onto. These spaces share similar structures and dimensions.
In essence, when \( T: V \rightarrow W \) is both one-to-one and onto, it tells us \( V \) and \( W \) have the same dimension, and thus, they are isomorphic. This equivalence in structure and size implies that they can be transformed into each other with an understanding that preserves linear operations. Recognizing isomorphic vector spaces helps mathematicians see when different-looking spaces are fundamentally the same, just expressed differently.

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Most popular questions from this chapter

In statistical theory, a common requirement is that a matrix be of full rank. That is, the rank should be as large as possible. Explain why an \(m \times n\) matrix with more rows than columns has full rank if and only if its columns are linearly independent.

A laboratory animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of \(50 \%,\) and it will choose the other foods on the next trial with equal probabilities of 25\(\% .\) a. What is the stochastic matrix for this situation? b. If the animal chooses food \(\\# 1\) on an initial trial, what is the probability that it will choose food \(\\# 2\) on the second trial after the initial trial?

Find a basis for the set of vectors in \(\mathbb{R}^{2}\) on the line \(y=5 x\)

Let \(\mathbf{v}_{1}=\left[\begin{array}{r}{7} \\ {4} \\ {-9} \\\ {-5}\end{array}\right], \mathbf{v}_{2}=\left[\begin{array}{r}{4} \\ {-7} \\\ {2} \\ {5}\end{array}\right], \mathbf{v}_{3}=\left[\begin{array}{r}{1} \\\ {-5} \\ {3} \\ {4}\end{array}\right] .\) It can be verified that \(\mathbf{v}_{1}-3 \mathbf{v}_{2}+5 \mathbf{v}_{3}=\mathbf{0} .\) Use this information to find a basis for \(H=\operatorname{Span}\left\\{\mathbf{v}_{1}, \mathbf{v}_{2}, \mathbf{v}_{3}\right\\}\)

Exercises 23 and 24 refer to a difference equation of the form \(y_{k+1}-a y_{k}=b,\) for suitable constants \(a\) and \(b\) A loan of \(\$ 10,000\) has an interest rate of 1\(\%\) per month and a monthly payment of \(\$ 450 .\) The loan is made at month \(k=0\) , and the first payment is made one month later, at \(k=1 .\) For \(k=0,1,2, \ldots,\) let \(y_{k}\) be the unpaid balance of the loan just after the \(k\) th monthly payment. Thus a. Write a difference equation satisfied by \(\left\\{y_{k}\right\\}\) b. \([\mathbf{M}]\) Create a table showing \(k\) and the balance \(y_{k}\) at month \(k .\) List the program or the keystrokes you used to create the table. c. \([\mathbf{M}]\) What will \(k\) be when the last payment is made? How much will the last payment be? How much money did the borrower pay in total?

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