Chapter 3: Problem 26
Let \(T : \mathbb{R}^{m} \rightarrow \mathbb{R}^{n}\) be a linear transformation, and let \(\mathbf{p}\) be a vector and \(S\) a set in \(\mathbb{R}^{m} .\) Show that the image of \(\mathbf{p}+S\) under \(T\) is the translated set \(T(\mathbf{p})+T(S)\) in \(\mathbb{R}^{n} .\)
Short Answer
Expert verified
The image under \(T\) of \(\mathbf{p}+S\) is \(T(\mathbf{p})+T(S)\).
Step by step solution
01
Understand the Given Problem
We have a linear transformation \(T : \mathbb{R}^{m} \rightarrow \mathbb{R}^{n}\), a vector \(\mathbf{p}\), and a set \(S\) within \(\mathbb{R}^{m}\). We need to show that the image of \(\mathbf{p}+S\) under the transformation \(T\) results in the set \(T(\mathbf{p})+T(S)\).
02
Construct the Set \(\mathbf{p}+S\)
The set \(\mathbf{p} + S\) is defined as \(\{ \mathbf{p} + \mathbf{s} \, | \, \mathbf{s} \in S \}\). This means each element of this set is obtained by adding vector \(\mathbf{p}\) to each vector in \(S\).
03
Apply the Linear Transformation
The image of the set \(\mathbf{p}+S\), denoted as \(T(\mathbf{p} + S)\), is defined by applying \(T\) to each element of \(\mathbf{p}+S\), resulting in \(\{ T(\mathbf{p} + \mathbf{s}) \, | \, \mathbf{s} \in S \}\).
04
Use the Property of Linear Transformation
For a linear transformation, \(T(\mathbf{a} + \mathbf{b}) = T(\mathbf{a}) + T(\mathbf{b})\). Applying this property, we have \(T(\mathbf{p} + \mathbf{s}) = T(\mathbf{p}) + T(\mathbf{s})\) for any \(\mathbf{s} \in S\).
05
Construct the Translated Set
The set \(T(\mathbf{p}) + T(S)\) is defined as \(\{ T(\mathbf{p}) + \mathbf{t} \, | \, \mathbf{t} \in T(S) \}\). Since \(T(S) = \{ T(\mathbf{s}) \, | \, \mathbf{s} \in S \}\), it follows that \(T(\mathbf{p}) + T(S) = \{ T(\mathbf{p}) + T(\mathbf{s}) \, | \, \mathbf{s} \in S \}\).
06
Conclude the Proof
From Steps 3 and 5, we see that \(T(\mathbf{p}+S) = \{ T(\mathbf{p}) + T(\mathbf{s}) \, | \, \mathbf{s} \in S \} = T(\mathbf{p}) + T(S)\), proving that the image of \(\mathbf{p}+S\) under \(T\) is \(T(\mathbf{p}) + T(S)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Set Translation
In mathematics, a set translation involves shifting an entire set of vectors by a fixed vector. Consider we have a vector \( \mathbf{p} \) and a set \( S \) in \( \mathbb{R}^m \). Set translation means creating a new set \( \mathbf{p} + S \), which is \( \{ \mathbf{p} + \mathbf{s} \mid \mathbf{s} \in S \} \).
Essentially, you're adding the vector \( \mathbf{p} \) to each element of the set \( S \). This is akin to picking up every vector in \( S \) and moving it over by \( \mathbf{p} \). Here are a few characteristics of set translation:
Essentially, you're adding the vector \( \mathbf{p} \) to each element of the set \( S \). This is akin to picking up every vector in \( S \) and moving it over by \( \mathbf{p} \). Here are a few characteristics of set translation:
- Set translation preserves the shape and structure of \( S \). All vectors in \( S \) maintain their relative positions to one another.
- While its position in space shifts, the size and orientation stay the same.
- If \( T \) is a linear transformation, the translated set still respects linear operations when mapped.
Linear Mapping
A linear mapping, or linear transformation, is a function that maps vectors from one vector space to another while preserving two operations: vector addition and scalar multiplication.
Given a transformation \( T : \mathbb{R}^m \rightarrow \mathbb{R}^n \), it follows two main rules:
\( T(\mathbf{p}+\mathbf{s}) = T(\mathbf{p}) + T(\mathbf{s}) \). This property is fundamental in proving that the set translation holds under \( T \).
This predictability in behavior makes linear maps a powerful tool in various applications, including geometry, physics, and computer graphics.
Given a transformation \( T : \mathbb{R}^m \rightarrow \mathbb{R}^n \), it follows two main rules:
- **Additivity:** \( T(\mathbf{a} + \mathbf{b}) = T(\mathbf{a}) + T(\mathbf{b}) \). This implies that when two vectors are added before applying the transformation, the result is the same as applying the transformation separately and adding the results.
- **Homogeneity:** \( T(c\mathbf{a}) = cT(\mathbf{a}) \) for any scalar \( c \). This ensures that scaling a vector before transformation yields the same result as scaling the transformed vector.
\( T(\mathbf{p}+\mathbf{s}) = T(\mathbf{p}) + T(\mathbf{s}) \). This property is fundamental in proving that the set translation holds under \( T \).
This predictability in behavior makes linear maps a powerful tool in various applications, including geometry, physics, and computer graphics.
Vector Addition
Vector addition is a foundational operation in vector spaces. It involves combining two vectors to produce a third vector. Given vectors \( \mathbf{a} \) and \( \mathbf{b} \), their addition \( \mathbf{a} + \mathbf{b} \) produces a vector which is achieved by adding each corresponding component of \( \mathbf{a} \) and \( \mathbf{b} \).
Vector addition has specific properties that make it an essential operation in linear algebra:
Vector addition has specific properties that make it an essential operation in linear algebra:
- **Commutativity:** \( \mathbf{a} + \mathbf{b} = \mathbf{b} + \mathbf{a} \). The order in which you add vectors does not affect their sum.
- **Associativity:** \( (\mathbf{a} + \mathbf{b}) + \mathbf{c} = \mathbf{a} + (\mathbf{b} + \mathbf{c}) \). This property allows you to group additions in different ways.
- **Identity Element:** There exists a zero vector \( \mathbf{0} \) such that \( \mathbf{a} + \mathbf{0} = \mathbf{a} \).
- **Inverse Elements:** For any vector \( \mathbf{a} \), there exists a vector \( -\mathbf{a} \) such that \( \mathbf{a} + (-\mathbf{a}) = \mathbf{0} \).