Chapter 2: Problem 30
If \(A\) is an \(n \times n\) matrix and the transformation \(\mathbf{x} \mapsto A \mathbf{x}\) is one-to-one, what else can you say about this transformation? Justify your answer.
Short Answer
Expert verified
The transformation is bijective, meaning it is both one-to-one and onto.
Step by step solution
01
Understanding One-to-One Transformation
A transformation is one-to-one (injective) if different inputs map to different outputs, i.e., for any vectors \( \mathbf{u} \) and \( \mathbf{v} \), when \( \mathbf{u} eq \mathbf{v} \), then \( A\mathbf{u} eq A\mathbf{v} \). This implies that the null space (kernel) of \( A \) contains only the zero vector.
02
Connection to Linear Independence and Invertibility
If \( A \) is a one-to-one transformation, it means the columns of \( A \) are linearly independent. This implies \( A \) must have full rank \( n \). Consequently, an \( n \times n \) matrix with full rank is invertible. Thus, the transformation \( A\mathbf{x} \) is also onto (surjective).
03
Understanding Onto (Surjective) Transformations
An onto transformation maps \( \mathbb{R}^n \) to \( \mathbb{R}^n \) where every vector in the codomain has a pre-image in the domain. For matrix \( A \), being onto means its rank is \( n \) and its rows span \( \mathbb{R}^n \). As \( A \) is both one-to-one and onto, it is bijective.
04
Conclusion Based on Invertibility
Since \( A \) is one-to-one and \( n \times n \), we conclude that \( A \) is invertible. Therefore, the transformation is both one-to-one and onto, meaning \( \mathbf{x} \mapsto A\mathbf{x} \) is bijective.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Invertibility
When discussing matrix invertibility, it implies that the matrix has an inverse; in other words, there exists another matrix which, when multiplied with the original matrix, yields the identity matrix. Specifically for an \( n \times n \) matrix \( A \), this means there is a matrix \( A^{-1} \) such that \( A \cdot A^{-1} = I \) and \( A^{-1} \cdot A = I \), where \( I \) is the identity matrix.
If a matrix is invertible, it naturally follows that:
If a matrix is invertible, it naturally follows that:
- It has full rank, meaning there are \( n \) linearly independent rows and columns.
- There is a unique solution to the system of linear equations \( A\mathbf{x} = \mathbf{b} \) for any vector \( \mathbf{b} \) in \( \mathbb{R}^n \).
- No zero eigenvalues, as having a zero eigenvalue would imply singularity (the matrix is non-invertible).
Linear Independence
Linear independence is a fundamental concept in linear algebra, particularly when dealing with vectors and matrices. A set of vectors is said to be linearly independent if no vector in the set can be written as a linear combination of the others. For an \( n \times n \) matrix \( A \), its columns are linearly independent if the only solution to \( A\mathbf{x} = \mathbf{0} \) is the trivial solution, where \( \mathbf{x} \) is the zero vector.
This concept ties closely to several characteristics, such as:
This concept ties closely to several characteristics, such as:
- Each vector adds a new dimension to the span, meaning the vectors span a space of dimension equal to the number of vectors.
- In an \( n \times n \) matrix with linearly independent columns, each column must contribute uniquely without being represented by others.
- It is directly related to the matrix having full rank \( n \), leading to invertibility.
Bijective Transformation
A bijective transformation, or bijection, is both one-to-one (injective) and onto (surjective). This means every element in the range is mapped by exactly one element in the domain, and every element in the domain maps to a unique element in the range. In terms of a linear transformation represented by a matrix \( A \), such a transformation \( A\mathbf{x} \) is bijective if \( A \) is an invertible \( n \times n \) matrix.
The bijection property embraces:
The bijection property embraces:
- The injective nature implies that the transformation is one-to-one; different input vectors result in different output vectors.
- The surjective nature ensures every possible output value has a corresponding input, meaning the transformation fully covers the target space \( \mathbb{R}^n \).
- Together, injective and surjective properties confirm that the transformation is reversible, allowing for the mapping to be inverted.