/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Let \(A\) be a \(6 \times 5\) ma... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(A\) be a \(6 \times 5\) matrix. What must \(a\) and \(b\) be in order to define \(T : \mathbb{R}^{a} \rightarrow \mathbb{R}^{b}\) by \(T(\mathbf{x})=A \mathbf{x} ?\)

Short Answer

Expert verified
To define \( T: \mathbb{R}^{a} \rightarrow \mathbb{R}^{b}\), \( a = 5 \) and \( b = 6 \).

Step by step solution

01

Define Domain Dimension of T

The function \( T: \mathbb{R}^a \rightarrow \mathbb{R}^b \) is defined by the matrix-vector product \( T(\mathbf{x}) = A \mathbf{x} \). For the multiplication \( A \mathbf{x} \) to be defined, vector \( \mathbf{x} \) must have the same number of components as the number of columns in matrix \( A \). Since \( A \) is a \( 6 \times 5 \) matrix, it has 5 columns, hence \( a = 5 \).
02

Define Codomain Dimension of T

The result of the matrix-vector product \( A \mathbf{x} \) becomes a vector in \( \mathbb{R}^b \), which is determined by the number of rows in the matrix \( A \). Since \( A \) has 6 rows, \( A \mathbf{x} \) results in a vector in \( \mathbb{R}^6 \), hence \( b = 6 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix-Vector Multiplication
Matrix-vector multiplication is a key operation in linear algebra and involves two main components: a matrix and a vector. To perform this operation, the matrix must have the same number of columns as the number of entries in the vector.
For example, if we have a matrix \( A \) with dimensions \( m \times n \) (meaning it has \( m \) rows and \( n \) columns), the vector \( \mathbf{x} \) must be \( n \) components long.
The product \( A\mathbf{x} \) is calculated by taking each row of the matrix and performing a dot product with the vector, resulting in a new vector that has \( m \) components. Each component of the resulting vector is a weighted sum of the vector components, weighted by the corresponding elements in a row of the matrix.
Domain and Codomain
Understanding the domain and codomain in the context of linear transformations is essential. The domain is the set of all possible inputs for a linear transformation, while the codomain is the set of potential outputs.
In the context of a linear transformation \( T: \mathbb{R}^a \rightarrow \mathbb{R}^b \), we define it using a matrix \( A \). The domain of \( T \) corresponds to \( \mathbb{R}^a \), which means that input vectors must have \( a \) components. The codomain \( \mathbb{R}^b \) signifies that output vectors resulting from the transformation will have \( b \) components.
For your exercise, given matrix \( A \) is 6x5, the domain is \( \mathbb{R}^5 \) because the vector must have 5 components (matching the 5 columns of \( A \)). Meanwhile, the codomain is \( \mathbb{R}^6 \), reflecting the 6 rows of the matrix \( A \), indicating that \( T(x) \) will always result in a vector with 6 components.
Dimensions of a Matrix
The dimensions of a matrix are given as \( m \times n \), which indicates the matrix has \( m \) rows and \( n \) columns. These dimensions are fundamental for determining matrix compatibility during mathematical operations like multiplication.
When you look at matrix dimensions, it's vital they match appropriately with other mathematical elements. For matrix-vector multiplication to be valid, the number of columns of the matrix must equal the number of components in the vector. If not, the multiplication isn't defined.
Moreover, when dealing with transformations, the dimensions also inform you about the domain and codomain, as in this case with matrix \( A \).\( A \) is described as \( 6 \times 5 \), meaning it operates within a transformation context from a 5-dimensional space into a 6-dimensional space, effectively reflected in \( T: \mathbb{R}^5 \rightarrow \mathbb{R}^6 \).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine by inspection whether the vectors are linearly independent. Justify each answer. \(\left[\begin{array}{l}{4} \\\ {4}\end{array}\right],\left[\begin{array}{r}{-1} \\\ {3}\end{array}\right],\left[\begin{array}{l}{2} \\\ {5}\end{array}\right],\left[\begin{array}{l}{8} \\ {1}\end{array}\right]\)

1\( produces ore that contains 20 metric tons of copper and 550 kilograms of silver, while one day's opera… # A mining company has two mines. One day's operation at mine \)\\# 1\( produces ore that contains 20 metric tons of copper and 550 kilograms of silver, while one day's operation at mine \)\\# 2\( produces ore that contains 30 metric tons of copper and 500 kilograms of silver. Let \)\mathbf{v}_{1}=\left[\begin{array}{c}{20} \\ {550}\end{array}\right]\( and \)\mathbf{v}_{2}=\left[\begin{array}{c}{30} \\ {500}\end{array}\right] .\( Then \)\mathbf{v}_{1}\( and \)\mathbf{v}_{2}\( represent the "output per day" of mine \)\\# 1\( and mine \)\\# 2\( , respectively. a. What physical interpretation can be given to the vector 5 \)\mathbf{v}_{1} ?\( b. Suppose the company operates mine \)\\# 1\( for \)x_{1}\( days and mine \)\\# 2\( for \)x_{2}\( days. Write a vector equation whose solution gives the number of days each mine should operate in order to produce 150 tons of copper and 2825 kilograms of silver. Do not solve the equation. c. \)[\mathbf{M}]\( Solve the equation in \)(b)$

Suppose an economy has only two sectors, Goods and Services. Each year, Goods sells 80\(\%\) of its output to Services and keeps the rest, while Services sells 70\(\%\) of its output to Goods and retains the rest. Find equilibrium prices for the annual outputs of the Goods and Services sectors that make each sector's income match its expenditures.

Each statement in Exercises 33–38 is either true (in all cases) or false (for at least one example). If false, construct a specific example to show that the statement is not always true. Such an example is called a counterexample to the statement. If a statement is true, give a justification. (One specific example cannot explain why a statement is always true. You will have to do more work here than in Exercises 21 and 22.) If \(\mathbf{v}_{1}, \ldots, \mathbf{v}_{4}\) are in \(\mathbb{R}^{4}\) and \(\left\\{\mathbf{v}_{1}, \mathbf{v}_{2}, \mathbf{v}_{3}\right\\}\) is linearly dependent, then \(\left\\{\mathbf{v}_{1}, \mathbf{v}_{2}, \mathbf{v}_{3}, \mathbf{v}_{4}\right\\}\) is also linearly dependent.

Determine by inspection whether the vectors are linearly independent. Justify each answer. \(\left[\begin{array}{r}{4} \\ {-2} \\\ {6}\end{array}\right],\left[\begin{array}{r}{6} \\ {-3} \\\ {9}\end{array}\right]\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.