Chapter 6: Problem 5
If \(A\) and \(B\) are positive definite, then \(A+B\) is positive definite. Pivots and eigenvalues are not convenient for \(A+B\). Much better to prove \(x^{\mathrm{T}}(A+B) x>0\).
Short Answer
Expert verified
Yes, if both \(A\) and \(B\) are positive definite, then \(A+B\) is also positive definite.
Step by step solution
01
Understand Positive Definiteness
A matrix is positive definite if for any non-zero vector \( x \), the expression \( x^{\mathrm{T}} A x > 0 \). Both matrices \( A \) and \( B \) are positive definite, meaning \( x^{\mathrm{T}} A x > 0 \) and \( x^{\mathrm{T}} B x > 0 \) for any non-zero vector \( x \).
02
Formulate the Expression for A+B
The matrix \( A+B \) must be shown to be positive definite. According to the definition, we need to prove that \( x^{\mathrm{T}} (A+B) x > 0 \) for any non-zero vector \( x \). This will give us the condition for positive definiteness of the addition \( A+B \).
03
Expand the Expression
Expand the expression \( x^{\mathrm{T}}(A+B)x \) to \( x^{\mathrm{T}}Ax + x^{\mathrm{T}}Bx \) using the properties of matrix addition and vector multiplication.
04
Use Positive Definiteness of A and B
Since both \( A \) and \( B \) are positive definite, \( x^{\mathrm{T}} A x > 0 \) and \( x^{\mathrm{T}} B x > 0 \) for any non-zero vector \( x \). Thus, \( x^{\mathrm{T}}Ax + x^{\mathrm{T}}Bx > 0 + 0 = 0 \).
05
Conclusion
Since \( x^{\mathrm{T}} (A+B) x = x^{\mathrm{T}}Ax + x^{\mathrm{T}}Bx > 0 \) for any non-zero \( x \), the matrix \( A+B \) is positive definite. The addition of two positive definite matrices results in a positive definite matrix.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Addition
Matrix addition is a basic operation where corresponding elements from two matrices are added together to produce a new matrix. For example, if you have two matrices \( A \) and \( B \), each of size \( n \times m \), then their sum \( A + B \) is calculated by adding each element of \( A \) to the corresponding element of \( B \).
To better illustrate this, consider two simple 2x2 matrices:
To better illustrate this, consider two simple 2x2 matrices:
- \( A = \begin{pmatrix} a_{11} & a_{12} \ a_{21} & a_{22} \end{pmatrix} \)
- \( B = \begin{pmatrix} b_{11} & b_{12} \ b_{21} & b_{22} \end{pmatrix} \)
- \( C = \begin{pmatrix} a_{11} + b_{11} & a_{12} + b_{12} \ a_{21} + b_{21} & a_{22} + b_{22} \end{pmatrix} \)
Vector Multiplication
Vector multiplication can represent several types of operations, but here we focus on multiplying a matrix by a vector, which is crucial in the context of positive definiteness. When you multiply a vector \( x \) by a matrix, we're usually referring to the dot product or the expression \( x^{\mathrm{T}}Ax \).
This operation combines two vectors into a single number. Specifically, \( x^{\mathrm{T}} \) (the transpose of \( x \)) is multiplied by \( A \), and the result is multiplied by \( x \) again. This process essentially measures how a vector is transformed by a matrix, and plays a key role in checking if a matrix is positive definite.
This operation combines two vectors into a single number. Specifically, \( x^{\mathrm{T}} \) (the transpose of \( x \)) is multiplied by \( A \), and the result is multiplied by \( x \) again. This process essentially measures how a vector is transformed by a matrix, and plays a key role in checking if a matrix is positive definite.
- For vector \( x \), its transpose \( x^{\mathrm{T}} \) is the row equivalent, turning it from a column vector to a row vector.
- Multiplying \( x^{\mathrm{T}} \) by matrix \( A \) results in another vector.
- Finally, multiplying this new vector by \( x \) gives a scalar value which must be greater than zero for positive definiteness.
Positive Definite Matrix
Understanding the concept of a positive definite matrix is vital when dealing with linear algebra and various mathematical computations. A matrix is called positive definite if, for any non-zero vector \( x \), the expression \( x^{\mathrm{T}} A x > 0 \) always holds true. This definition implies that such matrices exhibit certain desirable properties.
Here's why positive definite matrices are significant:
Here's why positive definite matrices are significant:
- They feature in optimization problems where you want guaranteed solutions due to their convex nature.
- They ensure systems derived from physical processes (like in engineering) are stable.
- In machine learning, positive definiteness ensures algorithms converge to solutions efficiently.
Eigenvalues
Eigenvalues are a fundamental concept in linear algebra, associated with a matrix. They provide immense insights about the matrix, particularly concerning stability, vibration, and optimization problems. When a matrix \( A \) is multiplied by one of its eigenvectors \( v \), the output is just a scaled version of \( v \) itself, where the scale factor is known as the eigenvalue \( \lambda \).
This is expressed mathematically as:
This is expressed mathematically as:
- \( Av = \lambda v \)
- For a matrix to be positive definite, all its eigenvalues must be positive.
- If even one eigenvalue is non-positive (zero or negative), the matrix isn't positive definite.