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What matrix \(P\) projects every point in \(\mathbf{R}^{3}\) onto the line of intersection of the planes \(x+y+t=0\) and \(x-t=0 ?\)

Short Answer

Expert verified
The projection matrix is \(P = \frac{1}{6} \begin{pmatrix} 1 & -2 & 1 \\ -2 & 4 & -2 \\ 1 & -2 & 1 \end{pmatrix}\).

Step by step solution

01

Understand the Intersection

To find the intersection of the planes given by the equations \(x + y + t = 0\) and \(x - t = 0\), we need to solve these equations simultaneously. Notice that \(x = t\) from the second plane.
02

Solve for Intersection Line

Substitute \(x = t\) into the first plane equation: \(t + y + t = 0\) which simplifies to \(2t + y = 0\). Solving for \(y\), we have \(y = -2t\). Thus, a parametric representation of the line is \((x, y, t) = (t, -2t, t)\). Let \(t\) be the parameter: \((t, -2t, t) = t(1, -2, 1)\). The direction vector of the line is \((1, -2, 1)\).
03

Express Direction as a Vector

The line of intersection can be represented by the direction vector \(\begin{pmatrix} 1 \ -2 \ 1 \end{pmatrix}\). We aim to project points onto this line.
04

Create Projection Matrix Formula

To project onto a line defined by a vector \(\mathbf{v} = \begin{pmatrix} a \ b \ c \end{pmatrix}\), the projection matrix \(P\) is given by the formula: \(P = \frac{1}{{a^2 + b^2 + c^2}} \begin{pmatrix} a^2 & ab & ac \ ab & b^2 & bc \ ac & bc & c^2 \end{pmatrix}\).
05

Calculate Projection Matrix

Using \(\mathbf{v} = \begin{pmatrix} 1 \ -2 \ 1 \end{pmatrix}\), we have \(a = 1, b = -2, c = 1\). Calculate \(a^2 + b^2 + c^2 = 1 + (-2)^2 + 1 = 6\). Thus, the projection matrix \(P\) is:\[ P = \frac{1}{6} \begin{pmatrix} 1 & -2 & 1 \ -2 & 4 & -2 \ 1 & -2 & 1 \end{pmatrix} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Line of Intersection
When two planes intersect in three-dimensional space, their intersection forms a line. To identify this line from the planes given by the equations \( x + y + t = 0 \) and \( x - t = 0 \), we solve these equations together. This means we look for the set of points that satisfy both. The second equation, \( x - t = 0 \), simplifies the determination of \( x \), allowing us to state that \( x = t \).
Using this expression for \( x \) in the first equation provides further simplifications. By substituting \( x = t \), the first equation becomes \( t + y + t = 0 \), which simplifies to \( 2t + y = 0 \). Solving these two equations simultaneously enables us to describe the line where these planes intersect. This intersection line can be visualized as a collection of all possible solutions that meet both plane equations.
Hence, finding the intersection of two planes essentially involves solving their simultaneous equations for a set of linear solutions.
Direction Vector
The direction vector helps us express both the orientation and extent of a straight line in space. For the line of intersection described by the simultaneous equations, the direction is rendered through a vector. In our previous example, after determining that \( x = t \) and \( y = -2t \), the line can be represented with the parametric form \( (x, y, t) = (t, -2t, t) \).
This form allows us to identify the direction vector, which is \( \begin{pmatrix} 1 \ -2 \ 1 \end{pmatrix} \). Such a vector specifies the changes in \( x \), \( y \), and \( t \) as we move along the line, effectively showing where and how fast each coordinate changes.
Understanding the direction vector is critical in creating a projection matrix for projecting points onto a line, a common application in computer graphics and data analysis. Essentially, it's the backbone of defining a line's spatial trajectory.
Parametric Representation
The parametric representation of a line is a simple and effective way to express a line in three-dimensional space. Derived from the equations of the planes \( x + y + t = 0 \) and \( x - t = 0 \), the parametric form we obtained was \( (x, y, t) = (t, -2t, t) \).
This form uses a parameter, often denoted by \( t \), that can take any real value to determine specific points on the line. Each component of the vector equation shows the relationship between a point on the line and the parameter \( t \).
The beauty of this representation lies in its simplicity, enabling us to visualize and calculate exact points for different values of \( t \), making it easier to apply transformations like projection or determine where the line intersects with other geometrical objects.
Simultaneous Equations
Simultaneous equations play a crucial role when determining the intersection line between two planes. By solving them, we essentially find all the points that lie on both planes. For the given planes \( x + y + t = 0 \) and \( x - t = 0 \), we used simultaneous equations to simplify and eventually eliminate variables to express the intersection in terms of a single parameter \( t \).
The technique involves expressing one variable in terms of another, which we did by letting \( x = t \). Plugging this into the first equation, we found \( y = -2t \).
This process allows mathematicians and engineers to define constraints and relationships between multiple equations quickly. Simultaneous equations are a powerful mathematical tool, foundational in algebra, calculus, and applied mathematics, helping us to handle a plethora of practical problems from high school physics to cutting-edge engineering.

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