Chapter 2: Problem 18
To decide whether \(b\) is in the subspace spanned by \(w_{1}, \ldots, w_{n}\), let the vectors \(w\) be the columns of \(A\) and try to solve \(A x=b\). What is the result for (a) \(w_{1}=(1,1,0), w_{2}=(2,2,1), w_{3}=(0,0,2), b=(3,4,5) ?\) (b) \(w_{1}=(1,2,0), w_{2}=(2,5,0), w_{3}=(0,0,2), w_{4}=(0,0,0)\), and any \(b\) ?
Short Answer
Step by step solution
Construct matrix A from column vectors
Set up equation Ax = b
Solve for x using augmented matrix
Analyze results for consistency
Conclude whether b is in the span
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Spaces
In the context of this exercise, the vectors provided, \( w_1, w_2, w_3, \) and \( w_4 \), form a part of the vector space. We are tasked with determining whether another vector, \( b \), can be expressed within this vector space through a specific combination of these vectors.
Linear Combinations
This exercise asks us to decide if a vector \( b \) is expressible as a linear combination of the given vectors \( w_1, w_2, \ldots, w_n \). This involves solving the equation \( Ax = b \), where \( A \) is the matrix whose columns are \( w_1, w_2, \ldots, w_n \). Solving this equation helps determine if such scalars \( c_1, c_2, \ldots, c_n \) exist to express \( b \).
Row Reduction
In the context of this problem, row reduction begins with setting up an augmented matrix that combines matrix \( A \) and vector \( b \). Then, through a series of operations like swapping rows, multiplying by scalars, and adding/subtracting rows, we simplify the matrix to solve for the unknown vector \( x \). Through analysis of the resulting matrix, you can determine if the system is consistent and if \( b \) is indeed a linear combination of the \( w \) vectors.
Augmented Matrix
Using the augmented matrix, we apply row reduction methods to find solutions for \( x \) in the linear equation \( Ax = b \). In problem (a), the matrix \( A \) augmented by \( b \) forms a straight path forward to determine if a solution exists. A consistent system—a row in the form of \( 0x_1 + 0x_2 + 0x_3 = 0 \) in row-reduced form—indicates \( b \) is part of the vector space spanned by \( w_1, w_2, \) and \( w_3 \). For problem (b), the presence of the zero vector in \( A \) indicates potential issues in forming a general solution, often resulting in inconsistencies regardless of \( b \).