Chapter 6: Problem 9
Find the matrix \([T]_{C \leftarrow B}\) of the linear transformation \(T: V \rightarrow W\) with respect to the bases \(\mathcal{B}\) and \(\mathcal{C}\) of \(\mathrm{V}\) and \(\mathrm{W}\), respectively. Verify Theorem 6.26 for the vector \(\mathrm{v}\) by computing \(T\) ( \(\mathbf{v}\) ) directly and using the theorem. \(T: M_{22} \rightarrow M_{22}\) defined by \(T(A)=A^{T}, \mathcal{B}=\mathcal{C}=\) \(\left\\{E_{11}, E_{12}, E_{21}, E_{22}\right\\}, \mathbf{v}=A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\)
Short Answer
Step by step solution
Identify basis matrices and transformation
Apply the transformation to basis matrices
Express transformed matrices in basis \( \mathcal{C} \)
Form matrix \([T]_{C \leftarrow B}\) from coordinate vectors
Verify Theorem 6.26 by direct computation and matrix multiplication
Compare results to verify correctness
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Basis
In our example, the basis \( \mathcal{B} = \mathcal{C} = \{E_{11}, E_{12}, E_{21}, E_{22}\} \) consists of matrices where each matrix has only one entry as 1 and zeroes elsewhere, representing key positions in a 2x2 matrix. This forms a foundation that allows us to meticulously describe and compute transformations in \( M_{22} \), the space of all 2x2 matrices.
- \( E_{11} \) is \( \begin{bmatrix} 1 & 0 \ 0 & 0 \end{bmatrix} \), indicating the position (1,1).
- \( E_{12} \) is \( \begin{bmatrix} 0 & 1 \ 0 & 0 \end{bmatrix} \), indicating (1,2).
- \( E_{21} \) is \( \begin{bmatrix} 0 & 0 \ 1 & 0 \end{bmatrix} \), indicating (2,1).
- \( E_{22} \) is \( \begin{bmatrix} 0 & 0 \ 0 & 1 \end{bmatrix} \), indicating (2,2).
Matrix Transposition
For example, if \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \), then \( A^T = \begin{bmatrix} a & c \ b & d \end{bmatrix} \).
This transformation shifts the elements \( b \) and \( c \, \) affecting the orientation of the matrix while preserving mathematical properties like symmetry. In our problem, the transformation \( T(A) = A^T \) is applied to each of the basis matrices, resulting in:
- \( T(E_{11}) = E_{11}^T = E_{11} \)
- \( T(E_{12}) = E_{12}^T = E_{21} \)
- \( T(E_{21}) = E_{21}^T = E_{12} \)
- \( T(E_{22}) = E_{22}^T = E_{22} \)
Theorem 6.26
This theorem is verified by illustrating that applying the linear transformation \( T(A) = A^T \) on a vector \( v \), represented in the basis \( \mathcal{B} \, \) can be achieved equivalently twofold:
- Direct computation: Transpose the vector \( A \) to get \( A^T \).
- Matrix multiplication: Multiply the transformation matrix \( [T]_{C \leftarrow B} \) by the coordinate vector of \( v \).
Coordinate Vectors
In our exercise, by expressing vectors like \( T(E_{11}) = E_{11} \) and others in terms of the basis \( \mathcal{C} \), \ we convert these expressions into coordinate vectors. Each vector’s impact is recorded through a specific format that aids in constructing the matrix \( [T]_{C \leftarrow B} \).
The coordinate vectors of the transformed matrices form the columns of \( [T]_{C \leftarrow B} \):
- \( T(E_{11}) = E_{11} \rightarrow \begin{bmatrix} 1 \ 0 \ 0 \ 0 \end{bmatrix} \)
- \( T(E_{12}) = E_{21} \rightarrow \begin{bmatrix} 0 \ 0 \ 1 \ 0 \end{bmatrix} \)
- \( T(E_{21}) = E_{12} \rightarrow \begin{bmatrix} 0 \ 1 \ 0 \ 0 \end{bmatrix} \)
- \( T(E_{22}) = E_{22} \rightarrow \begin{bmatrix} 0 \ 0 \ 0 \ 1 \end{bmatrix} \)