/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 Let \(f(x)=\sin ^{2} x\) and \(g... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(f(x)=\sin ^{2} x\) and \(g(x)=\cos ^{2} x\). Determine whether \(h(x)\) is in span \((f(x), g(x))\). $$h(x)=\sin 2 x$$

Short Answer

Expert verified
No, \( \sin 2 x \) is not in the span of \( \sin^2 x \) and \( \cos^2 x \).

Step by step solution

01

Understand the Definition of Span

The span of two functions, \(f(x)\) and \(g(x)\), refers to all linear combinations of these functions. A function \(h(x)\) is in the span of \(f(x)\) and \(g(x)\) if \(h(x) = a \cdot f(x) + b \cdot g(x)\) for some constants \(a\) and \(b\).
02

Investigate the Function h(x)

The function \(h(x) = \sin 2x\) is an identity we can express as \(h(x)=2 \sin x \cos x\). This identity is frequently used in trigonometry.
03

Trigonometric Identity Analysis

We know that \(\sin^2 x + \cos^2 x = 1\). In terms of \(f(x)\) and \(g(x)\), this is \(f(x) + g(x) = 1\). These trigonometric forms can help identify other relationships that include \(h(x)\).
04

Express h(x) in Terms of f(x) and g(x)

To express \(h(x) = \sin 2x = 2 \sin x \cos x\) as a linear combination of \(f(x) = \sin^2 x\) and \(g(x) = \cos^2 x\), observe identities like: \(\sin 2x = 2 \sin x \cos x = 1 - \cos 2x\). Hence, \(\sin 2x\) can be derived from the known trigonometric relationships but not directly expressed as \(a \sin^2 x + b \cos^2 x\).
05

Conclusion on h(x) Belonging to Span

Returning to linear combinations, \(h(x)\) cannot be expressed as \(a \cdot \sin^2 x + b \cdot \cos^2 x\) for any real \(a\) and \(b\). While \(h(x)\) is a function of \(\sin x\) and \(\cos x\), it represents a specific product form not achievable by strictly combining squares like in \(\sin^2 x\) and \(\cos^2 x\). Thus, \(h(x)\) is not in the span of \(f(x)\) and \(g(x)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Span of Functions
In mathematics, particularly in linear algebra, the concept of a 'span' is central when talking about functions or vectors. When we speak about the 'span of functions' such as \(f(x) = \sin^2 x\) and \(g(x) = \cos^2 x\), we are referring to all possible linear combinations that can be formed using these functions. A function is said to be within the span if it can be expressed as a combination like \(a\cdot f(x) + b\cdot g(x)\), where \(a\) and \(b\) are constants.

Understanding whether a function, like \(h(x) = \sin 2x\), is in the span of \(f(x)\) and \(g(x)\) requires checking if there's a way to express \(h(x)\) using these constant coefficients of the span's base functions. If no such expression exists, \(h(x)\) is not in the span. For the given exercise, we determined that \(h(x)\) cannot be expressed through \(\sin^2 x\) and \(\cos^2 x\), indicating it doesn't belong to their span.
Trigonometric Identities
Trigonometric identities are equations that involve trigonometric functions and are true for every value of the occurring variables where both sides of the equality are defined. One of the most foundational trigonometric identities is \(\sin^2 x + \cos^2 x = 1\). This identity is handy when you're dealing with problems involving trigonometric functions.

In this specific exercise, another identity is used: \(\sin 2x = 2 \sin x \cos x\). This identity directly relates to \(h(x)\) given in the task and is pivotal in assessing its relationship to \(f(x)\) and \(g(x)\). Recognizing and applying trigonometric identities is key in exploring how different trigonometric expressions relate or how they can be transformed.

Identities like these help not only in transformations but also in simplifications of mathematical expressions, making complex equations much more manageable to solve.
Linear Algebra
Linear algebra is a branch of mathematics that deals with vectors, vector spaces (also known as linear spaces), and linear transformations. Many concepts in linear algebra, such as spans and linear transformations, are not just confined to vectors but can also be extended to functions.

In the context of this exercise, linear combinations of functions \(f(x)\) and \(g(x)\) were tested to see if they could construct \(h(x)\). This mirrors how one would test if a vector lies in a given vector space by checking if it is a linear combination of the space's basis vectors.
  • Linear algebra provides tools for solving problems involving linear equations and systems, plush offers foundational understanding for more complex topics such as differential equations and functional analysis.
  • Understanding these principles helps in many areas, including computer science, physics, and engineering.
In this problem, linear algebraic methods were used to understand why \(h(x)\) was not expressible within the given span, highlighting the function's independence from the span of \(\sin^2 x\) and \(\cos^2 x\).

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Most popular questions from this chapter

Verify that S and T are inverses. \(S: \mathscr{P}_{1} \rightarrow \mathscr{P}_{1}\) defined by \(S(a+b x)=\) \((-4 a+b)+2 a x\) and \(T: \mathscr{P}_{1} \rightarrow \mathscr{P}_{1}\) defined by \\[ T(a+b x)=b / 2+(a+2 b) x \\]

Let \(U\) and \(W\) be subspaces of a finite-dimensional vector space \(V\). Prove Grassmann's Identit \(y:\) \\[ \operatorname{dim}(U+W)=\operatorname{dim} U+\operatorname{dim} W-\operatorname{dim}(U \cap W) \\] [Hint: The subspace \(U+W\) is defined in Exercise 48 of Section 6.1. Let \(\mathcal{B}=\left\\{\mathbf{v}_{1}, \ldots, \mathbf{v}_{k}\right\\}\) be a basis for \(U \cap W .\) Extend \(\mathcal{B}\) to a basis \(\mathcal{C}\) of \(U\) and a basis \(\mathcal{D}\) of \(W\) Prove that \(\mathcal{C} \cup \mathcal{D}\) is a basis for \(U+W\).]

Find a basis for \(\operatorname{span}\left(1-2 x, 2 x-x^{2}, 1-x^{2}, 1+x^{2}\right)\) in \(\mathscr{P}_{2}\).

Extend \(\left\\{\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right],\left[\begin{array}{ll}0 & 1 \\ 1 & 0\end{array}\right]\right\\}\) to a basis for the vector space of symmetric \(2 \times 2\) matrices.

A pendulum consists of a mass, called a \(b o b\), that is affixed to the end of a string of length \(L\) (see Figure 6.24 ). When the bob is moved from its rest position and released, it swings back and forth. The time it takes the pendulum to swing from its farthest right position to its farthest left position and back to its next farthest right position is called the period of the pendulum. Let \(\theta=\theta(t)\) be the angle of the pendulum from the vertical. It can be shown that if there is no resistance, then when \(\theta\) is small it satisfies the differential equation $$\theta^{\prime \prime}+\frac{g}{L} \theta=0$$ where \(g\) is the constant of acceleration due to gravity, approximately \(9.7 \mathrm{m} / \mathrm{s}^{2} .\) Suppose that \(L=1 \mathrm{m}\) and that the pendulum is at rest (i.e., \(\theta=0\) ) at time \(t=0\) second. The bob is then drawn to the right at an angle of \(\theta_{1}\) radians and released. (a) Find the period of the pendulum. (b) Does the period depend on the angle \(\theta_{1}\) at which the pendulum is released? This question was posed and answered by Galileo in \(1638 .\) [Galileo Galilei \((1564-1642)\) studied medicine as a student at the University of Pisa, but his real interest was always mathematics. In \(1592,\) Galileo was appointed professor of mathematics at the University of Padua in Venice, where he taught primarily geometry and astronomy. He was the first to use a telescope to look at the stars and planets, and in so doing, he produced experimental data in support of the Copernican view that the planets revolve around the sun and not the earth. For this, Galileo was summoned before the Inquisition, placed under house arrest, and forbidden to publish his results. While under house arrest, he was able to write up his research on falling objects and pendulums. His notes were smuggled out of Italy and published as Discourses on Two New Sciences in \(1638 .]\)

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