/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Define linear transformations \(... [FREE SOLUTION] | 91Ó°ÊÓ

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Define linear transformations \(S: \mathbb{R}^{2} \rightarrow M_{22}\) and \(T: \mathbb{R}^{2} \rightarrow \mathbb{R}^{2}\) by \(S\left[\begin{array}{l}a \\\ b\end{array}\right]=\left[\begin{array}{cc}a+b & b \\ 0 & a-b\end{array}\right]\) and \(T\left[\begin{array}{c}c \\\ d\end{array}\right]=\left[\begin{array}{c}2 c+d \\ -d\end{array}\right]\) Compute \((S \circ T)\left[\begin{array}{l}2 \\ 1\end{array}\right]\) and \((S \circ T)\left[\begin{array}{l}x \\ y\end{array}\right] .\) Can you compute \((T \circ S)\left[\begin{array}{l}x \\ y\end{array}\right]\) ? If \(s o,\) compute it.

Short Answer

Expert verified
\((S \circ T)(\begin{bmatrix}2 \\ 1\end{bmatrix}) = \begin{bmatrix}4 & -1 \\ 0 & 6\end{bmatrix}\), \((S \circ T)(\begin{bmatrix}x \\ y\end{bmatrix}) = \begin{bmatrix}2x & -y \\ 0 & 2x + 2y\end{bmatrix}\); \((T \circ S)\) is not defined.

Step by step solution

01

Understand the Compositions

The problem asks us to find \((S \circ T)(\begin{bmatrix}2 \ 1\end{bmatrix})\), \((S \circ T)(\begin{bmatrix}x \ y\end{bmatrix})\), and possibly \((T \circ S)(\begin{bmatrix}x \ y\end{bmatrix})\). This means we will apply the transformation \(T\) first, followed by \(S\), and then determine if \((T \circ S)\) is defined and compute it if possible.
02

Compute \(T\) on \(\begin{bmatrix}2 \\ 1\end{bmatrix}\)

Apply the transformation \(T\) to \(\begin{bmatrix}2 \ 1\end{bmatrix}\). According to the definition, \(T\begin{bmatrix}2 \ 1\end{bmatrix} = \begin{bmatrix}2(2) + 1 \ -1\end{bmatrix} = \begin{bmatrix}4 + 1 \ -1\end{bmatrix} = \begin{bmatrix}5 \ -1\end{bmatrix}\).
03

Apply \(S\) to \(T\begin{bmatrix}2 \\ 1\end{bmatrix}\) Result

Now apply \(S\) to the result from Step 2. Compute \(S\begin{bmatrix}5 \ -1\end{bmatrix}\) using the formula for \(S\). \(S\begin{bmatrix}5 \ -1\end{bmatrix} = \begin{bmatrix}(5) + (-1) & -1 \ 0 & (5) - (-1)\end{bmatrix} = \begin{bmatrix}4 & -1 \ 0 & 6\end{bmatrix}\).
04

Compute \(T\) on \(\begin{bmatrix}x \\ y\end{bmatrix}\)

Next, apply the transformation \(T\) to a general vector \(\begin{bmatrix}x \ y\end{bmatrix}\). \(T\begin{bmatrix}x \ y\end{bmatrix} = \begin{bmatrix}2x + y \ -y\end{bmatrix}\).
05

Apply \(S\) to \(T\begin{bmatrix}x \\ y\end{bmatrix}\) Result

Now apply \(S\) to the result from Step 4. Compute \(S\begin{bmatrix}2x+y \ -y\end{bmatrix}\). Using the formula for \(S\), we get \(S\begin{bmatrix}2x+y \ -y\end{bmatrix} = \begin{bmatrix}(2x+y) + (-y) & -y \ 0 & (2x+y) - (-y)\end{bmatrix} = \begin{bmatrix}2x & -y \ 0 & 2x + 2y\end{bmatrix}\).
06

Analyze \((T \circ S)\)

To check if \((T \circ S)\) can be computed, review the domains and codomains of \(S\) and \(T\). \(S\) maps from \(\mathbb{R}^2\) to \(M_{22}\), while \(T\) maps from \(\mathbb{R}^2\) to \(\mathbb{R}^2\). Since \(T\) requires a vector in \(\mathbb{R}^2\) to operate, but \(S\) outputs a matrix in \(M_{22}\), the function \((T \circ S)\) is not defined.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Composition of Functions
When we talk about the composition of functions, we are referring to one function applying its rule to the output of another function. Imagine having two functions, let's say \(f\) and \(g\). The composition \(f \circ g\) means that you first apply \(g\) to an input and then apply \(f\) to the result of \(g\). In other words, it’s a process of feeding the output of \(g\) into \(f\). This concept is crucial when dealing with transformations as it helps create complex operations by merging simpler ones.

In our problem, two linear transformations, \(T\) and \(S\), are composed. The order is significant: which means \(S\) acts on the result of \(T\). It's like two sequential processes—what \(T\) does first changes the way \(S\) operates. Additionally, understanding that the sequence matters showcases two different transformations resulting from different compositions like \((S \circ T)\) and \((T \circ S)\). Here, only \((S \circ T)\) is valid since \(T\) outputs a format suitable for \(S\) to process.

An important takeaway here is that for the composition to be defined, the codomain of the first function should match the domain of the second one.
Matrix Transformations
Matrix transformations are linear transformations represented using matrices. They provide a powerful way to perform operations like rotations, scaling, and translations on vectors. A linear transformation can be expressed as a matrix multiplication. In our problem, the transformation \(S\) is expressed as a 2x2 matrix, which acts upon vector inputs.

What makes matrix transformations so nifty is their ability to encapsulate operations in a linear structure. Any transformation \(T: \mathbb{R}^2 \rightarrow \mathbb{R}^2\) is reduced to a matrix acting on column vectors. Applying transformation \(T\) involves simple matrix-vector multiplication. This ease stems from the fact that each linear transformation is perfectly modeled by a consistent and universal matrix format.

However, for \(S\) defined in our problem, which outputs a matrix in \(M_{22}\), the output takes a different form. This highlights that not all transformations result in vector outputs; they can produce a matrix that alters subsequent applications if allowed.
Function Domains and Codomains
Every function, including those representing transformations, has a domain and a codomain. The domain is the set of possible inputs for the function, while the codomain is essentially the set of potential outputs the function can deliver.

For linear transformations, understanding domains and codomains ensures functions can "connect" correctly in compositions. In our exercise, \(T\) maps from \(\mathbb{R}^2\) to \(\mathbb{R}^2\) which means both its inputs and outputs are vectors in two-dimensional space. On the other hand, transformation \(S\) starts with a similar domain, \(\mathbb{R}^2\), but its outputs are matrices in \(M_{22}\).

The mismatch between the codomain of \(S\) and the domain of \(T\) is why \((T \circ S)\) remains undefined: \(T\) cannot accept matrices as inputs. Emphasizing the matching requirement between the codomain of the first and the domain of the second function in composition is vital to grasping why some compositions are possible while others are not.

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Most popular questions from this chapter

Find either the nullity or the rank of \(T\) and then use the Rank Theorem to find the other. $$T: \mathscr{P}_{2} \rightarrow \mathbb{R} \text { defined by } T(p(x))=p^{\prime}(0)$$

Find either the nullity or the rank of \(T\) and then use the Rank Theorem to find the other. $$T: \mathscr{P}_{2} \rightarrow \mathbb{R} \text { defined by } T(p(x))=p^{\prime}(0)$$

Determine whether the linear transformation T is invertible by considering its matrix with respect to the standard bases. If \(T\) is invertible, use Theorem 6.28 and the method of Example 6.82 to find \(T^{-1}\) \(T: M_{22} \rightarrow M_{22}\) defined by \(T(A)=A B,\) where \\[ B=\left[\begin{array}{ll} 3 & 2 \\ 2 & 1 \end{array}\right] \\]

Let \(T: V \rightarrow W\) be a linear transformation between finite-dimensional vector spaces V and \(\mathrm{W}\) Let \(\mathcal{B}\) and \(\mathcal{C}\) be bases for \(V\) and \(W\), respectively, and let \(A=[T]_{C \leftarrow B}\) Show that \(\operatorname{rank}(T)=\operatorname{rank}(A)\)

The set of all linear transformations from a vector space \(V\) to a vector space \(W\) is denoted \(b y \mathscr{L}(V, W)\). If S and T are in \(\mathscr{L}(V, W),\) we can define the sum \(S+T\) of \(S\) and \(T b y\) \\[ (S+T)(\mathbf{v})=S(\mathbf{v})+T(\mathbf{v}) \\] for all \(\mathbf{v}\) in \(V\). If \(c\) is a scalar, we define the scalar multiple \(c T\) of \(T\) by c to be \\[ (c T)(\mathbf{v})=c T(\mathbf{v}) \\] for all vin \(V\). Then \(S+T\) and \(c\) T are both transformations from \(V\) to \(W\) Prove that \(S+T\) and \(c T\) are linear transformations.

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