Chapter 5: Problem 8
Find the symmetric matrix \(A\) associated with the given quadratic form. $$x_{1} x_{2}$$
Short Answer
Expert verified
The symmetric matrix is \(\begin{pmatrix} 0 & \frac{1}{2} \\ \frac{1}{2} & 0 \end{pmatrix}\).
Step by step solution
01
Understanding the Structure of Quadratic Forms
A quadratic form in two variables, say \(x_1\) and \(x_2\), can be represented in the form: \(Q(x_1, x_2) = ax_1^2 + bx_1x_2 + cx_2^2\). In this problem, the quadratic form is given by \(x_1x_2\).
02
Identify the Coefficients
In the given quadratic form \(x_1x_2\), the coefficient of \(x_1x_2\) is 1. The coefficients of the squared terms, \(x_1^2\) and \(x_2^2\), are 0, since they are not explicitly present in the expression.
03
Construct the Symmetric Matrix
For a symmetric matrix associated with the quadratic form in two variables, \[A = \begin{pmatrix} a & \frac{b}{2} \ \frac{b}{2} & c \end{pmatrix}\] where \(a\), \(b\), and \(c\) are the coefficients of \(x_1^2\), \(x_1x_2\), and \(x_2^2\) respectively. Substituting the values from Step 2, we get:\[A = \begin{pmatrix} 0 & \frac{1}{2} \ \frac{1}{2} & 0 \end{pmatrix}\]
04
Confirm Symmetric Matrix Requirements
A symmetric matrix is such that \(A = A^T\), meaning it is equal to its transpose. The matrix derived in Step 3, \[\begin{pmatrix} 0 & \frac{1}{2} \ \frac{1}{2} & 0 \end{pmatrix}\], is symmetric because its transpose is: \[\begin{pmatrix} 0 & \frac{1}{2} \ \frac{1}{2} & 0 \end{pmatrix}\], which is equal to the original matrix.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic form
A quadratic form is a special type of polynomial where each term is of degree two. In its simplest representation, a quadratic form in two variables, such as \(x_1\) and \(x_2\), can be expressed as:
Understanding the coefficients correctly within the quadratic form is essential to constructing its corresponding symmetric matrix, which helps manipulate and further study such forms easily.
- \(Q(x_1, x_2) = ax_1^2 + bx_1x_2 + cx_2^2\)
- \(a\) is the coefficient of \(x_1^2\).
- \(b\) is the coefficient of \(x_1x_2\) or the cross-product term.
- \(c\) is the coefficient of \(x_2^2\).
Understanding the coefficients correctly within the quadratic form is essential to constructing its corresponding symmetric matrix, which helps manipulate and further study such forms easily.
matrix transpose
Transposing a matrix involves flipping the matrix over its diagonal. This process swaps the matrix's row and column indices. For example, consider a matrix \(A\):
- \(A = \begin{pmatrix} a & b \ c & d \end{pmatrix}\)
- The transpose of \(A\), denoted \(A^T\), is obtained by swapping \(b\) and \(c\):
- \(A^T = \begin{pmatrix} a & c \ b & d \end{pmatrix}\)
- The elements across the diagonal remain unchanged.
- This property can be represented as \(a_{ij} = a_{ji}\), where \(a_{ij}\) and \(a_{ji}\) denote elements of the matrix.
matrix coefficients
Matrix coefficients are the building blocks that tell us about the strength and relationship of the terms represented by the matrix. Consider a quadratic form like \(x_1x_2\), which can be transformed into a symmetric matrix form:
- This transformation involves identifying the coefficients \(a\), \(b\), and \(c\) from the quadratic form \(Q(x_1, x_2) = ax_1^2 + bx_1x_2 + cx_2^2\).
- The diagonal entries correspond to \(a\) and \(c\), representing the coefficients of the squared terms \(x_1^2\) and \(x_2^2\), respectively.
- The off-diagonal entries, which must be identical in a symmetric matrix, are \(\frac{b}{2}\), representing half the coefficient of the cross-product term \(x_1x_2\).
- \(A = \begin{pmatrix} 0 & \frac{1}{2} \ \frac{1}{2} & 0 \end{pmatrix}\)