Chapter 5: Problem 22
Find a symmetric \(2 \times 2\) matrix with eigenvalues \(\lambda_{1}\) and \(\lambda_{2}\) and corresponding orthogonal eigenvectors \(\mathbf{v}_{1}\) and \(\mathbf{v}_{2}\) $$\lambda_{1}=3, \lambda_{2}=-3, \mathbf{v}_{1}=\left[\begin{array}{l} 1 \\ 2 \end{array}\right], \mathbf{v}_{2}=\left[\begin{array}{r} -2 \\ 1 \end{array}\right]$$
Short Answer
Step by step solution
Understanding Symmetric Matrices and Eigenvectors
Construct the Diagonal Matrix D
Form the Matrix of Eigenvectors P
Calculate the Matrix A
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eigenvalues
- Here, \( A \) is a square matrix, \( \lambda \) is the eigenvalue, and \( \mathbf{v} \) is the eigenvector.
- Finding eigenvalues involves solving the characteristic polynomial, which is derived from the determinant equation \( \det(A - \lambda I) = 0 \).
- For symmetric matrices, eigenvalues are always real, which simplifies computations.
Eigenvectors
- Eigenvectors represent directions in which the transformation \( A \) stretches.
- For a symmetric matrix, eigenvectors can be chosen to be orthogonal, meaning they meet at right angles.
- They offer insights into the matrix's structure and are useful in tasks like diagonalization and decompositions.
Orthogonal Matrices
- Orthogonal matrices have the property that their transpose is also their inverse. Thus, \( Q^TQ = QQ^T = I \).
- When multiplying an orthogonal matrix by its transpose, the result is the identity matrix. This highlights their role in transformation preserving lengths and angles.
- Orthogonal matrices maintain numerical stability in computations and preserve the dot product.
Matrix Multiplication
- The number of columns in the first matrix must match the number of rows in the second matrix.
- The resulting matrix has dimensions of the outer dimensions of the two matrices (i.e., rows of the first matrix by columns of the second).
- Matrix multiplication is associative, \((AB)C = A(BC)\), but not commutative, \(AB eq BA\).