Chapter 4: Problem 26
Find the companion matrix of \(p(x)=x^{2}-7 x+12\) and then find the characteristic polynomial of \(C(p)\).
Short Answer
Expert verified
The characteristic polynomial of the companion matrix is \( \lambda^2 - 7\lambda + 12 \), which matches \( p(x) \).
Step by step solution
01
Define the Characteristic Polynomial
The characteristic polynomial given is \( p(x) = x^2 - 7x + 12 \). This polynomial is of degree 2, which means our companion matrix will be a 2x2 matrix.
02
Construct the Companion Matrix
The companion matrix \( C(p) \) for a polynomial \( p(x) = x^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0 \) is given by: \[C(p) = \begin{bmatrix} 0 & 1 \ -a_0 & -a_1 \end{bmatrix}\]For \( p(x) = x^2 - 7x + 12 \), the coefficients are \( a_1 = -7 \) and \( a_0 = 12 \). Plugging these into the matrix gives:\[C(p) = \begin{bmatrix} 0 & 1 \ -12 & 7 \end{bmatrix}\]
03
Calculate the Characteristic Polynomial of the Companion Matrix
To find the characteristic polynomial, we need to compute the determinant of \( \lambda I - C(p) \), where \( I \) is the identity matrix and \( \lambda \) is a variable. Thus, \[\lambda I - C(p) = \begin{bmatrix} \lambda & 0 \ 0 & \lambda \end{bmatrix} - \begin{bmatrix} 0 & 1 \ -12 & 7 \end{bmatrix} = \begin{bmatrix} \lambda & -1 \ 12 & \lambda - 7 \end{bmatrix}\]The determinant is:\(\det(\lambda I - C(p)) = \lambda(\lambda - 7) - (-1)(12)= \lambda^2 - 7\lambda + 12\) This is the characteristic polynomial of \( C(p) \), which is the same as \( p(x) \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Characteristic Polynomial
A characteristic polynomial is an essential concept in linear algebra and is associated with a square matrix. It is a polynomial that provides significant insights into the properties of the matrix, such as its eigenvalues. The characteristic polynomial of a matrix is often instrumental for determining whether a matrix is diagonalizable or invertible, among other properties.
In practice, to find the characteristic polynomial of a matrix, we calculate the determinant of the matrix \( \,\lambda I - A \)\, where \( \,I \)\ is the identity matrix and \( \,A \)\ is the matrix for which we are finding the characteristic polynomial. The variable \( \,\lambda \) represents a scalar that is being subtracted from the diagonal of the matrix. The result is a polynomial where the degree corresponds to the size of the matrix.
For example, consider the polynomial \( p(x) = x^2 - 7x + 12 \). When tasked to find the characteristic polynomial of a corresponding companion matrix, we ultimately find that it matches the original polynomial \( p(x) \). This consistent match is a defining feature when dealing with companion matrices.
In practice, to find the characteristic polynomial of a matrix, we calculate the determinant of the matrix \( \,\lambda I - A \)\, where \( \,I \)\ is the identity matrix and \( \,A \)\ is the matrix for which we are finding the characteristic polynomial. The variable \( \,\lambda \) represents a scalar that is being subtracted from the diagonal of the matrix. The result is a polynomial where the degree corresponds to the size of the matrix.
For example, consider the polynomial \( p(x) = x^2 - 7x + 12 \). When tasked to find the characteristic polynomial of a corresponding companion matrix, we ultimately find that it matches the original polynomial \( p(x) \). This consistent match is a defining feature when dealing with companion matrices.
Companion Matrix Construction
Constructing a companion matrix is a systematic approach used to represent a polynomial equation as a matrix. This construction is valuable because it allows us to analyze polynomials using linear algebraic methods.
To construct a companion matrix for a polynomial \( p(x) = x^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0 \), we use a specific pattern:
\[ C(p) = \begin{bmatrix} 0 & 1 \ -12 & 7 \end{bmatrix} \]
This transformation turns the polynomial \( p(x) \) into a matrix form, helping us employ matrix operations to better understand its properties.
To construct a companion matrix for a polynomial \( p(x) = x^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0 \), we use a specific pattern:
- The first row contains all zeros except for a single 1 in the second column.
- Each subsequent row below the first contains a 1 in the column directly left of the 1 above it, forming an identity block structure.
- The last row consists of the negated coefficients of the polynomial except for the leading coefficient.
\[ C(p) = \begin{bmatrix} 0 & 1 \ -12 & 7 \end{bmatrix} \]
This transformation turns the polynomial \( p(x) \) into a matrix form, helping us employ matrix operations to better understand its properties.
Degree of Polynomial
The degree of a polynomial is the highest power of the variable within the expression, and it is a key attribute that defines its behavior and solutions.
In the polynomial \( p(x) = x^2 - 7x + 12 \), we observe that it has a degree of 2, indicated by the term \( x^2 \). This degree tells us valuable information about the polynomial, such as:
In the polynomial \( p(x) = x^2 - 7x + 12 \), we observe that it has a degree of 2, indicated by the term \( x^2 \). This degree tells us valuable information about the polynomial, such as:
- The shape of its graph, which is a parabola since it is of degree 2.
- The maximum number of solutions or roots it can have, which in this case is 2.
- The dimension of the companion matrix, which will also be a 2\times2 matrix, reflecting the polynomial's degree.
Determinant Calculation
Determinant calculation is an important process in linear algebra, especially in relation to matrices. The determinant is a scalar value that provides a wealth of information about the matrix, including whether it's invertible or singular.
When calculating the determinant to find the characteristic polynomial of a companion matrix like \( C(p) \), we first set up the matrix \( \lambda I - C(p) \), where \( \lambda \) is a variable. The identity matrix \( I \) has the same dimensions as \( C(p) \). For the given matrix:
\[ \lambda I - C(p) = \begin{bmatrix} \lambda & -1 \ 12 & \lambda - 7 \end{bmatrix} \]
We compute the determinant by multiplying the diagonal elements and subtracting the product of the off-diagonal elements:
\( \det(\lambda I - C(p)) = \lambda(\lambda - 7) - (-1)(12) \)
This simplifies to:
\( \lambda^2 - 7\lambda + 12 \)
Ultimately, through determinant calculation, we've derived the characteristic polynomial, illustrating a core connection between polynomial and matrix algebra.
When calculating the determinant to find the characteristic polynomial of a companion matrix like \( C(p) \), we first set up the matrix \( \lambda I - C(p) \), where \( \lambda \) is a variable. The identity matrix \( I \) has the same dimensions as \( C(p) \). For the given matrix:
\[ \lambda I - C(p) = \begin{bmatrix} \lambda & -1 \ 12 & \lambda - 7 \end{bmatrix} \]
We compute the determinant by multiplying the diagonal elements and subtracting the product of the off-diagonal elements:
\( \det(\lambda I - C(p)) = \lambda(\lambda - 7) - (-1)(12) \)
This simplifies to:
\( \lambda^2 - 7\lambda + 12 \)
Ultimately, through determinant calculation, we've derived the characteristic polynomial, illustrating a core connection between polynomial and matrix algebra.