Chapter 4: Problem 12
Compute (a) the characteristic polynomial of \(A,(b)\) the eigenvalues of \(A,(c)\) a basis for each eigenspace of \(A,\) and (d) the algebraic and geometric multiplicity of each eigenvalue. $$A=\left[\begin{array}{llll} 4 & 0 & 1 & 0 \\ 0 & 4 & 1 & 1 \\ 0 & 0 & 1 & 2 \\ 0 & 0 & 3 & 0 \end{array}\right]$$
Short Answer
Step by step solution
Find the Characteristic Polynomial
Find the Eigenvalues
Find a Basis for Each Eigenspace
Determine Algebraic and Geometric Multiplicity
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Characteristic Polynomial
This polynomial helps in identifying the eigenvalues of a matrix as they are the roots of this polynomial. For example, if you have a matrix \(A\) and find \(A - \lambda I\), you subtract \(\lambda\) from each diagonal element of \(A\) to get the new matrix. Finding the determinant of this matrix yields a polynomial in \(\lambda\).
- The degree of the characteristic polynomial matches the dimension of the square matrix \(A\).
- Solutions to the polynomial, i.e., values of \(\lambda\) that make the polynomial zero, are the eigenvalues of \(A\).
- In our specific case, the polynomial is \(\lambda^4 - 9\lambda^3 + 28\lambda^2 - 36\lambda + 18\).
Eigenspace
To find the eigenspace, one must solve the equation \((A - \lambda I)\mathbf{v} = \mathbf{0}\).
- This equation is a homogeneous system of linear equations.
- The solutions to this system form a vector space, called the eigenspace.
- The eigenspace is spanned by the basis vectors that solve this equation.
Algebraic Multiplicity
- Each eigenvalue may have a different algebraic multiplicity.
- An eigenvalue that appears twice is said to have an algebraic multiplicity of 2.
Geometric Multiplicity
- A geometric multiplicity of 1 means there is only one independent direction in the eigenspace.
- If the geometric multiplicity is less than the algebraic multiplicity, the matrix does not have enough independent eigenvectors to diagonalize it.