Chapter 1: Problem 21
Find the vector form of the equation of the line in \(\mathbb{R}^{2}\) that passes through \(P=(2,-1)\) and is parallel to the line with general equation \(2 x-3 y=1\).
Short Answer
Expert verified
The vector form of the line is \(\mathbf{r}(t) = (2 + 3t, -1 + 2t)\).
Step by step solution
01
Rewrite the given line equation in slope-intercept form
To find a line parallel to the given line, first rewrite the equation \(2x - 3y = 1\) in the form \(y = mx + b\), where \(m\) is the slope. Start by solving for \(y\):\[ 3y = 2x - 1 \]\[ y = \frac{2}{3}x - \frac{1}{3} \]The slope of the given line is \(\frac{2}{3}\).
02
Determine the direction vector
A parallel line will have the same slope, hence the same direction. For a line in slope-intercept form \(y = mx + b\), the direction vector corresponding to the slope \(\frac{2}{3}\) is \(\mathbf{d} = (3, 2)\). This is because the slope is the ratio of the change in \(y\) to the change in \(x\), i.e., \(m = \frac{\Delta y}{\Delta x} = \frac{2}{3}\).
03
Use the point-direction form to write the vector equation
With the direction vector \(\mathbf{d} = (3, 2)\) and the given point \(P = (2, -1)\), the vector form of the line can be written using the point-direction form of the line equation: \[ \mathbf{r}(t) = \mathbf{p} + t\mathbf{d} \]Here, \(\mathbf{p} = (2, -1)\) and \(\mathbf{d} = (3, 2)\), hence:\[ \mathbf{r}(t) = (2, -1) + t(3, 2) \]
04
Express the vector equation explicitly
The explicit vector notation of the line is:\[ \mathbf{r}(t) = (2 + 3t, -1 + 2t) \]This represents the set of all points \((x, y)\) such that the line passes through \((2, -1)\) and moves in the direction \(\mathbf{d} = (3, 2)\) as \(t\) varies over all real numbers.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form of a linear equation is a popular method for expressing straight lines. You may often see this formula written as \( y = mx + b \). Here, \( m \) represents the slope of the line, while \( b \) is the y-intercept, or the point where the line crosses the y-axis.
The slope \( m \) tells us how steep the line is. It's calculated as the "rise over run," or the change in y divided by the change in x between any two points on the line.
The slope \( m \) tells us how steep the line is. It's calculated as the "rise over run," or the change in y divided by the change in x between any two points on the line.
- A positive slope means the line ascends from left to right.
- A negative slope means the line descends from left to right.
- A zero slope indicates a horizontal line.
- An undefined slope suggests a vertical line.
Direction Vector
A direction vector provides essential information about the direction and angle a line takes. In the context of a vector equation, it describes the orientation of a line in space. When given a slope, you can derive the direction vector by considering the slope as a fraction \( m = \frac{\Delta y}{\Delta x} \), where \( \Delta y \) is the change in the y-coordinate, and \( \Delta x \) is the change in the x-coordinate.
For example, if the slope of a line is \( \frac{2}{3} \), the corresponding direction vector could be \( (3, 2) \). This vector indicates how you move to create the path of the line.
For example, if the slope of a line is \( \frac{2}{3} \), the corresponding direction vector could be \( (3, 2) \). This vector indicates how you move to create the path of the line.
- The x-component (3) suggests moving three units horizontally.
- The y-component (2) indicates moving two units vertically.
Point-Direction Form
In vector mathematics, the point-direction form provides a comprehensive way to express the vector equation of a line. This form utilizes both a point through which the line passes and a direction vector, which defines how the line extends.
The formula to represent this is: \( \mathbf{r}(t) = \mathbf{p} + t\mathbf{d} \), where:
Using the point-direction form can help in multiple calculations in geometry and physics, allowing us to solve problems involving paths, trajectories, and line intersections efficiently.
The formula to represent this is: \( \mathbf{r}(t) = \mathbf{p} + t\mathbf{d} \), where:
- \( \mathbf{p} \) is a fixed point on the line, given as an ordered pair.
- \( t \) is a real number parameter that scales the direction vector.
- \( \mathbf{d} \) is the direction vector, dictating the line's slope and orientation.
Using the point-direction form can help in multiple calculations in geometry and physics, allowing us to solve problems involving paths, trajectories, and line intersections efficiently.