Chapter 7: Problem 14
Determine which of the four inner product axioms do not hold. Give a specific example in each case. $$\begin{aligned}&\text { Let } \mathbf{u}=\left[\begin{array}{l}u_{1} \\\u_{2}\end{array}\right] \text { and } \mathbf{v}=\left[\begin{array}{l}v_{1} \\\v_{2}\end{array}\right] \text { in } \mathrm{R}^{2} \text { . Define }\\\&\langle\mathbf{u}, \mathbf{v}\rangle=u_{1} v_{1}-u_{2} v_{2} \end{aligned}$$
Short Answer
Step by step solution
Review Inner Product Axioms
Check Linearity in the First Argument
Check Commutativity
Check Positivity
Confirm Scalar Multiplication Axiom
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linearity
\[ \langle a \mathbf{x} + b \mathbf{y}, \mathbf{z} \rangle = a \langle \mathbf{x}, \mathbf{z} \rangle + b \langle \mathbf{y}, \mathbf{z} \rangle \]
Here, \( a \) and \( b \) are scalars. This axiom ensures that the process respects scalar multiplication and addition within the vector space. By checking the provided example, the definition of the inner product as \( u_1 w_1 - u_2 w_2 \) holds under this axiom. This shows how the inner product definition here respects linearity in its operations effectively.
Commutativity
\[ \langle \mathbf{x}, \mathbf{y} \rangle = \langle \mathbf{y}, \mathbf{x} \rangle \]
This property is crucial for ensuring the symmetry of the inner product operation. In the example exercise, the inner product is defined as \( u_1 v_1 - u_2 v_2 \). Testing with vectors \( \mathbf{u} \) and \( \mathbf{v} \), the expressions \( \langle \mathbf{u}, \mathbf{v} \rangle \) and \( \langle \mathbf{v}, \mathbf{u} \rangle \) yield the same result. Therefore, the commutative property is upheld, ensuring a symmetrical result when the vectors are switched.
Positivity
\[ \langle \mathbf{x}, \mathbf{x} \rangle \geq 0 \]
Moreover, if \( \langle \mathbf{x}, \mathbf{x} \rangle = 0 \), then \( \mathbf{x} \) must be a zero vector. This axiom asserts that the inner product measures a kind of ‘magnitude’, similar to distance or length, and therefore should not be negative. In the given exercise, positivity fails since using the vector \( \mathbf{u} = \begin{bmatrix} 1 \ 2 \end{bmatrix} \), we find \( \langle \mathbf{u}, \mathbf{u} \rangle = -3 \), which is negative. This violates the positivity axiom, indicating that the provided inner product definition might have limitations with this property.
Scalar Multiplication
\[ \langle c \mathbf{x}, \mathbf{y} \rangle = c \langle \mathbf{x}, \mathbf{y} \rangle \]
Where \( c \) is a scalar. This means when a vector in one of the arguments is multiplied by a scalar, the entire inner product is proportionately scaled. In the example problem, both expressions of \( \langle c \mathbf{u}, \mathbf{v} \rangle \) and \( c \langle \mathbf{u}, \mathbf{v} \rangle \) yield identical results, affirming this property holds true for the given vectors. These elements enable a consistent and predictable scaling behavior in linear algebra within inner product spaces.