Chapter 4: Problem 89
Find an invertible matrix Pand a matrix \(C\) of the form \(C=\left[\begin{array}{cr}a & -b \\ b & a\end{array}\right]\) such that \(A=P C P^{-1}\) Sketch the first six points of the trajectory for the dynamical system \(\mathbf{x}_{\mathrm{k}+1}=A \mathbf{x}_{\mathrm{k}}\) with \(\mathbf{x}_{0}=\left[\begin{array}{l}1 \\ 1\end{array}\right]\) and classify the origin as \(a\) spiral attractor, spiral repeller, or orbital center $$A=\left[\begin{array}{rr} 0.1 & -0.2 \\ 0.1 & 0.3 \end{array}\right]$$
Short Answer
Step by step solution
Find Eigenvalues of Matrix A
Solve the Characteristic Equation
Calculate the Eigenvalues
Form Matrix C
Find Eigenvectors of A
Construct Matrix P
Verify Similarity Transformation
Sketch the Trajectory of the Dynamical System
Classification of the Origin
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Eigenvalues and Eigenvectors
- \( A \) is a square matrix,
- \( \mathbf{v} \) represents an eigenvector,
- and \( \lambda \) is the corresponding eigenvalue.
Invertible Matrices
- \( A \) is the original matrix,
- \( P \) is the inverse of matrix \( A \),
- and \( I \) is the identity matrix.
Dynamical Systems
- The matrix \( A \) governs the dynamics by applying transformations to the current state vector \( \mathbf{x}_k \).
- The complex eigenvalues of \( A \) suggest a spiral trajectory, indicating rotational behavior.
- By iterating the matrix multiplication, you can find and sketch successive states, which helps in classifying the system's behavior.
Characteristic Polynomial
- It describes oscillatory modes in physics and engineering thanks to its complex roots.
- The solutions provide vital information about the stability and type of the dynamical system.
- Helps in constructing matrix \( C \), particularly due to its requirement for similar matrices sharing eigenvalues.