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Show that \(A\) and \(B\) are not similar matrices. $$A=\left[\begin{array}{ll} 1 & 2 \\ 3 & 4 \end{array}\right], B=\left[\begin{array}{rr} 2 & -5 \\ -2 & 4 \end{array}\right]$$

Short Answer

Expert verified
Matrices \(A\) and \(B\) are not similar because their traces differ.

Step by step solution

01

Define Similarity of Matrices

Two matrices \(A\) and \(B\) are similar if there exists an invertible matrix \(P\) such that \(A = PBP^{-1}\). A necessary condition for similarity is that both matrices have the same determinant, trace, and eigenvalues.
02

Calculate Determinant of Matrix A

To find the determinant of matrix \(A\), use the formula for a 2x2 matrix: \( \det(A) = ad - bc \). For matrix \(A\):\[ A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \]\[ \det(A) = (1)(4) - (2)(3) = 4 - 6 = -2 \]
03

Calculate Determinant of Matrix B

Similarly, calculate the determinant of matrix \(B\):\[ B = \begin{bmatrix} 2 & -5 \ -2 & 4 \end{bmatrix} \]\[ \det(B) = (2)(4) - (-5)(-2) = 8 - 10 = -2 \]
04

Calculate Trace of Matrix A

The trace of a matrix is the sum of its diagonal elements. For matrix \(A\):\[ \text{Trace}(A) = 1 + 4 = 5 \]
05

Calculate Trace of Matrix B

Calculate the trace of matrix \(B\):\[ \text{Trace}(B) = 2 + 4 = 6 \]
06

Compare Determinant and Trace

Both matrices \(A\) and \(B\) have the same determinant, \(-2\), but their traces are different. Trace of \(A\) is 5 and trace of \(B\) is 6.
07

Conclude Non-Similarity

Since the traces of matrices \(A\) and \(B\) are different, they cannot be similar, as similarity requires matching traces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Determinant
The determinant of a matrix is a special number that can be calculated for square matrices. It is useful in many areas of linear algebra such as systems of linear equations, and finding eigenvalues. For a 2x2 matrix, the determinant is calculated using the formula \(\det(A) = ad - bc\), where \(a\), \(b\), \(c\), and \(d\) are the elements of the matrix.

The determinant gives us important information about the matrix, such as whether it is invertible. If the determinant is zero, then the matrix does not have an inverse. For the matrices \(A\) and \(B\) given in the exercise, both share the same determinant value of -2, indicating they both have full rank and are invertible. However, matching determinants alone don't assure similarity.
Trace
The trace of a matrix is the sum of the entries on its main diagonal. It is another attribute used to determine some key properties of matrices.

The trace gives insights into the eigenvalues of the matrix, as it is equal to the sum of its eigenvalues. For our matrices \(A\) and \(B\), matrix \(A\) has a trace of 5, while matrix \(B\) has a trace of 6.

Because these traces differ, \(A\) and \(B\) cannot be similar, since similarity requires equal sums of eigenvalues, which in turn means equal traces. This makes checking the trace a quick test for matrix similarity.
Similar Matrices
Two matrices are deemed similar if you can transform one into the other using an invertible matrix \(P\), expressed as \(A = PBP^{-1}\). Similar matrices shed light on how geometric transformations can be equivalent even if they initially appear different.

For similarity, it is essential that matrices share three attributes:
  • Determinant
  • Trace
  • Eigenvalues
For matrices in the example, although the determinants align, the trace does not. Therefore, matrices \(A\) and \(B\) are ruled out from being similar.

The resemblance in determinant isn't enough; trace and eigenvalues too must mirror each other, ensuring that all intrinsic structural properties match.
Eigenvalues
Eigenvalues are the special numbers associated with a matrix, which provide vital insights into its properties. They are parts of the solutions to the characteristic equation \(\det(A - \lambda I) = 0\), where \(I\) is the identity matrix, and \(\lambda\) symbolizes the eigenvalues.

Eigenvalues are connected to both the determinant and the trace of the matrix. The determinant is the product of the eigenvalues, and the trace is their sum. This implies that if two matrices are similar, not only will their determinants and traces be equivalent, but so will their eigenvalues.

In our example, although we haven't explicitly computed the eigenvalues, the trace already indicates a discrepancy, thus suggesting differing eigenvalues and confirming the non-similarity of matrices \(A\) and \(B\). Eigenvalues offer a deeper view of the transformations a matrix represents.

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Most popular questions from this chapter

Find the general solution to the given system of differential equations. Then find the specific solution that satisfies the initial conditions. (Consider all functions to be functions of \(t .\) $$\begin{array}{ll} y_{1}^{\prime}=y_{1}-y_{2}, & y_{1}(0)=1 \\ y_{2}^{\prime}=y_{1}+y_{2}, & y_{2}(0)=1 \end{array}$$

Find the general solution to the given system of differential equations. Then find the specific solution that satisfies the initial conditions. (Consider all functions to be functions of \(t .\) $$\begin{array}{ll} x_{1}^{\prime}=x_{1}+x_{2}, & x_{1}(0)=1 \\ x_{2}^{\prime}=x_{1}-x_{2}, & x_{2}(0)=0 \end{array}$$

Calculate the positive eigenvalue and \(a\) corresponding positive eigenvector of the Leslie matrix \(L\) $$L=\left[\begin{array}{lll} 0 & 7 & 4 \\ 0.5 & 0 & 0 \\ 0 & 0.5 & 0 \end{array}\right]$$

Species \(X\) preys on species \(Y\). The sizes of the populations are represented by \(x=x(t)\) and \(y=y(t)\) The growth rate of each population is governed by the system of differential equations \(\mathbf{x}^{\prime}=A \mathbf{x}+\mathbf{b},\) where \(\mathbf{x}=\left[\begin{array}{l}x \\\ y\end{array}\right]\) and \(\mathbf{b}\) is a constant vector. Determine what happens to the two populations for the given A and b and initial conditions \(\mathbf{x}(0)\). (First show that there are constants a and \(b\) such that the substitutions \(x=u+a\) and \(y=v+b\) convert the system into an equivalent one with no constant terms.) $$A=\left[\begin{array}{rr} -1 & 1 \\ -1 & -1 \end{array}\right], \mathbf{b}=\left[\begin{array}{r} 0 \\ 40 \end{array}\right], \mathbf{x}(0)=\left[\begin{array}{l} 10 \\ 30 \end{array}\right]$$

Many species of seal have suffered from commercial hunting. They have been killed for their skin, blubber, and meat. The fur trade, in particular, reduced some seal populations to the point of extinction. Today, the greatest threats to seal populations are decline of fish stocks due to overfishing, pollution, disturbance of habitat, entanglement in marine debris, and culling by fishery owners. Some seals have been declared endangered species; other species are carefully managed. Table 4.7 gives the birth and survival rates for the northern fur seal, divided into 2 -year age classes. [The data are based on A. E. York and J. R. Hartley, "Pup Production Following Harvest of Female Northern Fur Seals," Canadian Journal of Fisheries and Aquatic Science, \(38(1981),\) pp. \(84-90 .\) $$\begin{array}{ccc} \text { Age (years) } & \text { Birth Rate } & \text { Survival Rate } \\ \hline 0-2 & 0.00 & 0.91 \\ 2-4 & 0.02 & 0.88 \\ 4-6 & 0.70 & 0.85 \\ 6-8 & 1.53 & 0.80 \\ 8-10 & 1.67 & 0.74 \\ 10-12 & 1.65 & 0.67 \\ 12-14 & 1.56 & 0.59 \\ 14-16 & 1.45 & 0.49 \\ 16-18 & 1.22 & 0.38 \\ 18-20 & 0.91 & 0.27 \\ 20-22 & 0.70 & 0.17 \\ 22-24 & 0.22 & 0.15 \\ 24-26 & 0.00 & 0.00 \end{array}$$ (a) Construct the Leslie matrix \(L\) for these data and compute the positive eigenvalue and a corresponding positive eigenvector. (b) In the long run, what percentage of seals will be in each age class and what will the growth rate be?

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