Chapter 1: Problem 30
Let \(A=(-3,2), B=(1,0),\) and \(C=(4,6) .\) Prove that \(\Delta A B C\) is a right- angled triangle.
Short Answer
Expert verified
Triangle ABC is right-angled at B.
Step by step solution
01
Calculate the Distance AB
The distance between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by the formula \( \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \). For points \(A(-3,2)\) and \(B(1,0)\), this becomes: \[ AB = \sqrt{(1 - (-3))^2 + (0 - 2)^2} = \sqrt{4^2 + (-2)^2} = \sqrt{16 + 4} = \sqrt{20} = 2\sqrt{5}. \]
02
Calculate the Distance BC
For points \(B(1,0)\) and \(C(4,6)\), use the distance formula: \[ BC = \sqrt{(4 - 1)^2 + (6 - 0)^2} = \sqrt{3^2 + 6^2} = \sqrt{9 + 36} = \sqrt{45} = 3\sqrt{5}. \]
03
Calculate the Distance CA
For points \(C(4,6)\) and \(A(-3,2)\), the distance is: \[ CA = \sqrt{(4 - (-3))^2 + (6 - 2)^2} = \sqrt{7^2 + 4^2} = \sqrt{49 + 16} = \sqrt{65}. \]
04
Check the Pythagorean Theorem
To confirm that triangle \(ABC\) is right-angled, check if the square of the longest side equals the sum of the squares of the other two sides. The lengths are \(2\sqrt{5}, 3\sqrt{5},\) and \(\sqrt{65}\). Check if: \[ (CA)^2 = (AB)^2 + (BC)^2 \] \[ 65 = (2\sqrt{5})^2 + (3\sqrt{5})^2 = 4\times5 + 9\times5 = 20 + 45 = 65. \] Since the Pythagorean theorem holds, \(\triangle ABC\) is a right-angled triangle.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Distance Formula
The distance formula is a useful tool in geometry for determining the distance between two points on a plane. Given two points with coordinates
For example, to find the distance between points \(A(-3,2)\) and \(B(1,0)\), calculate:
- \((x_1, y_1)\)
- \((x_2, y_2)\)
For example, to find the distance between points \(A(-3,2)\) and \(B(1,0)\), calculate:
- Horizontal distance: \(1 - (-3) = 4\)
- Vertical distance: \(0 - 2 = -2\)
Pythagorean Theorem
The Pythagorean theorem is a fundamental principle in geometry. It asserts that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. This relationship is expressed by the equation:\[c^2 = a^2 + b^2\]Consider triangle \(\Delta ABC\), where the sides are measured as follows:
- \(AB = 2\sqrt{5}\)
- \(BC = 3\sqrt{5}\)
- \(CA = \sqrt{65}\)
- Calculate \((2\sqrt{5})^2 + (3\sqrt{5})^2 = 20 + 45 = 65\)
- Compare it to \((\sqrt{65})^2 = 65\)
Coordinate Geometry
Coordinate geometry, also known as analytic geometry, connects algebra and geometry using a coordinate system. This fusion allows us to solve geometric problems algebraically. A coordinate system represents points using pairs of numbers containing coordinates such as
Using this method, we can calculate distances, midpoints, and more using algebraic formulas. In our exercise:
- \((x,y)\)
Using this method, we can calculate distances, midpoints, and more using algebraic formulas. In our exercise:
- Points \(A, B, C\) have coordinates \(A(-3,2)\), \(B(1,0)\), and \(C(4,6)\).
- This setup helps us to apply the distance formula to find lengths of triangle sides \(AB\), \(BC\), and \(CA\).
- Both the distance formula and the Pythagorean Theorem are rooted in coordinate geometry.