Chapter 1: Problem 12
In Exercises 11 and \(12,\) give the vector equation of the line passing through \(P\) and \(Q\) $$P=(4,-1,3), Q=(2,1,3)$$
Short Answer
Expert verified
The vector equation is \(\mathbf{r}(t) = (4 - 2t, -1 + 2t, 3)\).
Step by step solution
01
Identify Direction Vector
To find the vector equation of a line, first determine the direction vector, which is the vector from point \(P\) to point \(Q\). This is calculated as \(\overrightarrow{PQ} = Q - P = (2, 1, 3) - (4, -1, 3) = (2 - 4, 1 - (-1), 3 - 3) = (-2, 2, 0)\).
02
Write Vector Equation Template
The vector equation of a line can be written in the form \(\mathbf{r} = \mathbf{a} + t \mathbf{b}\), where \(\mathbf{a}\) is a point on the line and \(\mathbf{b}\) is the direction vector. Here, we can use \(P\) as the point on the line: \((4, -1, 3)\).
03
Substitute into Equation
Substitute point \(P = (4, -1, 3)\) and direction vector \(\overrightarrow{PQ} = (-2, 2, 0)\) into the vector equation template: \(\mathbf{r} = (4, -1, 3) + t(-2, 2, 0)\), where \(t\) is a scalar parameter.
04
Write Final Vector Equation
Simplify the expression to complete the vector equation: \(\mathbf{r}(t) = (4 - 2t, -1 + 2t, 3)\). This represents the line in vector form passing through points \(P\) and \(Q\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Direction Vector
When dealing with vectors and lines, a direction vector plays a key role. It is essentially a vector that indicates the direction in which a line is pointing. The direction vector is derived from two points on a line. By subtracting the coordinates of the initial point from those of the terminal point, you get the direction vector.
For instance, given two points, \( P = (4, -1, 3) \) and \( Q = (2, 1, 3) \), the direction vector \( \overrightarrow{PQ} \) is calculated as follows:
For instance, given two points, \( P = (4, -1, 3) \) and \( Q = (2, 1, 3) \), the direction vector \( \overrightarrow{PQ} \) is calculated as follows:
- Subtract the coordinates of \( P \) from \( Q \): \( (2 - 4, 1 - (-1), 3 - 3) \).
- This results in the vector \( (-2, 2, 0) \).
Scalar Parameter
In the context of vector equations of a line, the scalar parameter is typically denoted by \( t \). This variable gives you the flexibility to represent all the points on the line by substituting different values.
The vector equation can be expressed as \( \mathbf{r} = \mathbf{a} + t \mathbf{b} \), where:
The vector equation can be expressed as \( \mathbf{r} = \mathbf{a} + t \mathbf{b} \), where:
- \( \mathbf{a} \) is a known point on the line.
- \( \mathbf{b} \) is the direction vector.
- When \( t = 0 \), you find yourself at \( \mathbf{a} \), the starting point of the line.
- As \( t \) changes, different points along the line are obtained, moving in the direction of \( \mathbf{b} \).
Line Through Two Points
The vector equation of a line provides a straightforward method to describe a line through two points in space. When you have two points, you inherently establish a line that connects them.
For instance, you are given the points \( P = (4, -1, 3) \) and \( Q = (2, 1, 3) \). To form the vector equation of the line:
\[ \mathbf{r}(t) = (4, -1, 3) + t(-2, 2, 0) \]
This equation concisely represents all points on the line determined by moving from the point \( P \) in the orientation and magnitude specified by the direction vector, through varying \( t \). It's a powerful illustration of connecting algebraic calculations with geometric visualization.
For instance, you are given the points \( P = (4, -1, 3) \) and \( Q = (2, 1, 3) \). To form the vector equation of the line:
- The starting point on the line, \( \mathbf{a} \), can be point \( P \).
- You use the direction vector \( \overrightarrow{PQ} = (-2, 2, 0) \) derived from \( P \) and \( Q \).
\[ \mathbf{r}(t) = (4, -1, 3) + t(-2, 2, 0) \]
This equation concisely represents all points on the line determined by moving from the point \( P \) in the orientation and magnitude specified by the direction vector, through varying \( t \). It's a powerful illustration of connecting algebraic calculations with geometric visualization.