/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Let \(T: V \rightarrow W\) be a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(T: V \rightarrow W\) be a linear transformation between finite-dimensional vector spaces \(V\) and \(W\). Let \(\mathcal{B}\) and \(\mathcal{C}\) be bases for \(V\) and \(W\), respectively, and let \(A=[T]_{C+B}\). If \(V=W\) and \(\mathcal{B}=\mathcal{C},\) show that \(T\) is diagonalizable if and only if \(A\) is diagonalizable.

Short Answer

Expert verified
T and A are diagonalizable if and only if they share a basis of eigenvectors.

Step by step solution

01

Define Diagonalizability

A linear transformation or a matrix is called diagonalizable if there exists a basis in which its matrix representation is a diagonal matrix. In this problem, the goal is to determine the connection between the diagonalizability of the linear transformation \(T\) and the matrix \(A=[T]_{\mathcal{C}+\mathcal{B}}\).
02

Relationship Between Linear Transformation and Matrix

Since \(V = W\) and \(\mathcal{B} = \mathcal{C}\), the matrix representation of \(T\) with respect to the basis \(\mathcal{B}\) (which is also \(\mathcal{C}\)) is \(A=[T]_{\mathcal{B}}\). For \(T\) to be diagonalizable, there must exist a basis of \(V\) such that the representation of \(T\) is a diagonal matrix, which directly corresponds to the diagonalizability of \(A\).
03

Diagonalizability of Matrix A

The matrix \(A\) is diagonalizable if there exists a similarity transformation \(P^{-1}AP=D\), where \(D\) is a diagonal matrix and \(P\) is an invertible matrix with columns consisting of eigenvectors of \(A\). This corresponds to the existence of a basis of eigenvectors for the transformation \(T\).
04

Conclusion on Diagonalizability of T and A

Since \(V=W\) and \(\mathcal{B}=\mathcal{C}\), \(T\) is diagonalizable if and only if there exists a basis of \(V\) consisting entirely of eigenvectors of \(T\). This exactly matches the condition for \(A\) to be diagonalizable, concluding that \(T\) is diagonalizable if and only if \(A\) is diagonalizable.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Transformation
Understanding the concept of a linear transformation is key in the study of linear algebra. A linear transformation is a function between two vector spaces that preserves the operations of vector addition and scalar multiplication. To put it simply, if you have two vectors, say \(\mathbf{u}\) and \(\mathbf{v}\), and a scalar \(c\), a transformation \(T\) satisfies:
  • \(T(\mathbf{u} + \mathbf{v}) = T(\mathbf{u}) + T(\mathbf{v})\)
  • \(T(c\mathbf{u}) = cT(\mathbf{u})\)
This means transformations maintain the structure of the space they are acting upon, an essential property that makes computation and analysis feasible. In the context of the exercise, linear transformations are closely linked with how matrices transform bases in vector spaces, providing a basis for the concept of diagonalization.
Matrix Representation
When discussing linear transformations, an integral part is their representation as matrices. A matrix can be thought of as a way of encoding the information about a linear transformation with respect to given bases. For example, if \(T: V \rightarrow W\) is a linear transformation and you choose bases \(\mathcal{B}\) for \(V\) and \(\mathcal{C}\) for \(W\), you can construct a matrix \([T]_{\mathcal{C} \mathcal{B}}\). This matrix specifies how \(T\) acts on each basis vector.
Matrix representation is powerful because it allows the use of matrix operations to analyze transformations. This representation helps in connecting abstract theoretical concepts with practical calculations. When matrices are used to represent linear transformations, complex operations can be boiled down to solutions involving matrix algebra, often simplifying otherwise cumbersome problems. This is particularly useful when checking for properties like diagonalizability.
Eigenvectors
Eigenvectors play a critical role when we talk about diagonalization. They are special vectors associated with a matrix that, when transformed by that matrix, result only in a scalar multiplication. If \(\mathbf{v}\) is an eigenvector of a matrix \(A\), it satisfies:
  • \(A\mathbf{v} = \lambda\mathbf{v}\)
where \(\lambda\) is the eigenvalue associated with \(\mathbf{v}\).
The eigenvectors of a matrix are fundamental in the diagonalization process because they form the set of new basis vectors where the transformation has a simple diagonal representation. Diagonal matrices are easy to manipulate, which makes the eigenvectors a powerful tool in simplifying matrix problems. If a complete set of linearly independent eigenvectors can be found for a matrix, the transformation can be represented by a diagonal matrix, meaning the matrix is diagonalizable.
Similarity Transformation
The concept of similarity transformation connects various concepts in linear algebra, especially when discussing diagonalization. Similarity transformations are equations of the form \(P^{-1}AP = D\), where \(A\) is the original matrix, \(D\) is a diagonal matrix, and \(P\) is an invertible matrix.
This transformation essentially re-bases the vector space to a new set of basis vectors, which correspond to the eigenvectors of \(A\). A matrix \(A\) is similar to a diagonal matrix \(D\) if there exists such a matrix \(P\), consisting of eigenvectors of \(A\), that conjugates \(A\) to \(D\).
This similarity transformation simplifies many computations because operations with diagonal matrices are straightforward. For linear transformations, the existence of this transformation implies that the transformation is diagonalizable, offering insights into the structure and behavior of the transformation. It also highlights the intrinsic connection between linear transformations and their matrix representations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Prove that for every vector \(\mathbf{v}\) in a vector space \(V\) there is a unique \(\mathbf{v}^{\prime}\) in \(V\) such that \(\mathbf{v}+\mathbf{v}^{\prime}=\mathbf{0}\).

Table 6.2 gives the population of the United States at 10-year intervals for the years \(1900-2000\) (a) Assuming an exponential growth model, use the data for 1900 and 1910 to find a formula for \(p(t)\) the population in year \(t .\) ( Hint: Let \(t=0\) be 1900 and let \(t=1\) be \(1910 .\) ) How accurately does your formula calculate the U.S. population in 2000 ? (b) Repeat part (a), but use the data for the years 1970 and 1980 to solve for \(p(t) .\) Does this approach give a better approximation for the year \(2000 ?\) (c) What can you conclude about U.S. population growth? $$\begin{array}{lc} \text { Year } & \text { (Population in millions) } \\ \hline 1900 & 76 \\ 1910 & 92 \\ 1920 & 106 \\ 1930 & 123 \\ 1940 & 131 \\ 1950 & 150 \\ 1960 & 179 \\ 1970 & 203 \\ 1980 & 227 \\ 1990 & 250 \\ 2000 & 281 \end{array}$$

T: U \(\rightarrow\) Vand \(S: V \rightarrow W\) are linear transformations and \(\mathcal{B}, \mathcal{C},\) and \(\mathcal{D}\) are bases for \(U, V,\) and \(W\) respectively. Compute \([S \circ T]_{D \leftarrow B}\) in two ways: \((a) b y\) finding \(S \circ\) T directly and then computing its matrix and (b) by finding the matrices of S and T separately and using Theorem 6.27. $$\begin{array}{l} T: \mathscr{P}_{1} \rightarrow \mathscr{P}_{2} \text { defined by } T(p(x))=p(x+1) \\ S: \mathscr{P}_{2} \rightarrow \mathscr{P}_{2} \text { defined by } S(p(x))=p(x+1) \text { , } \\ \mathcal{B}=\\{1, x\\}, \mathcal{C}=\mathcal{D}=\left\\{1, x, x^{2}\right\\} \end{array}$$

Let \(S=\left\\{\mathbf{v}_{1}, \ldots, \mathbf{v}_{n}\right\\}\) be a spanning set for a vector space \(V .\) Show that if \(\mathbf{v}_{n}\) is in \(\operatorname{span}\left(\mathbf{v}_{1}, \ldots, \mathbf{v}_{n-1}\right),\) then \(S^{\prime}=\left\\{\mathbf{v}_{1}, \ldots, \mathbf{v}_{n-1}\right\\}\) is still a spanning set for \(V\).

Radiocarbon dating is a method used by scientists to estimate the age of ancient objects that were once living matter, such as bone, leather, wood, or paper. All of these contain carbon, a proportion of which is carbon\(14,\) a radioactive isotope that is continuously being formed in the upper atmosphere. since living organisms take up radioactive carbon along with other carbon atoms, the ratio between the two forms remains constant. However, when an organism dies, the carbon- 14 in its cells decays and is not replaced. Carbon-14 has a known half-life of 5730 years, so by measuring the concentration of carbon- 14 in an object, scientists can determine its approximate age. (Figure can't copy) One of the most successful applications of radiocarbon dating has been to determine the age of the Stonehenge monument in England (Figure 6.25 ). Samples taken from the remains of wooden posts were found to have a concentration of carbon-14 that was \(45 \%\) of that found in living material. What is the estimated age of these posts?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.