Chapter 6: Problem 22
Let \(V\) be an \(n\) -dimensional vector space with basis \(\mathcal{B}=\left\\{\mathbf{v}_{1}, \ldots, \mathbf{v}_{n}\right\\} .\) Let \(P\) be an invertible \(n \times n\) matrix and set \\[ \mathbf{u}_{i}=p_{1 i} \mathbf{v}_{1}+\cdots+p_{n i} \mathbf{v}_{n} \\] for \(i=1, \ldots, n .\) Prove that \(\mathcal{C}=\left\\{\mathbf{u}_{1}, \ldots, \mathbf{u}_{n}\right\\}\) is a basis for \(V\) and show that \(P=P_{B \leftarrow C \text { . }}\)
Short Answer
Step by step solution
Understand the Basis
Show Linear Independence
Prove Spanning
Confirm \(\mathcal{C}\) is a Basis
Show \(P = P_{\mathcal{B} \leftarrow \mathcal{C}}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Space
In simpler terms, a vector space operates under two main operations: vector addition and scalar multiplication.
The most familiar vector spaces are those that consist of 'n' tuples of numbers, like \ \( \mathbb{R}^n \), where 'n' represents the number of dimensions in the space.
Each vector space is accompanied by a set of rules (axioms) that dictate how the vectors in the space behave under these operations. For a set of vectors to form a vector space, it must adhere to conditions such as closure under addition and scalar multiplication, the existence of a zero vector, and the presence of additive inverses.
- Closure: Adding two vectors in the space results in another vector in the same space.
- Associativity and Commutativity: These properties hold for vector addition.
- Identity and Inverse: Every vector space has a zero vector and additive inverses.
Linear Independence
If a set of vectors \( \{\mathbf{v}_1, \ldots, \mathbf{v}_n\} \) is linearly independent, the only solution to the equation \( a_1\mathbf{v}_1 + a_2\mathbf{v}_2 + \ldots + a_n\mathbf{v}_n = \mathbf{0} \) is \( a_1 = a_2 = \ldots = a_n = 0 \).
Simply put, none of the vectors in the set can be formed using others through linear combinations.
This concept is crucial when defining a basis for a vector space, as a basis is comprised of linearly independent vectors and ensures the space is well-represented with the fewest necessary vectors.
- Unique Contribution: Each vector contributes something unique that others cannot replicate.
- Simplification: Linear independence simplifies solving and transforming equations involving vectors.
- Essential for Basis: Linear independence is required for a set of vectors to form the basis of a vector space.
Spanning Set
This means any vector in the space can be expressed as a sum of scaled versions of the vectors in the spanning set.
For instance, in the vector space \( \mathbb{R}^3 \), the standard basis vectors \( \mathbf{i}, \mathbf{j}, \mathbf{k} \) can span the entire space.
- Definition: A vector space is completely described by its spanning set.
- Flexibility: Adjustments to the spanning set can reframe perspectives within a vector space.
- Basis Possibility: If a spanning set is linearly independent, it forms a basis of the vector space.
Invertible Matrix
This matrix allows you to 'undo' a linear transformation, returning to the original vector before the transformation was applied.
For a matrix \( P \) to be invertible, its determinant must be non-zero, formally indicating that the matrix has full rank and maps input vectors to new independent vectors in its range.
- Unique Mapping: Invertible matrices ensure a one-to-one relationship between input vectors and transformed vectors.
- Essential for Changing Bases: Is crucial for operations like changing from one basis to another via the Change of Basis matrix.
- Existence of Inverse: Having an inverse matrix \( P^{-1} \) ensures that transformations can be reversed.