Chapter 5: Problem 25
Let \(W\) be a subspace of \(\mathbb{R}^{n}\) and \(\mathbf{v}\) a vector in \(\mathbb{R}^{n}\). Suppose that \(\mathbf{w}\) and \(\mathbf{w}^{\prime}\) are orthogonal vectors with \(\mathbf{w}\) in \(W\) and that \(\mathbf{v}=\mathbf{w}+\mathbf{w}^{\prime} .\) Is it necessarily true that \(\mathbf{w}^{\prime}\) is in \(W^{\perp}\) ? Either prove that it is true or find a counterexample.
Short Answer
Step by step solution
Understanding the Problem
Understanding Orthogonality
Forming a Test Case
Verifying Orthogonality
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Subspace
- The zero vector must be present.
- Closure under addition: If two vectors are in the subspace, their sum must also be in the subspace.
- Closure under scalar multiplication: If a vector is in the subspace, any scalar multiple of that vector must also be in the subspace.
Orthogonality
Vector Decomposition
For example, if \( W \) is the subspace of \( \mathbb{R}^2 \) spanned by \( (1, 0) \), and we have the vector \( \mathbf{v} = (1, 1) \), we could decompose \( \mathbf{v} \) into \( \mathbf{w} = (1, 0) \) and \( \mathbf{w}^{\prime} = (0, 1) \). \( \mathbf{w}^{\prime} \) is orthogonal to any vector in the span of \( (1, 0) \), solidifying its presence in \( W^{\perp} \).This process is useful in various applications such as projections and simplifying linear equations. By understanding vector decomposition, students can gain insights into more complex vector space manipulations.