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Use properties of determinants to evaluate the given determinant by inspection. Explain your reasoning. $$\left|\begin{array}{cccc} 1 & 0 & 1 & 0 \\ 0 & 1 & 0 & 1 \\ 1 & 1 & 0 & 0 \\ 0 & 0 & 1 & 1 \end{array}\right|$$

Short Answer

Expert verified
The determinant is 0 due to linear dependence in rows.

Step by step solution

01

Understanding the Matrix

Let's inspect the matrix to understand its structure and properties. The given matrix is a 4x4 matrix with the following layout:\[ \begin{bmatrix} 1 & 0 & 1 & 0 \ 0 & 1 & 0 & 1 \ 1 & 1 & 0 & 0 \ 0 & 0 & 1 & 1 \end{bmatrix} \]Each row and column has alternating zeros and ones, making it appear like a block matrix or a permutation matrix.
02

Analyzing the Matrix Configuration

Notice that the matrix can be split into blocks, particularly focusing on the 2x2 principal submatrices:1. Top-left block: \( \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \) and2. Bottom-right block: \( \begin{bmatrix} 0 & 0 \ 1 & 1 \end{bmatrix} \)Also, the top-right block is \( \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \), and the bottom-left block is \( \begin{bmatrix} 1 & 1 \ 0 & 0 \end{bmatrix} \).None of these blocks alone form a proper identity submatrix needed for diagonal dominance, indicating the determinant is zero.
03

Identifying Rows or Columns that Can Lead to a Zero Determinant

When you examine the matrix row by row or column by column, you will see each 2x2 block in off-diagonal positions replicates values: - Row 1 and Row 3 are swaps of each other, and - Row 2 and Row 4 form similar combinations of swaps. No combination multiplies into a diagonal set of non-zero values; thus these 2x2 shifts suggest linear dependence across these rows, indicating zero determinant.
04

Conclusion by Row Dependence

Rows 1 and 3 or Rows 2 and 4 are linearly dependent, meaning this configuration mimics properties of both permutation matrices and identity matrices but not adequately to form non-zero configurations. As blocks do not form a full identity (main diagonal with 1's), this linear dependence confirms a zero determinant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

4x4 matrix
A 4x4 matrix is a mathematical object arranged in a grid of 4 rows and 4 columns. Each element in this grid is a specific number that contributes to the overall properties of the matrix. This matrix format extends the complexity seen in basic square matrices like 2x2 or 3x3 matrices, allowing for more intricate manipulations and calculations.
Evaluating a determinant of a 4x4 matrix often involves breaking it down into simpler components. Techniques like cofactor expansion or leveraging properties of matrices such as symmetry or block matrices can make the process manageable.
This kind of matrix appears frequently in systems of linear equations, where each row can represent a linear equation. Understanding a 4x4 matrix well is crucial in fields such as computer graphics, physics simulations, and more.
Linear Dependence
Linear dependence occurs when one row (or column) in a matrix can be expressed as a combination of others. In simpler terms, if any row or column can be formed by adding or scaling other rows or columns, then they are said to be linearly dependent.
To evaluate if a given 4x4 matrix is linearly dependent, one can check if swapping or scaling of certain rows or columns would still result in similar formations. Notably, if any row or column is a direct swap or a linear sum of others, it indicates the matrix may have a zero determinant.
  • If a matrix is linearly dependent, its determinant is zero. This means the matrix does not cover an entire 4-dimensional space, representing a smaller volume.
  • Linear dependence often reduces the problem, making it easier to determine crucial matrix properties such as its rank.
Understanding linear dependence helps in determining whether solutions to a system of equations are unique or if infinite solutions exist.
Block Matrix
A block matrix is formed by making divisions within a matrix into smaller matrix segments or 'blocks.' This structure helps simplify complex operations on large matrices while maintaining overall coherence.
The given 4x4 matrix in the exercise can be considered as composed of four 2x2 block matrices, each representing different parts of the whole picture. Identifying these blocks makes observing their interactions more straightforward and can help in reducing complex problems to simpler ones.
  • One useful property of block matrices is that they can sometimes reveal hidden symmetries or repetitive structures within a matrix.
  • In calculations, block matrices allow operations to be performed on smaller sections of the matrix, often revealing determinant properties.
Working with block matrices helps recognize opportunities to calculate determinants through efficient methods like block diagonalization when the arrangement allows.
Determinant Properties
Determinant properties are fundamental in evaluating matrices, particularly for understanding matrix behavior such as invertibility and volume scaling transformations.
The determinant of a 4x4 matrix can be evaluated using various properties. For instance, if a matrix has two identical rows or columns, or if one row can be expressed as a linear combination of others, the determinant of that matrix is zero. This property indicates linear dependence.
  • Using the determinant properties can help simplify the computation, avoiding complex, manual expansion through cofactors.
  • Specific matrix forms, like triangular or block diagonal matrices, allow for direct determinant evaluation by multiplying the diagonal elements.
Understanding properties such as these is crucial when inspecting matrices by eye, especially in identifying zeros in a determinant when related to linear dependence or block structures. This knowledge makes analyzing and interpreting matrices more intuitive and efficient.

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Most popular questions from this chapter

The matrices in either are not diagonalizable or do not have a dominant eigenvalue (or both). Apply the power method anyway with the given initial vector \(\mathbf{x}_{0}\) performing eight iterations in each case. Compute the exact eigenvalues and eigenvectors and explain what is happening. $$A=\left[\begin{array}{ll} 4 & 1 \\ 0 & 4 \end{array}\right], \mathbf{x}_{0}=\left[\begin{array}{l} 1 \\ 1 \end{array}\right]$$

(a) Use mathematical induction to prove that, for \(n \geq 2,\) the companion matrix \(C(p)\) of \(p(x)=x^{n}+\) \(a_{n-1} x^{n-1}+\dots+a_{1} x+a_{0}\) has characteristic polynomial \((-1)^{n} p(\lambda) .\) [Hint: Expand by cofactors along the last column. You may find it helpful to introduce the polynomial \(\left.q(x)=\left(p(x)-a_{0}\right) / x .\right]\) (b) Show that if \(\lambda\) is an eigenvalue of the companion matrix \(C(p)\) in equation \((4),\) then an eigenvector corresponding to \(\lambda\) is given by \\[ \left[\begin{array}{c} \lambda^{n-1} \\ \lambda^{n-2} \\ \vdots \\ \lambda \\ 1 \end{array}\right] \\] If \(p(x)=x^{n}+a_{n-1} x^{n-1}+\cdots+a_{1} x+a_{0}\) and \(A\) is a square matrix, we can define a square matrix \(p(A)\) by \\[ p(A)=A^{n}+a_{n-1} A^{n-1}+\cdots+a_{1} A+a_{0} I \\] An important theorem in advanced linear algebra says that if \(c_{A}(\lambda)\) is the characteristic polynomial of the matrix \(A\), then \(c_{A}(A)=O\) (in words, every matrix satisfies its characteristic equation . This is the celebrated Cayley-Hamilton Theorem, named after Arthur Cayley \((1821-1895)\) and Sir William Rowan Hamilton (see page 2). Cayley proved this theorem in \(1858 .\) Hamilton discovered it, independently, in his work on quaternions, a generalization of the complex numbers.

Compute (a) the characteristic polynomial of \(A,(b)\) the eigenvalues of \(A,(c)\) a basis for each eigenspace of \(A,\) and \((d)\) the algebraic and geometric multiplicity of each eigenvalue. $$A=\left[\begin{array}{rrr} 1 & 1 & 0 \\ 0 & -2 & 1 \\ 0 & 0 & 3 \end{array}\right]$$

A matrix \(A\) is given along with an iterate \(\mathbf{x}_{k},\) produced using the power method, as in Example 4.31 (a) Approximate the dominant eigenvalue and eigenvector by computing the corresponding \(m_{k}\) and \(\mathbf{y}_{k}\). (b) Verify that you have approximated an eigenvalue and an eigenvector of \(A\) by comparing \(A \mathbf{y}_{k}\) with \(m_{k} \mathbf{y}_{k}.\) $$A=\left[\begin{array}{rrr}1 & 2 & -2 \\ 1 & 1 & -3 \\ 0 & -1 & 1\end{array}\right], \mathbf{x}_{10}=\left[\begin{array}{r}3.415 \\ 2.914 \\\ -1.207\end{array}\right]$$

The matrices in either are not diagonalizable or do not have a dominant eigenvalue (or both). Apply the power method anyway with the given initial vector \(\mathbf{x}_{0}\) performing eight iterations in each case. Compute the exact eigenvalues and eigenvectors and explain what is happening. $$A=\left[\begin{array}{lll} 4 & 0 & 1 \\ 0 & 4 & 0 \\ 0 & 0 & 1 \end{array}\right], \mathbf{x}_{0}=\left[\begin{array}{l} 1 \\ 1 \\ 1 \end{array}\right]$$

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