Chapter 3: Problem 27
let \\[A=\left[\begin{array}{rrr}1 & 0 & -2 \\\\-3 & 1 & 1 \\\2 & 0 & -1\end{array}\right]\\] and \\[B=\left[\begin{array}{rrr}2 & 3 & 0 \\\1 & -1 & 1 \\\\-1 & 6 & 4\end{array}\right]\\]. Use the row-matrix representation of the product to write each row of \(B A\) as a linear combination of the rows of \(A\).
Short Answer
Step by step solution
Understand the Row-Matrix Representation
Calculate the Product of Row 1 of B and Matrix A
Calculate the Product of Row 2 of B and Matrix A
Calculate the Product of Row 3 of B and Matrix A
Compile the Resulting Matrix BA
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Row-Matrix Representation
Here's a simple breakdown:
- Each row of the resulting matrix is derived by combining rows of the first matrix (\(A\)).
- Entries from a row in the second matrix (\(B\)) act as scaling factors for the corresponding rows in \(A\).
Linear Combination
Consider how this works for one row of the resulting matrix:
- The entry from the row in matrix \(B\) multiplies its corresponding row in matrix \(A\).
- The result is a scaled version of the row of \(A\).
- Add these scaled rows together to form a single row of the product matrix \(BA\).
Matrix Product Calculation
To calculate such a product:
- Begin with the first row of matrix \(B\). Each of its elements acts as a multiplier for the corresponding entire row of matrix \(A\).
- Compute the linear combination for this row, add them up to get the first row of \(BA\).
- Repeat this process for each subsequent row of matrix \(B\).