/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Suppose that \(S=\left\\{\mathbf... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose that \(S=\left\\{\mathbf{v}_{1}, \ldots, \mathbf{v}_{k}, \mathbf{v}\right\\}\) is a set of vectors in some \(\mathbb{R}^{n}\) and that \(\mathbf{v}\) is a linear combination of \(\mathbf{v}_{1}, \dots\) \(\mathbf{v}_{k}\) If \(S^{\prime}=\left\\{\mathbf{v}_{1}, \ldots, \mathbf{v}_{k}\right\\},\) prove that \(\operatorname{span}(S)=\operatorname{span}\left(S^{\prime}\right)\) \([\text {Hint: Exercise 21(b) is helpful here.}]\)

Short Answer

Expert verified
The spans of sets \( S \) and \( S' \) are equal because \( \mathbf{v} \) is a linear combination of vectors in \( S' \).

Step by step solution

01

Understand the Problem

We need to show that the span of the set \( S = \{ \mathbf{v}_1, \ldots, \mathbf{v}_k, \mathbf{v} \} \) is equal to the span of the set \( S' = \{ \mathbf{v}_1, \ldots, \mathbf{v}_k \} \). We know that \( \mathbf{v} \) is a linear combination of \( \mathbf{v}_1, \ldots, \mathbf{v}_k \).
02

Express \( \mathbf{v} \) as a Linear Combination

Because \( \mathbf{v} \) is a linear combination of the vectors \( \mathbf{v}_1, \ldots, \mathbf{v}_k \), there exist coefficients \( c_1, c_2, \ldots, c_k \) such that \( \mathbf{v} = c_1 \mathbf{v}_1 + c_2 \mathbf{v}_2 + \cdots + c_k \mathbf{v}_k \).
03

Show \( \operatorname{span}(S') \subseteq \operatorname{span}(S) \)

By definition, every vector in \( S' \) is also in \( S \). Therefore, any linear combination of vectors in \( S' \) can be formed using vectors from \( S \). Thus, \( \operatorname{span}(S') \subseteq \operatorname{span}(S) \).
04

Show \( \operatorname{span}(S) \subseteq \operatorname{span}(S') \)

Since \( \mathbf{v} \) can be expressed as a linear combination of \( \mathbf{v}_1, \ldots, \mathbf{v}_k \), any linear combination of vectors in \( S \) can be expressed solely using vectors in \( S' \). Therefore, \( \operatorname{span}(S) \subseteq \operatorname{span}(S') \).
05

Conclude that \( \operatorname{span}(S) = \operatorname{span}(S') \)

Since \( \operatorname{span}(S') \subseteq \operatorname{span}(S) \) and \( \operatorname{span}(S) \subseteq \operatorname{span}(S') \), it follows that \( \operatorname{span}(S) = \operatorname{span}(S') \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Combination
In linear algebra, a fundamental concept is the linear combination. Essentially, a linear combination of a set of vectors is formed by multiplying each vector by a scalar and then summing the results. This is crucial because it helps us determine how vectors relate to each other within a set. Suppose you have vectors \(\mathbf{v}_1, \mathbf{v}_2, \ldots, \mathbf{v}_k\) in a vector space \(\mathbb{R}^n\). A vector \(\mathbf{v}\) is a linear combination of these vectors if there exist scalars \(c_1, c_2, \ldots, c_k\) such that:
  • \(\mathbf{v} = c_1 \mathbf{v}_1 + c_2 \mathbf{v}_2 + \cdots + c_k \mathbf{v}_k\).
This expression illustrates that \(\mathbf{v}\) is built from the set of vectors using specific scalar multipliers, showcasing the importance of each vector in forming another.
Vector Spaces
A vector space is a mathematical structure formed by a collection of vectors, which can be added together and multiplied by scalars. These operations comply with certain rules such as commutativity, associativity, and distributivity. The set \(\mathbb{R}^n\) is a classic example of a vector space, where each vector has \(n\) dimensions or components.
Here are key characteristics of vector spaces:
  • Closed under addition and scalar multiplication.
  • Contains the zero vector serving as an additive identity.
  • Allows for the creation of linear combinations.
Understanding vector spaces is critical because they provide the framework where concepts like linear combinations, bases, and dimensions actively operate.
Span of a Set
The span of a set of vectors is the collection of all possible linear combinations of those vectors. If you have a set \(S = \{\mathbf{v}_1, \mathbf{v}_2, \ldots, \mathbf{v}_k\}\), the span, \(\operatorname{span}(S)\), includes every vector that can be expressed as:
  • \(c_1 \mathbf{v}_1 + c_2 \mathbf{v}_2 + \cdots + c_k \mathbf{v}_k\), where \(c_i\) are real numbers.
The concept of span is important because it tells us how large a vector space can be generated from a set of vectors.
In the given exercise, proving that \(\operatorname{span}(S)\) is equal to \(\operatorname{span}(S')\) involves showing that adding or removing a vector that is a linear combination of others doesn’t change the overall span.
Proof Writing in Mathematics
Proof writing is a critical skill in mathematics that involves presenting a logical and systematic argument to establish the truth of a statement. It requires a careful arrangement of logical steps supported by definitions, theorems, and previously established results.
In our exercise, we demonstrated that \(\operatorname{span}(S) = \operatorname{span}(S')\) by proving both:
  • \(\operatorname{span}(S') \subseteq \operatorname{span}(S)\)
  • \(\operatorname{span}(S) \subseteq \operatorname{span}(S')\)
By completing these steps, we conclude that the spans are equal, emphasizing clarity and structure in proof writing. Mastering this enables deeper understanding and communication of mathematical ideas, essential for solving a broad array of problems in linear algebra and beyond.

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