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Let a \(\in \mathbb{R}^{3}\) be fixed. Define \(T: \mathbb{R}^{3} \rightarrow \mathbb{R}^{3}\) by \(T(\mathbf{x})=\mathbf{a} \times \mathbf{x}\) (see Exercise 5 ). a. Prove that \(T\) is a linear transformation. b. Give the standard matrix \(A\) of \(T\). c. Explain, using part \(a\) of Exercise 5 and Proposition \(5.2\) of Chapter 2, why \(A\) is skew-symmetric.

Short Answer

Expert verified
To prove that T is a linear transformation, we show that it satisfies additivity and scalar multiplication. Using properties of cross product, we proved T is additive: \(T(\mathbf{x}+\mathbf{y}) = T(\mathbf{x})+T(\mathbf{y})\), and T satisfies scalar multiplication: \(T(k\mathbf{x}) = kT(\mathbf{x})\). The standard matrix A is: \(A = \begin{pmatrix} 0 & -a_3 & a_2 \\ a_3 & 0 & -a_1 \\ -a_2 & a_1 & 0 \end{pmatrix}\) We showed A is skew-symmetric by demonstrating its transpose represents -T(x), implying A岬 = -A: \(A^\intercal = \begin{pmatrix} 0 & a_3 & -a_2 \\ -a_3 & 0 & a_1 \\ a_2 & -a_1 & 0 \end{pmatrix}\)

Step by step solution

01

Prove additivity of T

To show that T is a linear transformation, we first need to prove its additivity. Let x, y 鈭 鈩澛. Then, \(T(\mathbf{x}+\mathbf{y})=\mathbf{a}\times(\mathbf{x}+\mathbf{y})\) Now we apply the properties of the cross product: \(\mathbf{a}\times(\mathbf{x}+\mathbf{y})=\mathbf{a}\times\mathbf{x}+\mathbf{a}\times\mathbf{y}=T(\mathbf{x})+T(\mathbf{y})\) This shows that T is additive.
02

Prove scalar multiplication of T

Next, we need to show that T satisfies scalar multiplication. Let x 鈭 鈩澛 and k 鈭 鈩. Then, \(T(k\mathbf{x})=\mathbf{a}\times(k\mathbf{x})\) Using the properties of the cross product, we get: \(\mathbf{a}\times(k\mathbf{x})=k(\mathbf{a}\times\mathbf{x})=kT(\mathbf{x})\) This shows that T satisfies scalar multiplication. Since T satisfies both additivity and scalar multiplication, it is a linear transformation.
03

Find the standard matrix A of T

Now we need to find the standard matrix A of the transformation T. We know that T(x)=a脳x, and we want to represent this as a matrix multiplication Ax. Let x = (x鈧, x鈧, x鈧)岬 and a = (a鈧, a鈧, a鈧)岬. Then, \(T(\mathbf{x}) = \mathbf{a} \times \mathbf{x} = \begin{pmatrix} a_2x_3 - a_3x_2 \\ a_3x_1 - a_1x_3 \\ a_1x_2 - a_2x_1 \end{pmatrix}\) This can be represented as a matrix multiplication: \(T(\mathbf{x}) = \begin{pmatrix} 0 & -a_3 & a_2 \\ a_3 & 0 & -a_1 \\ -a_2 & a_1 & 0 \end{pmatrix}\begin{pmatrix} x_1 \\ x_2 \\ x_3 \end{pmatrix}\) So the standard matrix A of the transformation T is: \(A = \begin{pmatrix} 0 & -a_3 & a_2 \\ a_3 & 0 & -a_1 \\ -a_2 & a_1 & 0 \end{pmatrix}\)
04

Explain why A is skew-symmetric

Recall that a matrix is skew-symmetric if its transpose is equal to its negation, i.e., A岬 = -A. We can use part a of Exercise 5 and Proposition 5.2 of Chapter 2 to show that the standard matrix A is skew-symmetric. From part a of Exercise 5, we know that a脳x = -x脳a. Therefore, \(T(\mathbf{x}) = \mathbf{a} \times \mathbf{x} = -\mathbf{x} \times \mathbf{a}\) Let's write the transpose of A: \(A^\intercal = \begin{pmatrix} 0 & a_3 & -a_2 \\ -a_3 & 0 & a_1 \\ a_2 & -a_1 & 0 \end{pmatrix}\) Notice that A岬 represents the transformation of the cross product of x and a: \(T^\intercal(\mathbf{x}) = \mathbf{x} \times \mathbf{a} = -\mathbf{a} \times \mathbf{x} = -T(\mathbf{x})\) Therefore, A岬 represents -T(x), which implies that A岬 = -A. And as a result, the standard matrix A is skew-symmetric.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Cross Product
The cross product, a fundamental operation in vector calculus, is exclusive to three-dimensional space and is used to compute a vector that is orthogonal (at a right angle) to two given vectors. In the context of linear algebra, if you are given two vectors in \(\mathbb{R}^3\), say \(\mathbf{a}\) and \(\mathbf{x}\), their cross product \(\mathbf{a} \times \mathbf{x}\) will be a new vector that isn't aligned with \(\mathbf{a}\) or \(\mathbf{x}\).

Mathematically, the cross product can be computed using the determinants of matrices or by applying a formula that involves the components of the vectors involved. It's critical to note that the cross product is anticommutative. This means that \(\mathbf{a} \times \mathbf{x}\) is the negative of \(\mathbf{x} \times \mathbf{a}\), which plays a role in proving the properties of the transformation in our exercise. The ability for the cross product to output a perpendicular vector has applications in physics (e.g., torque computation) and computer graphics (e.g., finding surface normals).
Demystifying the Standard Matrix
The notion of a standard matrix is pivotal when translating linear transformations into a language we can work with numerically. For any linear transformation \(T: \mathbb{R}^{n} \rightarrow \mathbb{R}^{m}\), the standard matrix \(A\) is the representation of \(T\) with respect to the standard bases of \(\mathbb{R}^{n}\) and \(\mathbb{R}^{m}\).

To find \(A\), you consider how \(T\) acts on the basis vectors. For instance, if you have the transformation \(T(\mathbf{x}) = \mathbf{a} \times \mathbf{x}\) as in our exercise, you'd compute the action of \(T\) on each standard basis vector in \(\mathbb{R}^{3}\), and then you'd set these resulting vectors as the columns of \(A\). Understanding how to derive the standard matrix is essential because it allows us to manipulate and analyze linear transformations using matrix operations.
Exploring Skew-Symmetric Matrices
A skew-symmetric matrix is a special kind of square matrix that satisfies a unique property: its transpose is equal to its negative. This means if \(A\) is a skew-symmetric matrix, then \(A^\intercal = -A\). At a glance, this property tells us that all of the diagonal entries in a skew-symmetric matrix must be zero because they would otherwise negate themselves.

The standard matrix \(A\) derived from the cross product transformation in our exercise is inherently skew-symmetric, as shown through the relation \(\mathbf{a} \times \mathbf{x} = -\mathbf{x} \times \mathbf{a}\). This relationship arises from the properties of the cross product and has geometric significance: it preserves the structure of a space where flipping the order of crossing two vectors gives the negative of the original result. Skew-symmetric matrices have several applications, such as in the study of angular velocity and rigid body motion in physics.

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Most popular questions from this chapter

a. If \(C\) is the cofactor matrix of \(A\), give a formula for \(\operatorname{det} C\) in terms of \(\operatorname{det} A\). b. Let \(C=\left[\begin{array}{rrr}1 & -1 & 2 \\ 0 & 3 & 1 \\ -1 & 0 & -1\end{array}\right]\). Can there be a matrix \(A\) with cofactor matrix \(C\) and det \(A=3\) ? Find a matrix \(A\) with positive determinant and cofactor matrix \(C\).

Calculate the following determinants using cofactors. a. \(\operatorname{det}\left[\begin{array}{rrr}-1 & 3 & 5 \\ 6 & 4 & 2 \\ -2 & 5 & 1\end{array}\right]\) c. \(\operatorname{det}\left[\begin{array}{rrrr}1 & 4 & 1 & -3 \\ 2 & 10 & 0 & 1 \\ 0 & 0 & 2 & 2 \\ 0 & 0 & -2 & 1\end{array}\right]\) "b. \(\operatorname{det}\left[\begin{array}{rrrr}1 & -1 & 0 & 1 \\ 0 & 2 & 1 & 1 \\ 2 & -2 & 2 & 3 \\ 0 & 0 & 6 & 2\end{array}\right]\) dd. det \(\left[\begin{array}{rrrrr}2 & -1 & 0 & 0 & 0 \\ -1 & 2 & -1 & 0 & 0 \\\ 0 & -1 & 2 & -1 & 0 \\ 0 & 0 & -1 & 2 & -1 \\ 0 & 0 & 0 & -1 & 2\end{array}\right]\)

Let \(\mathbf{x}, \mathbf{y} \in \mathbb{R}^{3}\). Show that $$ \operatorname{det}\left[\begin{array}{cc} \mathbf{x} \cdot \mathbf{x} & \mathbf{x} \cdot \mathbf{y} \\ \mathbf{y} \cdot \mathbf{x} & \mathbf{y} \cdot \mathbf{y} \end{array}\right] $$ is the square of the area of the parallelogram spanned by \(\mathbf{x}\) and \(\mathbf{y}\).

Suppose \(A, B\), and \(C\) are vertices of a triangle in \(\mathbb{R}^{2}\), and \(D\) is a point in \(\mathbb{R}^{2}\). a. Use the fact that the vectors \(\overrightarrow{A B}\) and \(\overrightarrow{A C}\) are linearly independent to prove that we can write \(D=r A+s B+t C\) for some scalars \(r, s\), and \(t\) with \(r+s+t=1\). (Here, we are treating \(A, B, C\), and \(D\) as vectors in \(\mathbb{R}^{2}\).) b. Use Exercise 3 to show that \(t\) is the ratio of the signed area of \(\triangle A B D\) to the signed area of \(\triangle A B C\) (and similar results hold for \(r\) and \(s\) ).

Using cofactors, find the determinant and the inverse of the matrix $$ A=\left[\begin{array}{rrr} -1 & 2 & 3 \\ 2 & 1 & 0 \\ 0 & 2 & 3 \end{array}\right] \text {. } $$

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