Chapter 3: Problem 10
Let \(V \subset \mathbb{R}^{n}\) be a subspace. Show that \(V \cap V^{\perp}=\\{0\\}\).
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Chapter 3: Problem 10
Let \(V \subset \mathbb{R}^{n}\) be a subspace. Show that \(V \cap V^{\perp}=\\{0\\}\).
These are the key concepts you need to understand to accurately answer the question.
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Let \(A\) be an \(n \times n\) matrix. Prove that if \(A\) is nonsingular and \(\left\\{\mathbf{v}_{1}, \ldots, \mathbf{v}_{k}\right\\}\) is linearly independent, then \(\left\\{A \mathbf{v}_{1}, A \mathbf{v}_{2}, \ldots, A \mathbf{v}_{k}\right\\}\) is likewise linearly independent. Give an example to show that the result is false if \(A\) is singular.
Using the inner product defined in Example \(10(\mathrm{c})\), let \(V=\mathrm{e}^{0}([a, b])\), and let \(W=\) \(\left\\{f \in V: \int_{a}^{b} f(t) d t=0\right\\} .\) a. Prove that \(W\) is a subspace of \(V\). b. Prove that \(W^{\perp}\) is the subspace of constant functions. c. Prove or disprove: \(W+W^{\perp}=V\).
Use the definition of a vector space \(V\) to prove the following: a. \(0 \mathbf{u}=\mathbf{0}\) for every \(\mathbf{u} \in V\). b. \(-\mathbf{u}=(-1) \mathbf{u}\) for every \(\mathbf{u} \in V\). (Hint: The distributive property 7 is all important.)
Let \(V \subset \mathbb{R}^{n}\) be a subspace. Show that \(V \subset\left(V^{\perp}\right)^{\perp}\). Do you think more is true?
In each case, construct a matrix with the requisite properties or explain why no such matrix exists. "a. The column space has basis \(\left[\begin{array}{l}1 \\ 0 \\\ 1\end{array}\right]\), and the nullspace contains \(\left[\begin{array}{l}1 \\\ 2 \\ 0\end{array}\right]\). b. The nullspace contains \(\left[\begin{array}{l}1 \\ 0 \\\ 1\end{array}\right],\left[\begin{array}{r}-1 \\ 2 \\ 1\end{array}\right]\), and the row space contains \(\left[\begin{array}{r}1 \\ 1 \\\ -1\end{array}\right]\). *c. The column space has basis \(\left[\begin{array}{l}1 \\\ 0 \\ 1\end{array}\right],\left[\begin{array}{l}0 \\ 1 \\\ 1\end{array}\right]\), and the row space has basis \(\left[\begin{array}{l}1 \\\ 1 \\ 1\end{array}\right],\left[\begin{array}{l}2 \\ 0 \\\ 1\end{array}\right]\). d. The column space and the nullspace both have basis \(\left[\begin{array}{l}1 \\\ 0\end{array}\right]\). e. The column space and the nullspace both have basis \(\left[\begin{array}{l}1 \\\ 0 \\ 0\end{array}\right]\).
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