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Find the values of \(k\) that make each of the following matrices positive definite: (a) \(\quad A=\left[\begin{array}{rr}2 & -4 \\ -4 & k\end{array}\right]\), (b) \(\quad B=\left[\begin{array}{ll}4 & k \\ k & 9\end{array}\right]\), (c) \(\quad C=\left[\begin{array}{rr}k & 5 \\ 5 & -2\end{array}\right]\)

Short Answer

Expert verified
The values of \(k\) that make each of the matrices positive definite are: (a) \(k > 8\) for matrix A, (b) \(-6 < k < 6\) for matrix B, (c) \(k > \frac{25}{2}\) for matrix C.

Step by step solution

01

Compute the characteristic polynomial of matrix A

To compute the characteristic polynomial, we need to find the determinant of matrix \((A - \lambda I)\), where \(\lambda\) is an eigenvalue and \(I\) is the identity matrix. That is: \[ \begin{vmatrix} 2 - \lambda & -4 \\ -4 & k - \lambda \end{vmatrix} \]
02

Find the determinant and characteristic equation of matrix A

Calculate the determinant using the formula \((2-\lambda)(k-\lambda) - (-4)(-4)\) which results in the following characteristic equation: \[ (2 - \lambda)(k - \lambda) - 16 = 0 \]
03

Solve the characteristic equation for eigenvalues of matrix A

To make sure that matrix A is positive definite, both eigenvalues must be positive. Solve the characteristic equation for \(\lambda\): \[ \lambda^2 - (2+k)\lambda + 2k-16 = 0 \]
04

Find the determinant and characteristic equation of matrix B

Similarly, we need to find the determinant of matrix \((B - \lambda I)\): \[ \begin{vmatrix} 4 - \lambda & k \\ k & 9 - \lambda \end{vmatrix} \] Calculate the determinant using the formula \((4-\lambda)(9-\lambda) - k^2\), which result in the following characteristic equation: \[ (4 - \lambda)(9 - \lambda) - k^2 = 0 \]
05

Solve the characteristic equation for eigenvalues of matrix B

To make sure that matrix B is positive definite, both eigenvalues must be positive. Solve the characteristic equation for \(\lambda\): \[ \lambda^2 - (13)\lambda + (36 - k^2) = 0 \]
06

Find the determinant and characteristic equation of matrix C

Now, find the determinant of matrix \((C - \lambda I)\): \[ \begin{vmatrix} k - \lambda & 5 \\ 5 & -2 - \lambda \end{vmatrix} \] Calculate the determinant using the formula \((k-\lambda)(-2-\lambda) - (5)(5)\), which results in the following characteristic equation: \[ (k - \lambda)(-2 - \lambda) - 25 = 0 \]
07

Solve the characteristic equation for eigenvalues of matrix C

To make sure that matrix C is positive definite, both eigenvalues must be positive. Solve the characteristic equation for \(\lambda\): \[ \lambda^2 - (k-2)\lambda + 2k - 25 = 0 \]
08

Determine the values of \(k\) for each matrix

(a) For matrix A, since the determinant \((2k - 16) > 0\), it implies that \(k > 8\). (b) For matrix B, since the determinant \((36 - k^2) > 0\), it implies that \(-6 < k < 6\). (c) For matrix C, since the determinant \((2k - 25) > 0\), it implies that \(k > \frac{25}{2}\). So, the values of \(k\) that make each of the matrices positive definite are: (a) \(k > 8\) for matrix A, (b) \(-6 < k < 6\) for matrix B, (c) \(k > \frac{25}{2}\) for matrix C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eigenvalues
Eigenvalues are essential in understanding a matrix's behavior. They are the scalar values that stem from the characteristic equation of a matrix. For a matrix to be positive definite, all its eigenvalues must be strictly positive. This characteristic ensures matrices can maintain certain positive properties, crucial in various calculations.

Calculating eigenvalues begins with setting up the characteristic equation derived from the determinant of \( (A - \lambda I) \), the matrix minus the eigenvalue \( \lambda \) times the identity matrix. This determinant yields a polynomial, typically of the second degree for 2x2 matrices, where \( \lambda \) represents the roots. Solving this polynomial gives you the eigenvalues.

To apply this to our original problem, for each matrix, we solve for \( \lambda \) using the given characteristic equations. Once calculated, these eigenvalues help verify if \( k \) values meet the positive definite condition. If both eigenvalues of a matrix are greater than zero, it confirms the matrix is positive definite.
Determinants
Determinants play a crucial role in understanding matrix properties. They are a scalar number that offers insight into matrix behavior, especially with transformations like rotations and scaling in linear algebra. A determinant can determine solvability of systems of linear equations and matrix invertibility.

For a 2x2 matrix \( \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \), the determinant is calculated as \( ad - bc \). For the matrices in our exercise, determining the conditions for the determinants to be positive is key to confirming when a matrix is positive definite.

In the problem, by calculating the determinants for each transformed matrix (i.e., \( (Matrix - \lambda I) \)), we find expressions involving \( k \) that must be positive. For instance, in matrix A, the determinant \( 2k - 16 > 0 \) suggests that \( k > 8 \). This calculation is crucial in assessing the conditions for positive definiteness.
Characterization of Matrices
Characterization of matrices involves identifying attributes that define their mathematical properties and behavior. Positive definite matrices are a special category characterized by distinct properties, notably that all their eigenvalues are positive and their top-left determinants must be positive. These properties assist in applications such as quadratic forms and optimization problems.

A matrix is considered positive definite if:
  • All eigenvalues are positive
  • The principal minors (determinants of submatrices) are positive
These conditions ensure any associated quadratic form is convex and greater than zero for non-zero vectors.

From our exercise, characterizing matrices under different conditions offers invaluable insights into their possible transformations and usages in real-world scenarios. By examining matrices A, B, and C, we identifiy the positive definiteness conditions, aiding in applications where such matrices ensure stable solutions and desirable properties.

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Most popular questions from this chapter

Find an orthogonal basis and an orthonormal basis for the subspace \(W\) of \(\mathbf{C}^{3}\) spanned by \(u_{1}=(1, i, 1)\) and \(u_{2}=(1+i, 0,2)\)

Prove Theorem 7.6 (Pythagoras): Suppose \(\left\\{u_{1}, u_{2}, \ldots, u_{r}\right\\}\) is an orthogonal set of vectors. Then \\[ \left\|u_{1}+u_{2}+\cdots+u_{r}\right\|^{2}=\left\|u_{1}\right\|^{2}+\left\|u_{2}\right\|^{2}+\cdots+\left\|u_{r}\right\|^{2}\\]

Prove Theorem 7.24: Let \(V\) be a normed vector space. Then the function \(d(u, v)=\|u-v\|\) satisfies the following three axioms of a metric space: \(\left[\mathrm{M}_{1}\right] \quad d(u, v) \geq 0\); and \(d(u, v)=0\) iff \(u=v\) \(\left[\mathbf{M}_{2}\right] \quad d(u, v)=d(v, u)\) \(\left[\mathrm{M}_{3}\right] \quad d(u, v) \leq d(u, w)+d(w, v)\) If \(u \neq v\), then \(u-v \neq 0\), and hence, \(d(u, v)=\|u-v\|>0\). Also, \(d(u, u)=\|u-u\|=\|0\|=0\). Thus, \(\left[\mathrm{M}_{1}\right]\) is satisfied. We also have $$ d(u, v)=\|u-v\|=\|-1(v-u)\|=|-1|\|v-u\|=\|v-u\|=d(v, u) $$ and \(\quad d(u, v)=\|u-v\|=\|(u-w)+(w-v)\| \leq\|u-w\|+\|w-v\|=d(u, w)+d(w, v)\) Thus, \(\left[\mathrm{M}_{2}\right]\) and \(\left[\mathrm{M}_{3}\right]\) are satisfied.

\- Consider the subspace \(W=\mathbf{P}_{2}(t)\) of \(\mathbf{P}(t)\) with inner product \(\langle f, g\rangle=\int_{0}^{1} f(t) g(t) d t\). Find the projection of \(f(t)=t^{3}\) onto \(W\). (Hint: Use the orthogonal polynomials \(1,2 t-1,6 t^{2}-6 t+1\) obtained in Problem 7.22.)

Let \(S\) consist of the following vectors in \(\mathbf{R}^{4}\) : $$ u_{1}=(1,1,1,1), \quad u_{2}=(1,1,-1,-1), \quad u_{3}=(1,-1,1,-1), \quad u_{4}=(1,-1,-1,1) $$ (a) Show that \(S\) is orthogonal and a basis of \(\mathbf{R}^{4}\). (b) Write \(v=(1,3,-5,6)\) as a linear combination of \(u_{1}, u_{2}, u_{3}, u_{4}\). (c) Find the coordinates of an arbitrary vector \(v=(a, b, c, d)\) in \(\mathbf{R}^{4}\) relative to the basis \(S\). (d) Normalize \(S\) to obtain an orthonormal basis of \(\mathbf{R}^{4}\).

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