Chapter 1: Problem 37
Prove: For any complex numbers \(z, w \in \mathbf{C},|z+w| \leq|z|+|w|.\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 1: Problem 37
Prove: For any complex numbers \(z, w \in \mathbf{C},|z+w| \leq|z|+|w|.\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Let \(S\) be the surface \(x y^{2}+2 y z=16\) in \(\mathbf{R}^{3}\) (a) Find the normal vector \(\mathbf{N}(x, y, z)\) to the surface \(S\) (b) Find the tangent plane \(H\) to \(S\) at the point \(P(1,2,3)\)
Prove Theorem 1.4 (Minkowski): \(\|u+v\| \leq\|u\|+\|v\|.\)
Find \(x\) and \(y\) where: (a) \((x, y+1)=(y-2,6)\); (b) \(x(2, y)=y(1,-2)\).
Prove: For any vectors \(u, v, w\) in \(\mathbf{C}^{n}\) : (a) \((u+v) \cdot w=u \cdot w+v \cdot w\) (b) \(w \cdot(u+v)=w \cdot u+w \cdot v\).
Suppose \(z=5+3 i\) and \(w=2-4 i\). Find: (a) \(z+w\), (b) \(z-w,(\mathrm{c}) \quad z w\). Use the ordinary rules of algebra together with \(i^{2}=-1\) to obtain a result in the standard form \(a+b i\). (a) \(z+w=(5+3 i)+(2-4 i)=7-i\) (b) \(z-w=(5+3 i)-(2-4 i)=5+3 i-2+4 i=3+7 i\) (c) \(z w=(5+3 i)(2-4 i)=10-14 i-12 i^{2}=10-14 i+12=22-14 i\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.