/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Prove that \(A+A^{t}\) is symmet... [FREE SOLUTION] | 91Ó°ÊÓ

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Prove that \(A+A^{t}\) is symmetric for any square matrix \(A\).

Short Answer

Expert verified
To prove that the given matrix \(A + A^t\) is symmetric, we need to show that its transpose is equal to the matrix itself. Using the properties of matrix transposes, we find: \[ (A + A^t)^t = A^t + (A^t)^t = A^t + A. \] Since the result is the same expression, \(A + A^t\) is symmetric for any square matrix \(A\).

Step by step solution

01

Find the transpose of the matrix \(A + A^t\).

To find the transpose of the given matrix, we must apply the transpose operation to the entire matrix expression. So, our objective is to find \((A + A^t)^t\).
02

Use the transpose properties.

Recall that for two matrices \(A\) and \(B\), the transpose of their sum \((A + B)^t\) is equal to the sum of their transposes \(A^t + B^t\). Therefore, we have \[ (A + A^t)^t = A^t + (A^t)^t. \]
03

Find the transpose of the transpose.

Note that taking the transpose of a transpose matrix, i.e., \((A^t)^t\), is equivalent to applying the transpose operation twice. The result is the original matrix \(A\). Hence, \[ A^t + (A^t)^t = A^t + A. \]
04

Prove symmetry.

Now, we have found the transpose of the given matrix \((A + A^t)^t = A^t + A\). If the transpose of the matrix \(A + A^t\) is equal to the matrix itself, then the matrix is symmetric. Since we obtained the same expression \(A^t + A\), the given matrix is indeed symmetric. Therefore, \(A + A^t\) is symmetric for any square matrix \(A\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Transpose
Understanding the concept of matrix transpose is fundamental in linear algebra. The transpose of a matrix, often denoted as \( A^t \), is formed by flipping the matrix over its diagonal. This essentially means that the row and column indices of each element are swapped. If you have a matrix \( A \) with elements \( a_{ij} \) positioned at the \( ith \) row and \( jth \) column, the corresponding element in the transpose \( A^t \) will be at the \( jth \) row and \( ith \) column, denoted by \( a_{ji} \).

The transpose operation can reveal many properties about the matrix, especially when it comes to symmetric matrices. A symmetric matrix is essentially its own transpose, meaning that \( A = A^t \), which plays a pivotal role in various mathematical applications and theoretical proofs, such as the exercise we are exploring.
Square Matrix
A square matrix is simply a matrix that has the same number of rows as columns. In other words, the dimensions of a square matrix are always \( n \times n \), where \( n \) represents the number of rows or columns. An important aspect of square matrices is that many operations and properties in linear algebra are exclusively defined for them.

  • Only square matrices can be symmetric, since symmetry requires the matrix to be identical upon transposition, which isn't possible if the dimensions don't match.
  • When it comes to finding eigenvalues and eigenvectors, which are crucial in various branches of science and engineering, we specifically look at square matrices.
  • The exercise on proving that \( A + A^t \) is symmetric relies on the fact that \( A \) is square, because only then can \( A \) and \( A^t \) be composed and compared.
Getting comfortable with square matrices is key to understanding more complex linear algebra concepts.
Properties of Transpose
The properties of transpose operations are extremely helpful when manipulating and understanding matrices, as demonstrated in the solution of our exercise. Here are a few crucial properties:

  • Transpose of a Sum: The transpose of a sum of two matrices equals the sum of their transposes. Mathematically, \( (A + B)^t = A^t + B^t \). This property is utilized in step 2 of our exercise solution.
  • Transpose of a Transpose: Taking the transpose of a transpose brings you back to the original matrix. In symbols, \( (A^t)^t = A \). This is evident in step 3 of our exercise solution.
  • Transpose of a Product: The product of two matrix transposes is the transpose of their product in reverse order. For example, \( (AB)^t = B^t A^t \).
By applying these properties, one can confidently navigate through complex algebraic expressions to reach desired conclusions, just like how we deduced the symmetry of \( A + A^t \).

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Most popular questions from this chapter

Exercises 5 and 6 show why the definitions of matrix addition and scalar multiplication (as defined in Example 2) are the appropriate ones. Richard Gard ("Effects of Beaver on Trout in Sagehen Creek, California," J. Wildlife Management, 25, 221-242) reports the following number of trout having crossed beaver dams in Sagehen Creek. Upstream Crossings $$ \begin{array}{lccc} \hline & \text { Fall } & \text { Spring } & \text { Summer } \\ \hline \text { Brook trout } & 8 & 3 & 1 \\ \text { Rainbow trout } & 3 & 0 & 0 \\ \text { Brown trout } & 3 & 0 & 0 \\ \hline \end{array} $$ Upstream Crossings $$ \begin{array}{lccc} \hline & \text { Fall } & \text { Spring } & \text { Summer } \\ \hline \text { Brook trout } & 9 & 1 & 4 \\ \text { Rainbow trout } & 3 & 0 & 0 \\ \text { Brown trout } & 1 & 1 & 0 \\ \hline \end{array} $$Record the upstream and downstream crossings in two 3 x 3 matrices, and verify that the sum of these matrices gives the total number of crossings (both upstream and downstream) categorized by trout species and season

Prove that the diagonals of a parallelogram bisect each other.

Prove that \(\operatorname{span}(\\{x\\})=\\{a x: a \in F\\}\) for any vector \(x\) in a vector space, Interpret this result geometrically in \(\mathrm{R}^{3}\).

Let \(V\) denote the vector space of sequences in \(R\), as defined in Example 5 of Section 1.2. Show that the set of convergent sequences \(\left(a_{n}\right)\) (that is, those for which \(\lim _{n \rightarrow \infty} a_{n}\) exists) is a subspace of \(\mathrm{V}\).

Let \(V\) denote the vector space of all upper triangular \(n \times n\) matrices (as defined on page 19), and let \(W_{1}\) denote the subspace of \(V\) consisting of all diagonal matrices. Define \(\mathrm{W}_{2}=\left\\{A \in \mathrm{V}: A_{i j}=0\right.\) whenever \(\left.i \geq j\right\\}\). Show that \(\mathrm{V}=\mathrm{W}_{1} \oplus \mathrm{W}_{2}\).

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