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Compute the determinants of the following matrices in $\mathrm{M}_{2 \times 2}(R)$. (a) \(\left(\begin{array}{rr}6 & -3 \\ 2 & 4\end{array}\right)\) (b) \(\left(\begin{array}{rr}-5 & 2 \\ 6 & 1\end{array}\right)\) (c) \(\left(\begin{array}{rr}8 & 0 \\ 3 & -1\end{array}\right)\)

Short Answer

Expert verified
The determinants of the given matrices are: (a) \(\det\left(\begin{array}{rr}6 & -3 \\\ 2 & 4\end{array}\right) = 30\) (b) \(\det\left(\begin{array}{rr}-5 & 2 \\\ 6 & 1\end{array}\right) = -17\) (c) \(\det\left(\begin{array}{rr}8 & 0 \\\ 3 & -1\end{array}\right) = -8\)

Step by step solution

01

Calculate the determinant of matrix (a)

To calculate the determinant of the matrix \(\left(\begin{array}{rr}6 & -3 \\\ 2 & 4\end{array}\right)\), we will apply the formula \(\det(A) = ad - bc\). In this case, \(a = 6\), \(b = -3\), \(c = 2\), and \(d = 4\). Therefore, \[\det(A) = (6)(4) - (-3)(2) = 24 + 6 = 30.\]
02

Calculate the determinant of matrix (b)

To calculate the determinant of the matrix \(\left(\begin{array}{rr}-5 & 2 \\\ 6 & 1\end{array}\right)\), we will apply the formula \(\det(A) = ad - bc\). In this case, \(a = -5\), \(b = 2\), \(c = 6\), and \(d = 1\). Therefore, \[\det(A) = (-5)(1) - (2)(6) = -5 - 12 = -17.\]
03

Calculate the determinant of matrix (c)

To calculate the determinant of the matrix \(\left(\begin{array}{rr}8 & 0 \\\ 3 & -1\end{array}\right)\), we will apply the formula \(\det(A) = ad - bc\). In this case, \(a = 8\), \(b = 0\), \(c = 3\), and \(d = -1\). Therefore, \[\det(A) = (8)(-1) - (0)(3) = -8.\] To summarize, the determinants of the given matrices are: (a) \(\det\left(\begin{array}{rr}6 & -3 \\\ 2 & 4\end{array}\right) = 30\) (b) \(\det\left(\begin{array}{rr}-5 & 2 \\\ 6 & 1\end{array}\right) = -17\) (c) \(\det\left(\begin{array}{rr}8 & 0 \\\ 3 & -1\end{array}\right) = -8\)

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