/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Is the set of all differentiable... [FREE SOLUTION] | 91Ó°ÊÓ

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Is the set of all differentiable real-valued functions defined on \(R\) a subspace of \(C(R)\) ? Justify your answer.

Short Answer

Expert verified
Yes, the set of all differentiable real-valued functions defined on \(R\) is a subspace of \(C(R)\) because it contains the zero function, and it is closed under both addition and scalar multiplication.

Step by step solution

01

Check if the zero function is in the set of differentiable functions

The zero function is defined as \(f(x) = 0, \forall x \in R\). The derivative of the zero function with respect to \(x\) is \(f'(x) = 0, \forall x \in R\), which means the zero function is differentiable. Thus, the zero function is in the set of differentiable real-valued functions.
02

Check if the set is closed under addition

Let \(f(x)\) and \(g(x)\) be any two differentiable real-valued functions defined on \(R\). We need to verify if their sum, \(f(x) + g(x)\), is also differentiable. The sum rule of differentiation states that \((f(x) + g(x))' = f'(x) + g'(x)\), which means that the derivative exists and is continuous. Since \(f(x) + g(x)\) is differentiable, the set is closed under addition.
03

Check if the set is closed under scalar multiplication

Let \(f(x)\) be a differentiable real-valued function defined on \(R\) and let \(c\) be any scalar. We need to verify if the scalar multiplication of \(f(x)\) and \(c\), which is \(cf(x)\), is differentiable. The scalar multiplication rule of differentiation states that \((cf(x))' = cf'(x)\). Since the derivative exists and is continuous, the function \(cf(x)\) is differentiable. Therefore, the set is closed under scalar multiplication. Since the set of differentiable real-valued functions defined on \(R\) satisfies the subspace criteria, it is a subspace of \(C(R)\).

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