Chapter 9: Problem 4
Find \(|z|\) and \(\bar{z}\), and verify that \(z \bar{z}=|z|^{2}\), if a. \(z=2+i\), b. \(z=3-4 i\).
Short Answer
Expert verified
For (a), \(|z| = \sqrt{5}\), \(\bar{z} = 2 - i\); for (b), \(|z| = 5\), \(\bar{z} = 3 + 4i\). Both verify \(z \bar{z} = |z|^2\).
Step by step solution
01
Identify the Components of z
For part (a), we have \(z = 2 + i\), where the real part is \(2\) and the imaginary part is \(1\). For part (b), \(z = 3 - 4i\), where the real part is \(3\) and the imaginary part is \(-4\).
02
Calculate |z| for Part (a)
For \(z = 2 + i\), the magnitude \(|z|\) is calculated as \(|z| = \sqrt{2^2 + 1^2} = \sqrt{4 + 1} = \sqrt{5}\).
03
Find \(\bar{z}\) for Part (a)
The conjugate of \(z = 2 + i\) is \(\bar{z} = 2 - i\).
04
Verify \(z\bar{z} = |z|^2\) for Part (a)
Compute \(z \bar{z} = (2 + i)(2 - i) = 2^2 - i^2 = 4 + 1 = 5\), and \(|z|^2 = (\sqrt{5})^2 = 5\). Therefore, \(z \bar{z} = |z|^2\) is verified for part (a).
05
Calculate |z| for Part (b)
For \(z = 3 - 4i\), the magnitude \(|z|\) is calculated as \(|z| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5\).
06
Find \(\bar{z}\) for Part (b)
The conjugate of \(z = 3 - 4i\) is \(\bar{z} = 3 + 4i\).
07
Verify \(z\bar{z} = |z|^2\) for Part (b)
Compute \(z \bar{z} = (3 - 4i)(3 + 4i) = 3^2 - (-4)^2 = 9 + 16 = 25\), and \(|z|^2 = 5^2 = 25\). Therefore, \(z \bar{z} = |z|^2\) is verified for part (b).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of Complex Numbers
The magnitude of a complex number, also known as the modulus, is a measure of its size. It gives us a way to quantify how large or small a complex number is, just like absolute value for real numbers.
For a complex number written as \( z = a + bi \) where \( a \) is the real part and \( b \) is the imaginary part, the magnitude is calculated by taking the square root of the sum of the squares of the real and imaginary parts.
For a complex number written as \( z = a + bi \) where \( a \) is the real part and \( b \) is the imaginary part, the magnitude is calculated by taking the square root of the sum of the squares of the real and imaginary parts.
- Formula: \(|z| = \sqrt{a^2 + b^2}\)
- Example: For \( z = 2 + i \), the magnitude is \( |z| = \sqrt{2^2 + 1^2} = \sqrt{5} \).
- For \( z = 3 - 4i \), the magnitude is \( |z| = \sqrt{3^2 + (-4)^2} = \sqrt{25} = 5 \).
Complex Conjugate
The complex conjugate of a complex number involves changing the sign of the imaginary part while keeping the real part unchanged. It is a crucial concept in complex number arithmetic.
If a complex number \( z \) is written as \( z = a + bi \), its conjugate, denoted as \( \bar{z} \), is \( \bar{z} = a - bi \).
If a complex number \( z \) is written as \( z = a + bi \), its conjugate, denoted as \( \bar{z} \), is \( \bar{z} = a - bi \).
- Example: For \( z = 2 + i \), the conjugate is \( \bar{z} = 2 - i \).
- For \( z = 3 - 4i \), the conjugate is \( \bar{z} = 3 + 4i \).
Properties of Complex Numbers
Complex numbers have several interesting properties, making them unique in mathematics. One of the key properties relates to how they interact with their conjugates and magnitudes.
- For any complex number \( z \), the relationship \( z \bar{z} = |z|^2 \) holds true.
- This means when you multiply a complex number by its conjugate, the result is always a real number equal to the square of the magnitude of the original complex number.
- Example: For \( z = 2 + i \), we found that \( z \bar{z} = (2+i)(2-i) = 5 = |z|^2 \).
- For \( z = 3 - 4i \), \( z \bar{z} = 25 = |z|^2 \); hence, this property is verified.