Chapter 9: Problem 3
Find \(|z|\) and \(\bar{z}\), and verify that \(z \bar{z}=|z|^{2}\), if a. \(z=3+2 i\), b. \(z=4-i\).
Short Answer
Expert verified
For a.
1. \(|z| = \sqrt{13}, \bar{z} = 3 - 2i\), and
2. \(z \bar{z} = 13 = |z|^2\).
For b.
1. \(|z| = \sqrt{17}, \bar{z} = 4 + i\), and
2. \(z \bar{z} = 17 = |z|^2\).
Step by step solution
01
Define the Complex Number
For each part, start by clearly identifying the given complex number, \(z\).
02
Find the Magnitude \(|z|\)
The magnitude of a complex number \(z = a + bi\) is calculated as \(|z| = \sqrt{a^2 + b^2}\). Use this formula to find the magnitude for the given \(z\).
03
Find the Conjugate \(\bar{z}\)
The conjugate of a complex number \(z = a + bi\) is \(\bar{z} = a - bi\). Write down the conjugate for the specified \(z\).
04
Verify \(z \bar{z} = |z|^2\)
Calculate \(z \bar{z}\) to verify it equals \(|z|^2\), using the relationships \(z \bar{z} = (a + bi)(a - bi)\) which simplifies to \(a^2 + b^2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of Complex Numbers
The magnitude of a complex number is a way to express its size or distance from the origin on the complex plane. For a complex number in the form of \(z = a + bi\), the magnitude \(|z|\) can be found using the formula:\[|z| = \sqrt{a^2 + b^2}\]Here, \(a\) is the real part of the complex number, and \(b\) is the imaginary part. This formula is derived from the Pythagorean theorem, making the magnitude analogous to the hypotenuse of a right triangle with sides \(a\) and \(b\). By calculating \(|z|\), you essentially find the distance from the point represented by the complex number \(z\) to the origin \((0,0)\) in the complex plane.
The process is simple:
The process is simple:
- Square the real part: \(a^2\).
- Square the imaginary part: \(b^2\).
- Add these squares together.
- Take the square root of that sum.
Conjugate of Complex Numbers
The conjugate of a complex number is pivotal in various mathematical operations, especially when simplifying certain expressions. For a complex number \(z = a + bi\), its conjugate is defined as \(\bar{z} = a - bi\).Taking a conjugate involves changing the sign of the imaginary part, turning \(+bi\) into \(-bi\). This is useful because when you multiply a complex number by its conjugate, the result is always a real number. This property is illustrated by the formula \(z \bar{z} = a^2 + b^2\).
Switching the imaginary part from positive to negative does not affect the magnitude but alters the direction in the complex plane, flipping it over the real axis.Examples:
Switching the imaginary part from positive to negative does not affect the magnitude but alters the direction in the complex plane, flipping it over the real axis.Examples:
- For \(z = 3 + 2i\), \(\bar{z} = 3 - 2i\).
- For \(z = 4 - i\), \(\bar{z} = 4 + i\).
- Simplifying division of complex numbers.
- Verifying properties like \(z \bar{z} = |z|^2\).
- Solving complex equations in algebra and calculus.
Verification in Complex Multiplication
Verification in complex multiplication, particularly through the property \(z \bar{z} = |z|^2\), is a powerful tool to confirm the relationships between magnitudes and conjugates.
This property indicates that multiplying a complex number \(z\) by its conjugate \(\bar{z}\) results in a real number, specifically the square of the magnitude of the complex number. The procedure involves expanding the expression:\[z \bar{z} = (a + bi)(a - bi) = a^2 - (bi)^2\]Since \((bi)^2 = -b^2\), then:\[a^2 - (bi)^2 = a^2 + b^2\]Thus, \(z \bar{z} = a^2 + b^2 = |z|^2\), which matches the magnitude squared.
This outcome confirms the identity \(z \bar{z} = |z|^2\), establishing that the product is not just real but precisely reflecting the magnitude squared.Through actual examples:
This property indicates that multiplying a complex number \(z\) by its conjugate \(\bar{z}\) results in a real number, specifically the square of the magnitude of the complex number. The procedure involves expanding the expression:\[z \bar{z} = (a + bi)(a - bi) = a^2 - (bi)^2\]Since \((bi)^2 = -b^2\), then:\[a^2 - (bi)^2 = a^2 + b^2\]Thus, \(z \bar{z} = a^2 + b^2 = |z|^2\), which matches the magnitude squared.
This outcome confirms the identity \(z \bar{z} = |z|^2\), establishing that the product is not just real but precisely reflecting the magnitude squared.Through actual examples:
- For \(z = 3 + 2i\):
- The conjugate is \(3 - 2i\).
- Multiplying: \( (3+2i)(3-2i) = 3^2 + 2^2 = 9 + 4 = 13\).
- Magnitude squared: \(|3+2i|^2 = (\sqrt{13})^2 = 13\).
- For \(z = 4 - i\):
- The conjugate is \(4 + i\).
- Multiplying: \((4-i)(4+i) = 4^2 + 1^2 = 16 + 1 = 17\).
- Magnitude squared: \(|4-i|^2 = (\sqrt{17})^2 = 17\).