Chapter 6: Problem 5
Find the indicated projection. The projection of \([-1,2,0,1]\) on \(\operatorname{sp}([2,-3,1,2])\) in \(\mathbb{R}^{4}\)
Short Answer
Expert verified
The projection vector is \([-\frac{2}{3}, 1, -\frac{1}{3}, -\frac{2}{3}]\).
Step by step solution
01
Understand the Projection Formula
The projection of a vector \( \mathbf{u} \) onto another vector \( \mathbf{v} \) is given by the formula: \[ \text{proj}_{\mathbf{v}} \mathbf{u} = \frac{\mathbf{u} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v} \]where \( \mathbf{u} = [-1, 2, 0, 1] \) and \( \mathbf{v} = [2, -3, 1, 2] \). We need to compute the dot products and the resulting projection.
02
Calculate the Dot Product \( \mathbf{u} \cdot \mathbf{v} \)
Calculate the dot product \( \mathbf{u} \cdot \mathbf{v} \):-1\cdot 2 + 2\cdot(-3) + 0\cdot1 + 1\cdot2 = -2 - 6 + 0 + 2 = -6.
03
Calculate the Dot Product \( \mathbf{v} \cdot \mathbf{v} \)
Calculate the dot product \( \mathbf{v} \cdot \mathbf{v} \):2\cdot2 + (-3)\cdot(-3) + 1\cdot1 + 2\cdot2 = 4 + 9 + 1 + 4 = 18.
04
Compute the Scalar for the Projection
Using the formula \( c = \frac{\mathbf{u} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \), compute the scalar:\[ c = \frac{-6}{18} = -\frac{1}{3} \]
05
Find the Projection Vector
Multiply the scalar by \( \mathbf{v} \) to find the projection:\[ \text{proj}_{\mathbf{v}} \mathbf{u} = -\frac{1}{3}[2, -3, 1, 2] = \left[ -\frac{2}{3}, 1, -\frac{1}{3}, -\frac{2}{3} \right] \]. This is the required projection vector.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dot Product
The dot product is a fundamental operation in linear algebra. It combines two vectors to produce a scalar. The dot product of two vectors, say \( \mathbf{a} = [a_1, a_2, a_3, \ldots] \) and \( \mathbf{b} = [b_1, b_2, b_3, \ldots] \), is calculated as:\[\mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + a_3b_3 + \cdots\]This sum essentially measures how much one vector goes in the direction of another. It's crucial for finding vector projections. To solve the exercise, the dot product \( \mathbf{u} \cdot \mathbf{v} \) was calculated as -6, which helped in determining the direction and magnitude of the projection.
Vector Projection
A vector projection is a way of projecting one vector onto another. This gives us a vector that shows the component of one vector along the direction of another. Visually, imagine a shadow cast by a vector onto another vector. This 'shadow' is the projection.
- We start with two vectors \( \mathbf{u} \) and \( \mathbf{v} \).
- The vector projection is essentially a vector that lies along \( \mathbf{v} \) and shows how much \( \mathbf{u} \) aligns with it.
Projection Formula
The projection formula is essential for finding the vector projection. In mathematical terms, the projection of vector \( \mathbf{u} \) onto vector \( \mathbf{v} \) is given by:\[\text{proj}_{\mathbf{v}} \mathbf{u} = \frac{\mathbf{u} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v}\]To use this formula, we first calculate the dot product \( \mathbf{u} \cdot \mathbf{v} \) and then \( \mathbf{v} \cdot \mathbf{v} \). These give us a scalar that represents the length of the projection vector. In the exercise, after calculating these, we obtained a scalar of \(-\frac{1}{3}\) and multiplied it by \( \mathbf{v} \), resulting in the projection vector \( \left[ -\frac{2}{3}, 1, -\frac{1}{3}, -\frac{2}{3} \right] \). This formula is vital in physics and engineering.
Linear Subspaces
Linear subspaces are a core concept, encompassing all possible linear combinations of a set of vectors in a vector space. If you have a vector space \( \mathbb{R}^n \), a subspace is a smaller space that satisfies certain properties such as closure under addition and scalar multiplication.
- Imagine \( \mathbf{v} = [2, -3, 1, 2] \) as defining a line through the origin in \( \mathbb{R}^4 \).
- The span of \( \mathbf{v} \) (line containing all scalar multiples of \( \mathbf{v} \)) is a linear subspace.