Chapter 6: Problem 31
Let \(A\) and \(C\) be orthogonal \(n \times n\) matrices. Show that \(C^{-1} A C\) is orthogonal.
Short Answer
Expert verified
The matrix \(C^{-1} A C\) is orthogonal, as its transpose times itself equals the identity matrix.
Step by step solution
01
Definition of Orthogonal Matrix
A matrix is orthogonal if its transpose is equal to its inverse, i.e., a matrix \( M \) is orthogonal if \( M^T M = I \), where \( I \) is the identity matrix of the same dimensions. Since both \( A \) and \( C \) are given to be orthogonal, we have \( A^T A = I \) and \( C^T C = I \).
02
Express the Target Matrix
We are asked to prove that \( B = C^{-1} A C \) is orthogonal. Therefore, we need to check whether \( B^T B = I \).
03
Transpose of Target Matrix
Calculate the transpose of \( B \): \( B^T = (C^{-1} A C)^T = C^T A^T (C^{-1})^T \). Utilize the property of transposed matrices \((XYZ)^T = Z^T Y^T X^T\) and \((C^{-1})^T = (C^T)^{-1} = C^{-1}\) for orthogonal matrices.
04
Verify Orthogonality of B
Now multiply \( B^T \) with \( B \) to check if it is equal to the identity matrix:\[B^T B = (C^T A^T C^{-1}) (C^{-1} A C)\]Rearrange the expression:\[= C^T (A^T (C^{-1} C^{-1}) A) C\]Recognizing \( C^{-1} C = I \) (the identity) and the orthogonality \( A^T A = I \), we simplify this as:\[= C^T A^T A C = C^T I C = C^T C = I\]Thus, \( B^T B = I \), confirming the orthogonality of \( B \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Transpose
A matrix transpose is essentially flipping a matrix over its diagonal, which means you switch the matrix's row and column indices. If you have a matrix \( M \), its transpose is denoted as \( M^T \). In simpler terms, the transpose of a matrix involves switching \( M[i,j] \) with \( M[j,i] \). Transposing is straightforward and has several properties that make it very useful, especially when working with orthogonal matrices.
- Transposing twice returns the original matrix: \( (M^T)^T = M \).
- The transpose of a product of two matrices is the product of their transposes in reverse order: \( (AB)^T = B^T A^T \).
- Scalar multiples and addends can be transposed: \( (cA + B)^T = cA^T + B^T \), where \( c \) is a constant.
Matrix Inverse
The inverse of a matrix is an important concept in linear algebra, analogous to finding a reciprocal for a number. For a square matrix \( M \), its inverse, denoted \( M^{-1} \), satisfies the equation \( M M^{-1} = M^{-1} M = I \), where \( I \) is the identity matrix. Not all matrices have an inverse, but when they do, they are called invertible or non-singular.
- For a matrix to be invertible, it must be square (same number of rows and columns) and have a non-zero determinant.
- The inverse is unique if it exists, meaning there's only one inverse for a matrix.
Identity Matrix
The identity matrix, usually denoted by \( I \), is a square matrix with ones on the diagonal and zeros elsewhere. It acts as the neutral element in matrix multiplication, similar to how multiplying a number by one leaves it unchanged. \( I \) satisfies the property that for any square matrix \( A \), the products \( AI \) and \( IA \) return \( A \) itself.
- The size of \( I \) is paramount: it must match the dimensions of the matrix being multiplied for the properties above to hold.
- The identity matrix is crucial in defining the inverse: if \( M M^{-1} = I \), then \( M^{-1} \) is the inverse of \( M \).
Matrix Multiplication
Matrix multiplication involves taking rows from the first matrix and multiplying them by columns from the second matrix. Given two matrices \( A \) and \( B \), with appropriate dimensions for multiplication, the product \( AB \) is calculated by multiplying corresponding entries of the row of \( A \) and the column of \( B \), and summing them up.
- The product \( AB \) is possible only if the number of columns in \( A \) equals the number of rows in \( B \).
- Matrix multiplication is associative and distributive but not commutative: \( AB eq BA \) in general.
- Orthogonal matrices maintain orthogonality under multiplication if both are orthogonal; this flows from their definition that \( M^T M = I \).