Chapter 6: Problem 23
Find a \(2 \times 2\) matrix with determinant I that is not an orthogonal matrix.
Short Answer
Expert verified
A 2x2 matrix with determinant 1 that is not orthogonal is \(\begin{pmatrix} 2 & 1 \\ 0 & \frac{1}{2} \end{pmatrix}\).
Step by step solution
01
Understand Matrix Types
We need to find a matrix with specific properties 1. **Determinant is I**: This means the determinant should be 1 (as "I" usually represents 1 in this context). 2. **Not Orthogonal**: This means the matrix does not satisfy that its transpose equals its inverse, i.e., \(A^T A eq I\), where \(I\) is the identity matrix.
02
Set Up the General Form of a 2x2 Matrix
A typical \(2 \times 2\) matrix \(A\) is represented as:\[A = \begin{pmatrix} a & b \ c & d \end{pmatrix}\]The determinant is calculated as \(ad - bc\). To have \(\det(A) = 1\), we need:\[ad - bc = 1\].
03
Choose Elements of the Matrix
Select values for \(a, b, c,\) and \(d\) such that \(ad - bc = 1\) and not all rows and columns are orthogonal. Let's choose: \[a = 2, \quad b = 1, \quad c = 0, \quad d = \frac{1}{2}\]
04
Verify the Determinant
Calculate the determinant of the chosen matrix:\[\det(A) = (2)(\frac{1}{2}) - (0)(1) = 1 - 0 = 1\]This satisfies the condition \(\det(A) = 1\).
05
Check Orthogonality
To verify that the matrix is not orthogonal, the product \(A^T A\) should not equal the identity. For \(A = \begin{pmatrix} 2 & 1 \ 0 & \frac{1}{2} \end{pmatrix}\),first find \(A^T = \begin{pmatrix} 2 & 0 \ 1 & \frac{1}{2} \end{pmatrix}\).Then calculate \(A^T A:\)\[A^T A = \begin{pmatrix} 2 & 0 \ 1 & \frac{1}{2} \end{pmatrix} \begin{pmatrix} 2 & 1 \ 0 & \frac{1}{2} \end{pmatrix} = \begin{pmatrix} 4 & 2 \ 2 & \frac{5}{4} \end{pmatrix} eq \begin{pmatrix} 1 & 0 \ 0 & 1 \end{pmatrix}\]Thus, \(A\) is not orthogonal.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant
The determinant of a matrix is a special number that can be calculated from its elements. For a simple \(2 \times 2\) matrix \(A\) represented as:
- \( A = \begin{pmatrix} a & b \ c & d \end{pmatrix} \)
- \( \det(A) = ad - bc \)
- If the determinant is zero, the matrix is singular, meaning it does not have an inverse.
- If the determinant is non-zero, then the matrix has an inverse, and its rank is full (equal to the number of rows or columns).
- The determinant also indicates the scaling factor of the linear transformation described by the matrix.
Orthogonal Matrix
An orthogonal matrix is a special kind of square matrix that has some very interesting properties:
- An orthogonal matrix \(A\) satisfies \(A^T A = I\), where \(A^T\) is the transpose of \(A\), and \(I\) is the identity matrix.
- Multiplying by an orthogonal matrix represents a rotation or reflection in space without changing the length of vectors (i.e., it preserves angles and distances).
- The inverse of an orthogonal matrix is its transpose, making calculations straightforward.
Transpose
The transpose of a matrix is obtained by flipping it over its diagonal. For a matrix \( A = \begin{pmatrix} a & b \ c & d \end{pmatrix} \), the transpose, denoted \(A^T\), becomes:
- \( A^T = \begin{pmatrix} a & c \ b & d \end{pmatrix} \)
- It is used in checking the orthogonality of a matrix. If the product of a matrix and its transpose equals the identity matrix, it is orthogonal.
- It plays a crucial role in various mathematical applications, including solving systems of equations and statistical analyses.
- Transpose helps to express and solve problems where changing the configuration or perspective of a dataset is needed.