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In Exercises 2-16, find the characteristic polynomial, the real eigenvalues, and the corresponding eigenvectors of the given matrix. $$ \left[\begin{array}{rr} 7 & 5 \\ -10 & -8 \end{array}\right] $$

Short Answer

Expert verified
Eigenvalues: \( \lambda_1 = \frac{-1 + \sqrt{425}}{-2} \) and \( \lambda_2 = \frac{-1 - \sqrt{425}}{-2} \); Eigenvectors are derived by substituting these values into \( (A-\lambda I)\mathbf{v} = 0 \). Characteristic polynomial: \(-\lambda^2 + \lambda + 106 = 0\).

Step by step solution

01

Write the Characteristic Equation

The characteristic equation is found using the formula \( \text{det}(A - \lambda I) = 0 \), where \( A \) is the matrix and \( \lambda \) is the eigenvalue. Start by forming the matrix \( A - \lambda I \). Here, the identity matrix \( I \) is \( \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \). Thus, \( A - \lambda I = \begin{bmatrix} 7-\lambda & 5 \ -10 & -8-\lambda \end{bmatrix} \).
02

Calculate the Determinant

Calculate the determinant of \( A - \lambda I \) by using the formula: \( \text{det}(A - \lambda I) = (7 - \lambda)(-8 - \lambda) - (-10)(5) \). Simplify the expression to find the characteristic polynomial.
03

Expand and Simplify the Determinant

Expanding the determinant gives: \( (7-\lambda)(-8-\lambda) = 56 + 8\lambda - 7\lambda - \lambda^2 \). Simplifying further gives: \( -\lambda^2 + \lambda + 56 + 50 = -\lambda^2 + \lambda + 106 \). Thus, the characteristic polynomial is \( -\lambda^2 + \lambda + 106 \).
04

Solve for Eigenvalues

Set the characteristic polynomial equal to zero: \( -\lambda^2 + \lambda + 106 = 0 \). Solve this quadratic equation using the quadratic formula \( \lambda = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = -1, b = 1, c = 106 \).
05

Calculate the Discriminant

Calculate the discriminant \( b^2 - 4ac = 1^2 - 4(-1)(106) = 1 + 424 = 425 \). Since the discriminant is positive, there are two real eigenvalues.
06

Find the Eigenvalues

Using the quadratic formula, \( \lambda = \frac{-1 \pm \sqrt{425}}{-2} \). Calculate the two eigenvalues: \( \lambda_1 = \frac{-1 + \sqrt{425}}{-2}, \lambda_2 = \frac{-1 - \sqrt{425}}{-2} \).
07

Determine Eigenvectors

For each eigenvalue, substitute back into the equation \( (A - \lambda I)\mathbf{v} = 0 \). Solve the resulting system for \( \mathbf{v} \) by substituting each eigenvalue into the matrix \( A - \lambda I \) and solving for the eigenvector \( \mathbf{v} \).
08

Eigenvectors Using \( \lambda_1 \)

Substitute \( \lambda_1 = \frac{-1 + \sqrt{425}}{-2} \) into \( A - \lambda I \). Solve the resulting homogeneous equations for each component of the eigenvector \( \mathbf{v} \).
09

Eigenvectors Using \( \lambda_2 \)

Substitute \( \lambda_2 = \frac{-1 - \sqrt{425}}{-2} \) into \( A - \lambda I \). Again, solve the resulting equations for the components of the eigenvector \( \mathbf{v} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eigenvalues
Eigenvalues are fundamental to understanding matrix transformations in linear algebra. They are the scalars that show how a matrix stretches or compresses vectors in a particular direction.
When you have a matrix like \( A \), you find its eigenvalues by solving the characteristic equation \( \text{det}(A - \lambda I) = 0 \). This calculation essentially helps you determine values \( \lambda \) (eigenvalues) for which the matrix has non-trivial solutions for \( \mathbf{v} \) such that \( A\mathbf{v} = \lambda\mathbf{v} \).
In practice, getting these values involves computing a determinant and solving a polynomial equation. Once these eigenvalues are identified, they offer deep insights into the matrix's properties, such as its stability and types of possible transformations.
Eigenvectors
Eigenvectors are vectors associated with eigenvalues that keep their direction after a linear transformation, even if they get scaled. For a given eigenvalue \( \lambda \), you find an eigenvector \( \mathbf{v} \) by solving the equation \( (A - \lambda I)\mathbf{v} = 0 \). This means we are looking for a non-zero vector \( \mathbf{v} \) that does not change direction under the transformation represented by \( A \).
To find the eigenvectors, substitute each eigenvalue back into the matrix equation \( A - \lambda I \). Then, solve the resulting system of equations to find \( \mathbf{v} \).
The eigenvectors, along with their corresponding eigenvalues, provide a complete picture of how a matrix acts on space.
Determinant
The determinant is a special number that can be calculated from a square matrix. It is crucial in finding eigenvalues and their calculation involving the characteristic polynomial.
For a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the determinant is calculated as \( ad - bc \). This simple determinant calculation extends to find the characteristic polynomial of a matrix \( A \) by evaluating \( \text{det}(A - \lambda I) \).
The determinant provides essential insights, such as whether a matrix is invertible (a non-zero determinant indicates the matrix is invertible) and how it scales volume and area in geometrical transformations.
Matrix Theory
Matrix Theory is a powerful branch of mathematics that deals with matrices and their application in diverse fields like computer graphics, statistics, engineering, and more.
It involves studying various matrix properties such as determinants, eigenvalues, and eigenvectors, which are all fundamentally interconnected.
In particular, matrix theory helps in solving systems of linear equations, performing transformations in vector spaces, and understanding complex dynamical systems. Concepts such as the characteristic polynomial or the spectral theorem are core elements of matrix theory.
With a strong grasp of matrix theory, one can effortlessly move through complex topics in linear algebra, understanding multidimensional data shows how powerful these concepts really are.

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Most popular questions from this chapter

Prove that, for every square matrix \(A\) all of whose eigenvalues are real, the product of its eigenvalues is \(\operatorname{det}(A)\).

Let \(T: V \rightarrow V\) be a linear transformation of a vector space \(V\) into itself, and let \(\lambda\) be a scalar. Prove that \(\\{\mathbf{v} \in V \mid T(\mathbf{v})=\lambda \mathbf{v}\\}\) is a subspace of \(V\).

Let \(A\) and \(C\) be \(n \times n\) matrices, and let \(C\) be invertible. Prove that, if \(\mathrm{v}\) is an eigenvector of \(A\) with corresponding eigenvalue \(\lambda\), then \(C^{-1} v\) is an eigenvector of \(C^{-1} A C\) with corresponding eigenvalue \(\lambda\). Then prove that all eigenvectors of \(C^{-1} A C\) are of the form \(C^{-1} \mathbf{v}\), where \(\mathbf{v}\) is an eigenvector of \(\boldsymbol{A}\).

The routine ALLROOTS in LINTEK can be used to find both real and complex roots of a polynomial. The program uses Newton's method, which finds a solution by successive approximations of the polynomial function by a linear one. ALLROOTS is designed so that the user can watch the approximations approach a solution. Of course, a program such as MATLAB, which is designed for research, simply spits out the answers. In Exercises 52-55, either 2\. use the command eig(A) in MATLAB to find all eigenvalues of the matrix or b. first use MATCOMP in LINTEK to find the characteristic equation of the given matrix. Copy down the equation, and then use ALLROOTS to find all eigenvaiues of the matrix. $$ \left[\begin{array}{rrrr} 21 & -8 & 0 & 32 \\ -14 & 17 & -6 & 9 \\ 15 & 11 & -13 & 16 \\ -18 & 30 & 43 & 31 \end{array}\right] $$

Mark each of the following True or False. \- a. Évery \(n \times n\) matrix is diagonalizabie. If an \(n \times n\) matrix has \(n\) distinct real eigenvalues, it is diagonalizable. c. Every \(n \times n\) real symmetric matrix is teal diagonalizable. d. An \(n \times n\) matrix is diagonalizable if and only if it has \(n\) distinct eigenvalues. i. If an \(n \times n\) matrix \(A\) is diagonalizable, there is a unique diagonal matrix \(D\) that is similar to \(A\). If \(A\) and \(B\) are similar square matrices, then \(\operatorname{det}(A)=\operatorname{det}(B)\). \- e. An \(n \times n\) matrix is diagonalizable if and only if the algebraic multiplicity of each of its eigenvalues equals the geometric multiplicity. -f. Every invertible matrix is diagonalizabie. \- g. Every triangular matrix is diagonalizable. h. If \(A\) and \(B\) are similar square matrices and \(A\) is diagonalizable, then \(B\) is also diagonalizable.

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