Chapter 3: Problem 37
Let \(v_{1}, v_{2}, \ldots, v_{n}\) be a list of nonzero vectors in a vector space \(V\) such that no vector in this list is a linear combination of its predecessors. Show that the vectors in the list form an independent set.
Short Answer
Expert verified
The vectors \(v_1, v_2, \ldots, v_n\) are linearly independent.
Step by step solution
01
Understanding the Problem
We need to prove that the set of vectors \(v_1, v_2, \ldots, v_n\) is linearly independent. This means that if there is a linear combination of these vectors that equals the zero vector, all the coefficients must be zero.
02
Set Up the Equation
Suppose there is a linear combination of the vectors that equals the zero vector: \(a_1v_1 + a_2v_2 + \ldots + a_nv_n = 0\). We need to show that all the scalars \(a_1, a_2, \ldots, a_n\) must be zero for this equation to hold.
03
Base Case Analysis
Consider the first vector, \(v_1\). Since no vectors precede \(v_1\), it must already be nonzero to satisfy the non-linear combination condition. Thus, if \(a_1v_1 = 0\) and \(v_1\) is nonzero, \(a_1\) must be zero.
04
Inductive Step Hypothesis
Assume that the first \(k\) vectors, \(v_1, v_2, \ldots, v_k\), are linearly independent, meaning \(a_1 = a_2 = \ldots = a_k = 0\) in any combination that sums to zero. We must show that \(a_{k+1} = 0\) as well for \(v_1, v_2, \ldots, v_{k+1}\) to be independent.
05
Show Linear Independence Extension
Consider the vector \(v_{k+1}\). According to the problem, \(v_{k+1}\) is not a linear combination of \(v_1, v_2, \ldots, v_k\). Therefore, for the entire sum \(a_1v_1 + a_2v_2 + \ldots + a_kv_k + a_{k+1}v_{k+1} = 0\) to hold, \(a_{k+1}\) must be zero because otherwise, \(v_{k+1}\) would be expressed as a linear combination of \(v_1, v_2, \ldots, v_k\), which contradicts our assumption.
06
Conclusion
By induction on the number of vectors, we have shown that all coefficients \(a_1, a_2, \ldots, a_n\) must be zero for the linear combination to equal the zero vector. Thus, the vectors \(v_1, v_2, \ldots, v_n\) are linearly independent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Space
A vector space is a fundamental concept in linear algebra. It is a set of objects, called vectors, that can be added together and multiplied by scalars to produce another vector from the same set.
Here are some important properties that define a vector space:
Here are some important properties that define a vector space:
- Closure under addition: The sum of two vectors is also a vector in the same vector space.
- Closure under scalar multiplication: Multiplying a vector by a scalar results in another vector within the space.
- Contains a zero vector: There exists a zero vector in the space such that adding it to any vector does not change the vector.
- Associative and commutative properties: The addition of vectors is both associative and commutative.
- Existence of additive inverses: For any vector in the space, there exists another vector such that their sum is the zero vector.
Linear Combination
A linear combination is an expression involving a set of vectors and scalars. It is formed by multiplying each vector by a corresponding scalar and then adding the results.
Mathematically, for vectors \(v_1, v_2, \ldots, v_n\) and scalars \(a_1, a_2, \ldots, a_n\), a linear combination looks like: \[ a_1v_1 + a_2v_2 + \ldots + a_nv_n \] The concept of linear combinations is central to understanding vector spaces and linear independence. If a vector can be written as a linear combination of others, it suggests a dependency among them.
Linear combinations help us express complex transformations and solve systems of equations more effectively. They link many vectors and their operations into a cohesive structure.
Mathematically, for vectors \(v_1, v_2, \ldots, v_n\) and scalars \(a_1, a_2, \ldots, a_n\), a linear combination looks like: \[ a_1v_1 + a_2v_2 + \ldots + a_nv_n \] The concept of linear combinations is central to understanding vector spaces and linear independence. If a vector can be written as a linear combination of others, it suggests a dependency among them.
Linear combinations help us express complex transformations and solve systems of equations more effectively. They link many vectors and their operations into a cohesive structure.
Inductive Proof
Inductive proofs are a powerful technique in mathematics, especially useful in showing properties that hold for any natural number.
They work in two clear steps:
They work in two clear steps:
- Base Case: Verify the property for the initial value (usually at \(k=1\) or \(k=0\)). This establishes the foundation.
- Inductive Step: Assume that the property holds for an arbitrary \(k\). Then, using this assumption, prove that it must also hold for \(k+1\).
Basis of a Vector Space
A basis of a vector space is a set of linearly independent vectors that "span" the entire space. This means every vector in the space can be expressed uniquely as a linear combination of the basis vectors.
A common application is reducing systems of equations to simpler forms, making calculations more manageable. It's important to note that while there can be many different bases for a given vector space, all bases will have the same number of vectors, a number crucially linked to the dimension of the space.
- Linearly Independent: The basis vectors must be linearly independent, meaning no vector in the set is a linear combination of the others.
- Spanning the Space: They must span the space, which ensures you can express any vector in the vector space using the basis vectors.
A common application is reducing systems of equations to simpler forms, making calculations more manageable. It's important to note that while there can be many different bases for a given vector space, all bases will have the same number of vectors, a number crucially linked to the dimension of the space.